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9.1 Inverse and Joint Variation Goals p Write and use inverse variation models. p Write and use joint variation models. Your Notes VOCABULARY Inverse variation Two variables x and y show inverse k variation provided y where k is a nonzero x constant. Constant of variation The nonzero constant in a direct variation equation, inverse variation equation, or joint variation equation Joint variation A relationship that occurs when a quantity varies directly as the product of two or more other quantities Example 1 Classifying Direct and Inverse Variation Tell whether x and y show direct variation, inverse variation, or neither. Given Equation Rewritten Equation a. y x 2 Type of Variation Neither b. 2 yx 2 y x Inverse y c. x 7 y 7x Direct Checkpoint Tell whether x and y show direct variation, inverse variation, or neither. 1. yx 1 inverse variation 204 Algebra 2 Notetaking Guide • Chapter 9 y 2. x 1.3 direct variation 3. y x 1 neither M2ng_nt.09 9/28/04 11:50 AM Page 205 Your Notes Writing an Inverse Variation Equation Example 2 The variables x and y vary inversely, and y 2 when x 3. a. Write an equation that relates x and y. b. Find y when x 2. Solution a. k y x k 2 3 6 k Write general equation for inverse variation. Substitute for y and for x. Solve for k. 6 The inverse variation equation is y . x b. When x 2, the value of y is: 6 y 3 2 Checking Data for Inverse Variation Example 3 Tell whether the following data show inverse variation. If they do, find a model for the relationship between a and b. a 5 10 15 20 25 b 21 10.5 7 5.25 4.2 Solution Each product ab is equal to 105 . For instance, (5)(21) 105 and (20)(5.25) 105 . So, the data do show inverse variation. A model for the 105 relationship is b . a Lesson 9.1 • Algebra 2 Notetaking Guide 205 M2ng_nt.09 9/28/04 11:50 AM Page 206 Your Notes Comparing Different Types of Variation Example 4 Write an equation for the given relationship. Relationship Equation a. v varies directly with u. v ku b. v varies inversely with u. k v u c. w varies jointly with t, u, and v. w ktuv d. v varies inversely with the cube of u. k v u3 e. w varies directly with u and inversely with v. ku w v Checkpoint Complete the following exercises. 4. The variables x and y vary inversely, and y 3.5 when x 4. Find an equation that relates x and y. Find y when x 6. 14 7 y ; x 3 5. Do the data below show inverse variation? If so, find a model for the relationship between x and y. x 2 4 6 8 10 y 12 6 4 3 2.4 24 yes; y x Homework 6. Write an equation for the given relationship: y varies jointly with x and z and varies inversely with the square of v. kxz y v2 206 Algebra 2 Notetaking Guide • Chapter 9 9.2 Graphing Simple Rational Functions Goals p Graph simple rational functions. p Use the graph of a rational function to solve real-life problems. Your Notes VOCABULARY p(x) Rational function A function of the form f(x) q(x) where p(x) and q(x) are polynomials and q(x) 0 Hyperbola The set of all points P such that the difference of the distances from P to two fixed points, called the foci, is constant Branches of a hyperbola Two symmetrical parts of a hyperbola Example 1 Graphing a Rational Function 3 Graph y 1. State the domain and range. x2 Solution Draw the asymptotes x 2 and y 1 . y 5 (3, 4) Plot two points to the left of the vertical asymptote, such as (1, 0 ) and (1, 2 ), and two points to the right, such as (3, 4 ) and (5, 2 ). Use the asymptotes and plotted 3 (5, 2) (1, 0) 1 1 1 1 3 5 x (1, 2) points to draw the branches of the hyperbola. The domain is all real numbers except 2 , and the range is all real numbers except 1 . Lesson 9.2 • Algebra 2 Notetaking Guide 207 Your Notes Example 2 Graphing a Rational Function 4x 2 Graph y . State the domain and range. 