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Download Sec 4.8 Solving Equations with fractions Add Chapter 4 test # 1
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Sec 4.8 Solving Equations with fractions Add Chapter 4 test # 1-27 p 303 to homework Test Problem: Example 1 Solve − 78 k = 21 Notice term containing k is isolated on the left and number term is on the right To get k multiply both sides of the equation by the reciprocal of − 78 which is − 87 − 87 − 78 k = 21− 87 sign on the left is + 21 8 reduce + 1k = 1 − 7 3 8 k = −11 k = −24 Test Problem: Example 3 Solve y − 15 = 321 32 To isolated the y term on the left add the opposite of − 15 which is + 15 to both sides of the 32 32 equation y − 15 + 15 = 321 + 15 32 32 32 y + 0 = 16 reduce 32 y = 12 Clearing fractions first Example 4 Solve x + 16 = 34 Multiply both sides of the equations by the LCD of any fractions in the equation The LCD of 4 and 6 = 12 12x + 16 = 12 34 multiply by LCD 1 3 12x + 12 6 = 12 4 use distributive property 12 12 3 12x + 6 = 1 ⋅ 4 reduce 12x + 2 = 9 notice there are no fractions in the equation −2 −2 subtract 2 from both sides of the equation —————————12x =7 divide both sides by 12, the coefficient of x x = 127 p289. Strategy Simplify the equations: 1. Clear the equation of fractions 2. Use the distributive property to remove any parentheses 3. Combine like terms on either side of the equation Isolate the variables: 4. Use the addition and subtraction properties of equality to get the variables on one side and the constant terms on the other 5. Combine like terms when necessary 6. Undo the operations of multiplication and division to isolate the variable 1 #58 Solve 14 y − 2 3 = 1 2 LCD of 4,3,2 = 12 12 14 y − 23 = 12 12 multiply both sides by LCD 1 2 1 use the distributive property to simplify 12 4 y − 12 3 = 12 2 2 3y − 4 1 = 6 reduce 3y − 8 = 6 notice there are no fractions in the equation + 8 +8 add 8 to both sides of the equation —————————3y = 14 divide both sides by 3, the coefficient of y 14 2 y = 3 or y = 4 3 Test Problem: Example 5 Solve 34 h − 12 = 58 h Multiply both sides of the equations by the LCD of any fractions in the equation The LCD of 2,4 and 8 = 8 8 34 h − 12 = 8 58 h multiply both sides by LCD 3 1 8 5 8 4 h − 8 2 = 1 8 h use the distributive property to simplify 2 3 4 1 h − 1 1 = 5h reduce 1 1 6h − 4 = 5h notice there are no fractions in the equation − 6h − 6h subtract 6h from both sides of the equation —————————to put the variable on the right − 4 = −1h divide both sides by −1, the coefficient of h 4 = h or h = 4 Do NOW a. y + 15 = 23 b. 45 p − 12 = 34 p c. 25 x + 1 = 13 + x ans. a. 7 15 b. 1 5 c. 10 9 Example 6 and 7 Word problems p 289 and 290 2