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171S3.2q Quadratic Equations, Functions, Zeros, and Models February 21, 2013 MAT 171 Precalculus Algebra Dr. Claude Moore Cape Fear Community College CHAPTER 3: Quadratic Functions and Equations; Inequalities 3.1 The Complex Numbers 3.2 Quadratic Equations, Functions, Zeros, and Models 3.3 Analyzing Graphs of Quadratic Functions 3.4 Solving Rational Equations and Radical Equations 3.5 Solving Equations and Inequalities with Absolute Value Solve Quadratic Equation by using this Excel program. http://cfcc.edu/faculty/cmoore/quadratic_formula.xls This program graphs a quadratic function and shows the roots (solutions). http://cfcc.edu/mathlab/geogebra/quadratic_roots.html This program graphs quadratic functions and shows two forms of equation. http://cfcc.edu/mathlab/geogebra/quadratic2ss.html Sep 273:17 PM 3.2 Quadratic Equations, Functions, Zeros, and Models • Find zeros of quadratic functions and solve quadratic equations by using the principle of zero products, by using the principle of square roots, by completing the square, and by using the quadratic formula. • Solve equations that are reducible to quadratic. • Solve applied problems using quadratic equations. Graphing Quadratic Function with TI Calculator Feb 1910:15 AM Quadratic Equations A quadratic equation is an equation that can be written in the form ax2 + bx + c = 0, a ≠ 0, where a, b, and c are real numbers. A quadratic equation written in this form is said to be in standard form. A quadratic function f is a function that can be written in the form f (x) = ax2 + bx + c, a ≠ 0, where a, b, and c are real numbers. Finding Zeros of Quadratic Function by Graphing with TI Calculator The zeros of a quadratic function f (x) = ax2 + bx + c are the solutions of the associated quadratic equation ax2 + bx + c = 0. Quadratic functions can have realnumber or imaginary number zeros and quadratic equations can have realnumber or imaginarynumber solutions. EquationSolving Principles The Principle of Zero Products: If ab = 0 is true, then a = 0 or b = 0, and if a = 0 or b = 0, then ab = 0. Sep 273:17 PM Sep 273:17 PM Example EquationSolving Principles Solve 2x2 x = 3. Solution The Principle of Square Roots: If x2 = k, then Completing the Square To solve a quadratic equation by completing the square: Example Checking the Solutions Check: x = – 1 TRUE • Isolate the terms with variables on one side of the equation and arrange them in descending order. • Divide by the coefficient of the squared term if that coefficient is not 1. • Complete the square by taking half the coefficient of the first degree term and adding its square on both sides of the equation. • Express one side of the equation as the square of a binomial. • Use the principle of square roots. • Solve for the variable. TRUE Sep 273:17 PM Sep 273:17 PM 1 171S3.2q Quadratic Equations, Functions, Zeros, and Models February 21, 2013 Quadratic Formula The solutions of ax2 + bx + c = 0, a ≠ 0, are given by Example This formula can be used to solve any quadratic equation. Solve 2x2 − 1 = 3x. Discriminant Solution When you apply the quadratic formula to any quadratic equation, you find the value of b2 4ac, which can be positive, negative, or zero. This expression is called the discriminant. For ax2 + bx + c = 0, where a, b, and c are real numbers: b2 4ac = 0 One realnumber solution; b2 4ac > 0 Two different realnumber solutions; b2 4ac < 0 Two different imaginarynumber solutions, complex conjugates. Equations Reducible to Quadratic Some equations can be treated as quadratic, provided that we make a suitable substitution. Example: x4 5x2 + 4 = 0 Knowing that x4 = (x2)2, we can substitute u for x2 and the resulting equation is then u2 5u + 4 = 0. This equation can then be solved for u by factoring or using the quadratic formula. Then the substitution can be reversed by replacing u with x2, and solving for x. Equations like this are said to be reducible to quadratic, or quadratic in form. Sep 273:17 PM Applications Sep 273:17 PM 255/2. Solve. (5x – 2)( 2x + 3) = 0 Some applied problems can be translated to quadratic equations. Example Time of Free Fall. The Petronas Towers in Kuala Lumpur, Malaysia are 1482 ft tall. How long would it take an object dropped from the top to reach the ground? 255/6. Solve. 10x2 – 16x + 6 = 0 1. Familiarize. The formula s = 16t2 is used to approximate the distance s, in feet, that an object falls freely from rest in t seconds. 2. Translate. Substitute 1482 for s in the formula: 1482 = 16t2. 3. Carry out. Use the principle of square roots. 4. Check. In 9.624 seconds, a dropped object would travel a distance of 16(9.624)2, or about 1482 ft. The answer checks. 5. State. It would take about 9.624 sec for an object dropped from the top of the Petronas Towers to reach the ground. Solve Quadratic Equation by using this Excel program. http://cfcc.edu/faculty/cmoore/quadratic_formula.xls This program graphs a quadratic function and shows the roots (solutions). http://cfcc.edu/mathlab/geogebra/quadratic_roots.html Sep 273:17 PM 256/12. Solve. 4x2 + 12 = 0 256/18. Solve. 3t3 + 2t = 5t2 Sep 302:26 PM Sep 279:10 PM 256/19. Solve. 