2x 2 Solution Draw the asymptotes. Solve 2x 2 0 for x to find the vertical asymptote x 1 . The horizontal asymptote is a 4 y 2 . c 2 y Plot two points to the left of the vertical asymptote, such as (4, 3 ) and (2, 5 ), and two points to the right, such as (0, 1 ) and (2, 1 ). Use the asymptotes and plotted (2, 5) 5 (4, 3) 3 1 5 3 1 1 points to draw the branches of the hyperbola. (2, 1) 1 3 x (0, 1) The domain is all real numbers except 1 , and the range is all real numbers except 2 . Checkpoint Complete the following exercise. 2 1. Graph y 1. x2 State the domain and range. y 3 (3, 1) (4, 0) 5 3 1 1 1 3 (1, 3) domain: all real numbers except 2; range: all real numbers except 1 208 Algebra 2 Notetaking Guide • Chapter 9 5 1 (0, 2) x Your Notes Example 3 Writing a Rational Model You are arranging a dinner at a local restaurant. The cost to rent a dining room is $300. In addition to this one-time charge, the unit cost of each plate is $40. a. Write a model that gives the average cost per person as a function of the number of people attending. b. Graph the model and use it to estimate how many people must attend to drop the average cost to $45 per person. c. Describe what happens to the average cost as the number of people attending increases. Solution a. The average cost is the total cost of the dinner divided by the number of people attending. One-time Unit p Number charges cost attending Verbal Model Average cost Labels Average cost A (dollars) One-time charges 300 (dollars) Unit cost 40 (dollars) Number attending x (people) Number attending Homework b. The A-axis is the vertical asymptote and the line A 40 is the horizontal asymptote. The domain is x > 0 and the range is A > 40 . When A 45, the value of x is 60 . So, you need at least 60 people to attend for the average cost to drop to $45 per person. Average cost (dollars) 300 40x Algebraic A x Model A 70 60 50 A 300 40x x (60, 45) 40 30 20 10 0 0 10 20 30 40 50 60 70 80 x Number attending c. As the number of people attending increases, the average cost per person gets closer and closer to $40 . Lesson 9.2 • Algebra 2 Notetaking Guide 209 9.3 Graphing General Rational Functions Goals p Graph general rational functions. p Use the graph of a rational function to solve real-life problems Your Notes GRAPHS OF RATIONAL FUNCTIONS Let p(x) and q(x) be polynomials with no common factors other than 1. The graph of the rational function am x m ⫹ am ⫺ 1x m ⫺ 1 ⫹ . . . ⫹ a1x ⫹ a0 p(x) f(x) ⫽ ᎏᎏ ⫽ ᎏᎏᎏᎏᎏ bn x n ⫹ bn ⫺ 1x n ⫺ 1 ⫹ . . . ⫹ b1x ⫹ b0 q(x) has the following characteristics. 1. The x-intercepts of the graph of f are the real zeros of p(x) . 2. The graph of f has a vertical asymptote at each real zero of q(x) . 3. The graph of f has at most one horizontal asymptote. • If m < n, the line y ⫽ 0 is a horizontal asymptote. a • If m ⫽ n, the line y ⫽ ᎏm ᎏ is a horizontal asymptote. bn • If m > n, the graph has no horizontal asymptote . The graph’s end behavior is the same as the graph of a m⫺n y ⫽ ᎏm ᎏx . bn 210 Algebra 2 Notetaking Guide • Chapter 9 M2ng_nt.09 9/28/04 11:50 AM Page 211 Your Notes Example 1 Graphing a Rational Function (m < n) 12 Graph y . State the domain and range. x4 4 Solution The numerator has no zeros, so there is no x-intercept . The denominator has no real zeros, so there is no vertical asymptote . The degree of the numerator ( 0 ) is less than the degree of the denominator ( 4 ), so the line y 0 is a horizontal asymptote. y The graph passes through the points (2, 0.6 ), (1, 2.4 ), (0, 3 ), (1, 2.4 ), and (2, 0.6 ). The domain is all real numbers , and the range is 3 ≤ y < 0 . 3 1 3 1 1 1 3 x 3 5 Checkpoint Complete the following exercise. 10 . 