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Transcript
To graph this inequality, draw a solid circle at
draw an arrow extending to the left.
and
1-5 Solving Inequalities
Solve each inequality. Then graph the solution
set on a number line.
15. 11. SOLUTION: SOLUTION: To graph this inequality, draw a solid circle at -3 and
draw an arrow extending to the left.
To graph this inequality, draw an open circle at 27
and draw an arrow extending to the left.
13. SOLUTION: 17. SOLUTION: To graph this inequality, draw a solid circle at
draw an arrow extending to the left.
and
To graph this inequality, draw an open circle at 3 and
draw an arrow extending to the left.
15. SOLUTION: 19. SOLUTION: To graph this inequality, draw an open circle at 27
and draw an arrow extending to the left.
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17. SOLUTION: Page 1
To graph this inequality, draw an open circle at 1 and
draw an arrow extending to the left.
To graph this inequality, draw an open circle at 3 and
draw an arrow extending to the left.
To graph this inequality, draw an open circle at 3 and
draw an arrow extending to the left.
1-5 Solving Inequalities
19. SOLUTION: Define a variable and write an inequality for
each problem. Then solve.
23. Twelve less than the product of three and a number
is less than 21.
SOLUTION: Let x be the unknown number.
To graph this inequality, draw an open circle at 1 and
draw an arrow extending to the left.
25. The difference of 5 times a number and 6 is greater
than the number.
SOLUTION: Let x be the unknown number.
21. SOLUTION: 27. HIKING Danielle can hike 3 miles in an hour, but
she has to take a one-hour break for lunch and a
one-hour break for dinner. If Danielle wants to hike
at least 18 miles, solve
to determine
how many hours the hike should take.
SOLUTION: To graph this inequality, draw an open circle at 3 and
draw an arrow extending to the left.
Define a variable and write an inequality for
each problem. Then solve.
23. Twelve less than the product of three and a number
is less
than- 21.
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Manual
Powered by Cognero
SOLUTION: Let x be the unknown number.
Danielle has to hike for at least 8 hours.
Page 2
Solve each inequality. Then graph the solution
set on a number line.
29. and draw an arrow extending to the right.
1-5 Solving Inequalities
27. HIKING Danielle can hike 3 miles in an hour, but
she has to take a one-hour break for lunch and a
one-hour break for dinner. If Danielle wants to hike
at least 18 miles, solve
to determine
how many hours the hike should take.
31. SOLUTION: SOLUTION: To graph this inequality, draw an open circle at 18.75
and draw an arrow extending to the right.
Danielle has to hike for at least 8 hours.
Solve each inequality. Then graph the solution
set on a number line.
33. SOLUTION: 29. SOLUTION: To graph this inequality, draw an open circle at –4.5
and draw an arrow extending to the right.
To graph this inequality, draw an open circle at
and draw an arrow extending to the right.
35. SOLUTION: 31. SOLUTION: eSolutions
Manualthis
- Powered
by Cognero
To graph
inequality,
draw
an open circle at 18.75
and draw an arrow extending to the right.
Page 3
To graph this inequality, draw an open circle at –4.5
and draw an arrow extending to the right.
To graph this inequality, draw an open circle at
and draw an arrow extending to the right.
1-5 Solving Inequalities
Solve each equation. Check your solutions.
35. 55. SOLUTION: SOLUTION: To graph this inequality, draw an open circle at
and draw an arrow extending to the right.
There appear to be two solutions,
.
Check: Substitute the values in the original equation.
Solve each equation. Check your solutions.
55. SOLUTION: The solution set is
57. ASTRONOMY Pluto travels in a path that is not
circular. Pluto’s farthest distance from the Sun is
4539 million miles, and its closest distance is 2756
million miles. Write an equation that can be solved to
find the minimum and maximum distances from the
Sun to Pluto.
There appear to be two solutions,
.
.
SOLUTION: Check: Substitute the values in the original equation.
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Page 4
The solution
set is
1-5 Solving
Inequalities
Substitute r = 891.5 and c = 3647.5 in the equation
.
.
57. ASTRONOMY Pluto travels in a path that is not
circular. Pluto’s farthest distance from the Sun is
4539 million miles, and its closest distance is 2756
million miles. Write an equation that can be solved to
find the minimum and maximum distances from the
Sun to Pluto.
SOLUTION: 59. GEOMETRY The formula for the surface area of a
cylinder is
.
a. Use the Distributive Property to rewrite the
formula by factoring out the greatest common factor
of the two terms.
b. Find the surface area for a cylinder with radius 3
centimeters and height 10 centimeters using both
formulas. Leave the answer in terms of .
c. Which formula do you prefer? Explain your
reasoning.
SOLUTION: a.
The value of c is 4539 – 891.5 or 3647.5.
Substitute r = 891.5 and c = 3647.5 in the equation
.
The GCF of the two terms is 2πr.
59. GEOMETRY The formula for the surface area of a
cylinder is
.
a. Use the Distributive Property to rewrite the
formula by factoring out the greatest common factor
of the two terms.
b. Find the surface area for a cylinder with radius 3
centimeters and height 10 centimeters using both
formulas. Leave the answer in terms of .
c. Which formula do you prefer? Explain your
reasoning.
b. Substitute r = 3 and h = 10 in the formula
.
SOLUTION: a.
Substitute r = 3 and h = 10 in the formula The GCF of the two terms is 2πr.
Therefore, the surface area of the cylinder is 78π
2
cm .
b. Substitute r = 3 and h = 10 in the formula
.
c. Sample answer: The formula in part b is quicker.
Solve each equation. Check your solutions.
61. SOLUTION: eSolutions Manual - Powered by Cognero
Substitute r = 3 and h = 10 in the formula The solution set is
.
Page 5
Therefore, the surface area of the cylinder is 78π
2
cm .
1-5 Solving
Inequalities
c. Sample answer: The formula in part b is quicker.
Solve each equation. Check your solutions.
The solution set is
.
65. 61. SOLUTION: SOLUTION: The solution set is
.
63. SOLUTION: There appear to be two solutions, –6 and 2.
Check: Substitute the values in the original equation.
There appear to be two solutions,
.
Check: Substitute the values in the original equation.
The solution set is
.
The solution set is
.
65. SOLUTION: eSolutions Manual - Powered by Cognero
Page 6