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Worksheet: SOLVING QUADRATIC EQUATIONS Math 90 We have learned several different methods for solving quadratic equations. Below are examples of two different methods that may come in handy. Example #1: Solve by FACTORING. x 2 + 6 = −7 x x2 + 7x + 6 = 0 Add 7x to both sides to get all terms to one side of equation = 0. Factor. Since 1 ⋅ 6 = 6 and 1 + 6 = 7, we can factor the left hand side. (x + 1)(x + 6) = 0 Set each factor = 0. x + 1 = 0 or x + 6 = 0 Solve for x. x = −1 or x = −6 Example 2: Solve using the QUADRATIC FORMULA. Given ax 2 + bx + c = 0 , the quadratic formula can give you the solution(s) for x. x = − b ± b 2 − 4ac 2a x 2 − 2 x = 10 Add 7 to both sides to get all terms to one side of equation = 0. x 2 − 2 x − 10 = 0 Determine a, b and c. a = 1, b = –2, c = –10. Use quadratic formula. x= x= − (− 2) ± (− 2)2 − 4(1)(− 10 ) = 2(1) 4 ± 4 − (− 40 ) 4 ± 4 + 40 4 ± 44 = = 2 2 2 Simplify your answer. 4 ± 44 4 ± 2 ⋅ 2 ⋅ 11 4 ± 2 11 4 2 11 = = = ± = 2 ± 11 So the solutions are x = 2 ± 11 . 2 2 2 2 2 THE MORAL OF THE STORY: Try the factoring method first. If all else fails… use the Quadratic Formula. SOLVE for x. 1. x 2 − 3 x = 4 6. 3x 2 − 7 x + 2 = 0 2. x 2 = 10 x − 25 7. x 2 − 3x + 1 = 6 3. x 2 − 5 = 3 8. 4 x 2 + 7 x + 2 = 0 4. (x + 4)2 =8 5. x 2 − 6 x + 8 = 0 9. 8 x 2 = 200 10. 4 x 2 − 6 x − 1 = 0 Algebra Review Solving Quadratics ____________________ Name PROBLEM SOLVING I. Solve by Factoring 1.) x2 – 64 = 0 2.) x2 – 6x – 16 = 0 3.) x2 + 3x = 40 4.) 2 x 2 + 3x + 1 = 0 5.) 6.) III. Solve by using the quadratic formula: The quadratic formula is: x= 7. 4x² – 8x = 1 9. x² + 3x + 2 = 0 8. x² – 100 = 0 Solve each equation any way you want. Show your work. 10. x2 + 11x + 18 = 0 11. x2 + 2x + 1 = 15 13. (x + 2)² = 36 16. x² = 36 14. 17. x² – 10x + 25 = 0 x² – 6x + 2 = 0 x² + 6x = 0 x² + 8x = 0 12. 7x2 – 9x +1 = 0 15. 18. x² – 5x + 4 = 0 x² + 3x + 7 = 0 REASONING: 20.) Explain why x² = -81 DOES NOT have a solution. Explain why: 24.) What are the two mistakes in setting up the quadratic formula: Solve: 2x² – x – 6 = 0 − 1 ± (−1) 2 − 4(2)(6) x= 2(2)