1. Graph y 3 x 8 State the domain and range. y 3 1 3 1 1 1 3 x domain: all real numbers except 2; range: all real numbers except 0 Lesson 9.3 • Algebra 2 Notetaking Guide 211 Your Notes Example 2 Graphing a Rational Function (m ⴝ n) x2 ⴚ 4 Graph y ⴝ ᎏ ᎏ. x2 ⴚ 1 The numerator can be factored as (x ⫹ 2)(x ⫺ 2) , so the x-intercepts of the graph are ⫺2 and 2 . The denominator can be factored as (x ⫹ 1)(x ⫺ 1) , so the denominator has zeros ⫺1 and 1 . This implies that the lines x ⫽ ⫺1 and x ⫽ 1 are vertical asymptotes of the graph. The degree of the numerator ( 2 ) is equal to the degree of the denominator a ( 2 ), so the horizontal asymptote is y ⫽ ᎏm ᎏ ⫽ 1 . To draw bn the graph, plot points between and beyond the vertical asymptotes. To the left of x ⴝ ⴚ1 Between x ⴝ ⴚ1 and x ⴝ 1 To the right of x ⴝ 1 y x y ⫺4 0.8 5 ⫺2 0 3 ⫺0.5 5 1 0 4 0.5 5 2 0 4 0.8 ⫺3 ⫺1 ⫺1 1 3 Checkpoint Complete the following exercise. ⫺x 3 ᎏ. 2. Graph y ⫽ ᎏ x3 ⫺ 1 y 3 1 ⫺3 ⫺1 ⫺1 ⫺3 ⫺5 212 Algebra 2 Notetaking Guide • Chapter 9 1 3 x x Your Notes Example 3 Graphing a Rational Function (m > n) x2 ⴚ 5x ⴙ 4 Graph y ⴝ ᎏᎏ. xⴚ5 The numerator can be factored as (x ⫺ 4)(x ⫺ 1) , so the x-intercepts of the graph are 4 and 1 . The only zero of the denominator is 5 , so the only vertical asymptote is x ⫽ 5 . The degree of the numerator ( 2 ) is greater than the degree of the denominator ( 1 ), so there is no horizontal asymptote and the end behavior of the graph of f is the same as the end behavior of the graph of y ⫽ x 2 ⫺ 1 ⫽ x . To draw the graph, plot points to the left and right of the vertical asymptote. To the left of x ⴝ 5 To the right of x ⴝ 5 x y 0 ⫺0.8 1 0 3 1 4 0 6 10 7 9 9 10 y 14 10 6 2 ⫺2 ⫺2 2 6 10 14 x Checkpoint Complete the following exercise. x2 ⫺ x ⫺ 5 3. Graph y ⫽ ᎏᎏ. x⫺2 y 5 3 Homework 1 ⫺3 ⫺1 ⫺1 1 3 5 x ⫺3 Lesson 9.3 • Algebra 2 Notetaking Guide 213 9.4 Multiplying and Dividing Rational Expressions Goals p Multiply and divide rational expressions. p Model real-life quantities using rational expressions. Your Notes VOCABULARY Simplified form of a rational expression A rational expression in which the numerator and denominator have no common factors (other than 1) SIMPLIFYING RATIONAL EXPRESSIONS Let a, b, and c be nonzero real numbers or variable expressions. Then the following property applies: ac a Divide out common factor c. bc b Example 1 Simplifying a Rational Expression x2 ⴚ 2x ⴚ 3 Simplify: x2 ⴚ 9 x2 2x 3 (x 3)(x 1) x2 9 (x 3)(x 3) x1 x3 Factor numerator and denominator. Divide out common factor x 3 and write simplified form. Checkpoint Complete the following exercise. x2 2x 15 1. Simplify: x2 6x 5 x3 x1 214 Algebra 2 Notetaking Guide • Chapter 9 Your Notes Example 2 Multiplying Rational Expressions 3x2 6x x4 Multiply: p 2 2 x 4x x 9x 14 Solution 3x2 6x x4 p 2 2 x 4x x 9x 14 3x(x 2) x4 p x(x 4) (x 2)(x 7) Factor numerators and denominators. 3x(x 2)(x 4) x(x 4)(x 2)(x 7) Multiply numerators and denominators. 3 x7 Example 3 Divide out common factors and write simplified form. Multiplying by a Polynomial 2x Multiply: p (x2 x 1) 3 x 1 Solution 2x p (x2 x 1) 3 x 1 2x x2 x 1 p x3 1 1 Write polynomial as rational expression. 2x(x2 x 1) (x 1)(x2 x 1) Factor and multiply. 2x x1 Divide out common factor and write simplified form. Lesson 9.4 • Algebra 2 Notetaking Guide 215 Your Notes Checkpoint Multiply the rational expressions. x3 4x2y3 p 2. xy2 x2 x 12 4xy x4 Example 4 x 3. p (x2 2x 4) 3 x 8 x x2 Dividing Rational Expressions x2 4x 3 x1 Divide: 2 4x 12x 3 Solution x2 4x 3 x1 2 4x 12x 3 x2 4x 3 3 p 2 4x 12x x1 Multiply by reciprocal. (x 3)(x 1) 3 p 4x(x 3) x1 Factor. 3 4x Divide out common factors and write simplified form. Checkpoint Divide the rational expressions. 20x2 x 1 4x 1 4. 