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Problem 7.15 The function υ (t) is the sum of two sinusoids, υ (t) = 4 cos(ω t + 30◦ ) + 6 cos(ω t + 60◦ ) V. (1) (a) Apply the necessary trigonometric identities from Table 7-1 to show that υ (t) = 9.67 cos(ω t + 48.1◦ ) V. (2) (b) Transform the expression given by Eq. (1) to the phasor domain, simplify it into a single term, and then transform it back to the time domain to show that the result is identical with the expression given by Eq. (2). Solution: (a) υ (t) = 4 cos(ω t + 30◦ ) + 6 cos(ω t + 60◦ ) = 4[cos ω t cos 30◦ − sin ω t sin 30◦ ] + 6[cos ω t cos 60◦ − sin ω t sin 60◦ ] = 6.46 cos ω t − 7.20 sin ω t. If υ (t) = A cos(ω t + θ ) = A[cos ω t cos θ − sin ω t sin θ ], then A cos θ = 6.46, A sin θ = 7.20, from which we deduce that p 6.462 + 7.22 = 9.67, 7.2 −1 θ = tan = 48.1◦ . 6.46 A= Hence, υ (t) = 9.67 cos(ω t + 48.1◦ ) (V). (b) ◦ V = 4e j30 + 6e j60 ◦ = 4 cos 30◦ + j4 sin 30◦ + 6 cos 60◦ + j6 sin 60◦ = 6.46 + j7.196 = 9.67e j48.1 ◦ (V) υ (t) = 9.67 cos(ω t + 48.1◦ ) (V). c All rights reserved. Do not reproduce or distribute. 2013 National Technology and Science Press