7x3 + x2 7x 1 = 0 (Hint: Factor by grouping.) 256/20. Solve. 3x3 + x2 12x 4 = 0 (Hint: Factor by grouping.) Sep 279:11 PM 2 171S3.2q Quadratic Equations, Functions, Zeros, and Models 256/19. Solve. 7x3 + x2 7x 1 = 0 (Hint: Factor by grouping.) February 21, 2013 256/22. Use the graph to find (a) The xintercepts (b) The zeros of the function The xintercepts should be written as ordered pairs (x, 0). The zeros (or roots, solutions) are xvalues when y = 0. 256/20. Solve. 3x + x 12x 4 = 0 (Hint: Factor by grouping.) 3 2 256/24. Use the graph to find (a) The xintercepts (b) The zeros of the function The xintercepts should be written as ordered pairs (x, 0). The zeros (or roots, solutions) are xvalues when y = 0. Sep 279:11 PM 256/26. Use the graph to find (a) The xintercepts (b) The zeros of the function Sep 279:12 PM 256/30. Solve by completing the square to obtain exact solutions. x2 + 8x = 15 The xintercepts should be written as ordered pairs (x, 0). The zeros (or roots, solutions) are xvalues when y = 0. 256/28. Use the graph to find (a) The xintercepts (b) The zeros of the function 256/32. Solve by completing the square to obtain exact solutions. x2 = 22 + 10x The xintercepts should be written as ordered pairs (x, 0). The zeros (or roots, solutions) are xvalues when y = 0. Sep 279:13 PM 256/34. Solve by completing the square to obtain exact solutions. x2 + 6x + 13 = 0 Sep 279:15 PM 256/44. Use the quadratic formula to find exact solutions. x2 + 1 = x 256/36. Solve by completing the square to obtain exact solutions. 2x2 5x 3 = 0 256/48. Use the quadratic formula to find exact solutions. 2t2 5t = 1 Sep 279:15 PM Sep 279:18 PM 3 171S3.2q Quadratic Equations, Functions, Zeros, and Models 256/52. Use the quadratic formula to find exact solutions. 5x2 + 3x = 1 256/56. Use the quadratic formula to find exact solutions. 3x2 + 3x = 4 Sep 279:18 PM 256/58. Find discriminant and describe solutions. 4x2 12x + 9 = 0 February 21, 2013 256/58. Find discriminant and describe solutions. 4x2 12x + 9 = 0 256/62. Find discriminant and describe solutions. 5t2 4t = 11 Sep 279:21 PM 256/74. Find the zeros of the function algebraically and solve graphically. Round solutions to 3decimal places if not integer. f(x) = 3x2 + 8x + 2 256/62. Find discriminant and describe solutions. 5t2 4t = 11 Sep 279:21 PM 256/78. Find the zeros of the function algebraically and solve graphically. Round solutions to 3decimal places if not integer. f(x) = x2 x 4 Sep 279:22 PM Sep 279:22 PM 256/82. Find the zeros of the function algebraically and solve graphically. Round solutions to 3decimal places if not integer. f(x) = 3x2 + 5x + 1 Sep 279:22 PM 4 171S3.2q Quadratic Equations, Functions, Zeros, and Models 257/84. Find the zeros of the function algebraically and solve graphically. Round solutions to 3decimal places if not integer. f(x) = 4x2 4x 5 February 21, 2013 257/92. Solve x4 + 3 = 4x2 257/96. Solve y4 15y2 16 = 0 Sep 279:27 PM 257/100. Solve t2/3 + t1/3 6 = 0 Sep 279:27 PM 257/104. Solve (3x + 2)2 + 7(3x + 2) 8 = 0 257/106. Solve 12 = (m2 5m)2 + (m2 5m) 257/102. Solve x 4x = 3 1/2 1/4 Sep 279:27 PM 257/104. Solve (3x + 2)2 + 7(3x + 2) 8 = 0 257/106. Solve 12 = (m2 5m)2 + (m2 5m) Sep 279:27 PM Time of a Free Fall. The formula s = 16t2 is used to approximate the distance s, in feet, that an object falls freely from rest in t seconds. Use this formula for Exercises 111 and 112. 258/111. The Taipei 101 Tower, also known as the Taipei Financial Center, in Taipei, Taiwan, is 1670 ft tall. How long would it take an object dropped from the top to reach the ground? Taipei 101 Tower Taipei, Taiwan 1670 ft http://video.about.com/archite cture/WorldsTallest BuildingsTheTaipei101 Tower.htm Sep 279:27 PM Sep 302:06 PM 5 171S3.2q Quadratic Equations, Functions, Zeros, and Models Time of a Free Fall. The formula s = 16t2 is used to approximate the distance s, in feet, that an object falls freely from rest in t seconds. Use this formula for Exercises 111 and 112. 258/112. At 630 ft, the Gateway Arch in St. Louis is the tallest manmade monument in the United States. How long would it take an object dropped http://www.gatewayarch.com/experien from the top to reach the ce/thegatewayarch/ February 21, 2013 Time of a Free Fall. The formula s = 16t2 is used to approximate the distance s, in feet, that an object falls freely from rest in t seconds. Use this formula for Exercises 111 and 112. 258/111. The Taipei 101 Tower, also known as the Taipei Financial Center, in Taipei, Taiwan, is 1670 ft tall. How long would it take an object dropped from the top to reach the ground? ground? Taipei 101 Tower Taipei, Taiwan 1670 ft http://video.about.com/archite cture/WorldsTallest BuildingsTheTaipei101 Tower.htm Sep 302:06 PM Sep 302:06 PM Time of a Free Fall. The formula s = 16t2 is used to approximate the distance s, in feet, that an object falls freely from rest in t seconds. Use this formula for Exercises 111 and 112. 258/112. At 630 ft, the Gateway Arch in St. Louis is the tallest manmade monument in the United States. How long would it take an object dropped http://www.gatewayarch.com/experienc e/thegatewayarch/ from the top to reach the ground? Sep 302:06 PM 6