3 7x x x x3 4x 5. (x4 16) 2 Homework 5x 1 7x2 1 216 Algebra 2 Notetaking Guide • Chapter 9 x 2 2(x 4) 9.5 Addition, Subtraction, and Complex Fractions Goals p Add and subtract rational expressions. p Simplify complex fractions. Your Notes VOCABULARY Complex fraction A fraction that contains a fraction in its numerator or denominator Example 1 Subtracting with Like Denominators 7 11 4 11 4 1 7x 7x x 7x 7x Example 2 Subtract numerators and simplify. Adding with Unlike Denominators xⴙ2 x Add: ⴙ 2 4x 3x ⴙ 9x First find the least common denominator. Factor the denominators: 4x 4 p x 3x2 9x 3 p x p (x 3) The LCD is 12x(x 3) . Use this to rewrite each expression. x x2 x x2 2 4x 4x 3x 9x 3x(x 3) (x 2) [3(x 3)] 4x [3(x 3)] x (4) 3x(x 3)(4) 3x 2 15x 18 4x 12x(x 3) 12x(x 3) 3x 2 19x 18 12x(x 3) Lesson 9.5 • Algebra 2 Notetaking Guide 217 Your Notes Example 3 Subtracting with Unlike Denominators 2x x2 Subtract: 2 2 x 1 x 2x 1 Solution 2x x2 2 2 x 1 x 2x 1 2x (x 1)(x 1) x2 (x 1)2 (x 2)(x 1) 2x(x 1) 2 (x 1)(x 1)(x 1) (x 1) (x 1) 2x2 2x (x2 x 2) x2 x 2 2 2 (x 1) (x 1) (x 1) (x 1) Checkpoint Perform the indicated operation. 2 4 1. 3x 3x 2 x 3 x 3. x2 16 x2 8x 16 x2 x 12 2 (x 4) (x 4) 218 Algebra 2 Notetaking Guide • Chapter 9 1 4 2. x5 x5 3 x5 1 5x 4. 4x2 2x3 8x2 9x 4 4x2(x 4) Your Notes Example 4 Simplifying a Complex Fraction 3 x1 Simplify: 1 3 x1 x Solution 3 3 x1 x1 1 3 2x 1 x x1 x(x 1) Add fractions in denominator. x (x 1) 3 p (2x 1) x1 Multiply by reciprocal. 3x 2x 1 Divide out common factor and write in simplified form. Checkpoint Complete the following exercise. x2 3x 1 5. Simplify: 1 2 x 3x 1 Homework x(x 2) x1 Lesson 9.5 • Algebra 2 Notetaking Guide 219 9.6 Solving Rational Equations Goals p Solve rational equations. p Use rational equations to solve real-life problems. Your Notes VOCABULARY Cross multiplying A method of solving a simple rational equation for which each side of the equation is a single rational expression. Equal products are formed by multiplying the numerator of each expression by the denominator of the other. Example 1 An Equation with One Solution 4 7 1 Solve: ⴚ ⴝ 3 x 6 4 7 1 3 x 6 冢 冣 Write original equation. 冢 冣 4 7 1 6x 6x 3 x 6 8x 42 x Multiply each side by LCD ⴝ 6x . Simplify. 8x x 42 Add 42 to each side. 7x 42 Subtract x from each side. x6 Divide each side by 7 . The solution is 6 . Check this in the original equation. Checkpoint Complete the following exercise. 7 5 1 1. Solve: 2x 3 12 2 220 Algebra 2 Notetaking Guide • Chapter 9 Your Notes Example 2 An Equation with an Extraneous Solution xⴙ6 5x ⴙ 12 Solve: ⴝ 2 ⴚ xⴙ3 xⴙ3 The least common denominator is x 3 . x6 5x 12 2 x3 x3 x6 5x 12 (x 3) p (x 3) p 2 (x 3) p x3 x3 x 6 2(x 3) (5x 12) x 6 2x 6 5x 12 4x 12 x 3 The solution appears to be 3 . After checking it in the original equation, however, you can conclude that 3 is an extraneous solution because it leads to division by zero . So, the original equation has no solution . Example 3 An Equation with Two Solutions 3x ⴚ 1 12 Solve: ⴝ 2 ⴙ xⴚ2 (x ⴚ 2)(x ⴚ 1) The LCD is (x 2)(x 1) . 3x 1 12 2 x2 (x 2)(x 1) (x 1)(3x 1) 2(x 2)(x 1) 12 3x2 4x 1 2x2 6x 16 x2 2x 15 0 (x 5)(x 3) 0 x5 0 x 5 or x3 0 or x 3 The solutions are 5 and 3 . Lesson 9.6 • Algebra 2 Notetaking Guide 221 Your Notes Checkpoint Solve the equation. 3x 2 x6 2. 3 x4 x4 2(x 3) 5 3. 1 2 x2 x 4 3, 1 no solution Example 4 Solving an Equation by Cross Multiplying 3x 2 4 Solve: 2 x 3x x4 Solution 3x 2 4 2 x 3x x4 (3x 2) (x 4) 4 (x2 3x) 3x2 14x 8 4x2 12x Write original equation. Cross multiply. Simplify. 0 x2 2x 8 Write in standard form. 0 (x 4)(x 2) Factor. x 4 or x 2 Zero product property The solutions are 4 and 2 . Check these in the original equation. Checkpoint Complete the following exercise. Homework 2x 8 x4 4. Solve: x2 x1 4 222 Algebra 2 Notetaking Guide • Chapter 9