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Solving equations When solving an equation we should keep algebra in every step of our method. When we 'undo' we do the inverse (opposite) e.g. 'Add' becomes 'Subtract'. On the RHS always start with what was already there. Removing only one step at a time means everything else remains the same and in the same place. A. SOLVING THREE TERM EQUATIONS a. 3x + 2 = 17 b. 12 + 4x = 32 3x = 15 x = 4x = 20 15 3 -2x = -8 x = 4 x =5 5x – 6 = 15 21 = 7x 21 21 5 7 x = 4.2 =x 3 =x −8 −2 x =4 20 = 7x - 1 e. 5x = 21 x = 20 – 2x = 12 Don’t lose the sign 20 x = x =5 d. c. f. 7x - 1 = 20 7x = 21 Completely swap sides to bring x onto the LHS x = 21 7 x =3 B. Solving equations with brackets a. 3(2x – 1) = 27 b. 6x - 3 = 27 Expand the brackets 2(4x + 9) = 6 8x + 18 = 6 6x = 30 x = 8x = -12 30 x = 6 x =5 −12 Expand the brackets 2(4x + 9) = 6 Divide by the coefficient 4x + 9 = 2 4x + 9 = 3 4x = -6 8 x = -1.5 6 x = Choose the method you find easiest −6 4 =1.5 C. Solving equations with fractions Only part of LHS is divided by 3. Either lose the ‘odd bit’ first or multiply every term by 3 Be careful. Look carefully to see what is being divided All LHS is divided by 2 so multiply RHS by 2 a. (2) 3x + 4 (2) 2 = 11 3x + 4 = 22 3x = 18 x = b. 5x 3 -1 =9 5x (3) (3) 5x(3) 3 -1 =9 = 10 5x - 3 = 27 5x = 30 5x = 30 3 18 x = 3 x =6 30 5 x =6 x = 30 5 x =6 Choose the method you find easiest © www.teachitmaths.co.uk 2017 28328 Page 1 of 3 Solving equations D. Solving equations with unkowns on both sides Collect all the letters onto one side and the numbers onto the other. a. 6x - 7 = 2x + 5 b. 4x - 7 = 5 7x - 14 = 5x - 4 5x + 4 = 20 – 3x 2x - 14 = -4 8x + 4 = 20 2x = 10 8x = 16 4x = 12 x = c. 12 x = 4 x =3 10 x = 2 x =5 16 2 x =2 You sometimes have various options to solve an equation d. 4x + 5 = 7x - 4 -3x + 5 = -4 -3x = -9 x = −9 −3 4x + 5 = 7x - 4 Completely swap sides to put the largest x term on the LHS 4x + 5 = 7x - 4 7x - 4 = 4x + 5 3x - 4 = 5 3x = 9 x =3 x = 5 = 3x - 4 Taking the letters to the RHS 9 = 3x 9 3 9 =x 3 =x 3 x =3 e. 23 – 2x = 6x - 5 6x – 5 = 23 -2x 23 – 8x = -5 8x - 5 = 23 -8x = -28 x = 23 – 2x = 6x - 5 23 = 8x - 5 8x = 28 −28 x = −8 x = 3.5 28 = 8x 28 28 8 8 x = 3.5 =x 3.5 = x Choose the method you find easiest f. 2(3x – 8) = 5(2x – 2) 6x - 16 = 10x - 10 10x - 10 = 6x – 16 4x – 10 = -16 4x = -6 x = −6 4 x = -1.5 © www.teachitmaths.co.uk 2017 Expand the brackets Swap sides g) 2(4x + 25) = 4(5 – x) 8x + 50 = 20 – 4x 12x + 50 = 20 Don’t skimp on method Work slowly Work carefully Work accurately Just follow the rules and it will work! 28328 12x = -30 x = −30 12 6 x = -2 12 x = -2.5 Page 2 of 3 Solving equations E. Solving harder equations with fractions To solve equations with fractions it is likely that we will need to find a common denominator and cross multiply. 4y + 8 5 a. c. = 5(3y - 5) 4x x − 3 2 2(4x) − 3(x) 6 8x − 3x 6 5x 6 5x = 10 = 10 = 10 = 10 = 60 4y + 8 = 4y + 8 = 15y - 25 -11y + 8 = -25 -11y = -33 y = −33 −11 x = 60 5 y = 3 x = 12 = 10 = 4x − 3 2x + 1 + 5 3 3(4x − 3) + 5(2x + 1) 15 12x − 9 + 10x + 5 15 22x − 4 15 15 is the common 22x - 4 denominator b. 3y - 5 6 is the common denominator 3x + 8 5 = x + 12 4 10 4(3x + 8 ) = 5(x + 12) = 10 12x + 32 = 5x + 60 = 10 7x + 32 = 60 = 150 7x = 28 22x = 154 x = x = 154 22 28 7 x = 4 x = 7 © www.teachitmaths.co.uk 2017 d. 28328 Page 3 of 3