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Predicate Logic
n
Methods of Proofs
n
Peter Lo
CS218 © Peter Lo 2004
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∀ and ∃ are known as Predicate Quantifiers
u ∀ means FOR ALL
u ∃ means THERE EXIST
Example:
u If we have 1 computer for all students, we say:
t ∃ one computer ∀ students
u If each student has a separate computer
t ∀ students ∃ one computer
CS218 © Peter Lo 2004
Odd and Even Numbers
Absolution Value
n
n
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Odd Number
u We donated as {x | x=2p+1, ∀x, p∈Z}
Even Number
u We denoted as {x | x=2p, ∀x, p∈Z}
CS218 © Peter Lo 2004
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The Absolution Value of a number x, denote by
the symbol |x|, is defined by the rules:
u |x| = x, ∀x ≥ 0
u |x| = -x, ∀x < 0
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Divisibility
Types of Numbers
n
n
If a divides b, we write a | b.
u i.e. b/a = c {∀a,b,c∈Z}
n
n
Example:
u 3 | 18 is True
t Because 18 = 3 x 6.
CS218 © Peter Lo 2004
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Natural numbers are the counting number and
the set of Natural Numbers is the set {1, 2, 3, … }.
A Prime Number is a natural number greater than
1 that is divisible only by itself and 1.
A Composite Number is a natural Number
greater than 1 that is not a prime number.
u Note that 1 is the only natural number that is
neither prime number nor composite number
CS218 © Peter Lo 2004
Types of Numbers
Types of Numbers
n
n
n
Whole Numbers is the union of 0 and the set of
natural number. The set of whole number is the set
{0, 1, 2, 3, … }.
Integer is the union of the set of whole numbers
and the set of negative numbers. The set of Integer
is the set {… , -3, -2, -1, 0, 1, 2, 3, … }.
n
n
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A Rational Number is any number that can be
written in the form a/b, and denoted as
u {x | x = a / b, ∀a,b≠0, a,b∈Z}
An Irrational Number is a decimal that cannot be
written in the form a/b, where a and b are integers
and b ≠ 0.
Real Number is the union of the set of rational
numbers and the set of irrational numbers. The set
real number is denoted by the symbol ℜ.
CS218 © Peter Lo 2004
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Recurrence Relation
Sequences
n
n
n
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A Recurrence Relation is an equation that defines
the ith value in a sequence of numbers in terms of
the preceding i-1 values.
For example,
u n! = n(n-1)!
= n(n-1)(n-2)… … . 3×2×1
(Do Ex. 1)
CS218 © Peter Lo 2004
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Series
n
n
A sequence is a list in which order is taken into
account.
u Finite Sequence: 1, 2, 3,4, 5, 6, … n
u Infinite Sequence: 1, 2, 3, 4, 5, 6, …
(Do Ex. 2 – 3)
CS218 © Peter Lo 2004
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Summation Properties
A series is the summation of a sequence such as
a1 + a2 + a3 + … + an
(Do Ex. 4)
CS218 © Peter Lo 2004
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CS218 © Peter Lo 2004
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Exponents
Logic
n
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CS218 © Peter Lo 2004
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Given a statement p → q
u The Inverse of p → q is ~p → ~q.
u The Converse of p → q is q → p.
u The Contrapositive of p → q is ~q → ~p
(Do Ex. 5 – 6)
CS218 © Peter Lo 2004
Method of Proofs
Direct Proofs
n
n
n
n
n
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Direct Proofs
Contrapositive Proofs
Proofs by Contradiction
Counterexamples
Mathematical Induction
CS218 © Peter Lo 2004
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A Direct Proof assumes that p(x1 , x2 , … xn ) is
true and then, using p(x1 , x2 , … xn ) as well as
other axioms, definitions and theorem, to show
that q(x1 , x2 , … xn ) is true.
CS218 © Peter Lo 2004
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Example
n
Give a direct proof that the sum of three consecutive
integers is divisible by 3.
n
Answer
Let the three consecutive integers be n, n+1 and n+2.
Sum = n + (n+1) + (n+2)
Contrapositive Proofs
n
Contrapositive , is based on the fact that ~Q ⇒ ~P
is logically equivalent to P ⇒ Q
u i.e. (~q → ~p) ↔ (p→q)
= 3n + 3
= 3(n+1), which is divisible by 3.
CS218 © Peter Lo 2004
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Example
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Proofs by Contradiction
n
Consider the statement ‘If it is cold then Tony will wear a
coat.’ Write down the contrapositive of this statement.
n
Answer:
u ‘If Tony is not wearing a coat, then it is not cold. ’
CS218 © Peter Lo 2004
CS218 © Peter Lo 2004
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n
A Proof by Contradiction is a proof of an
implication that shows that joining the assumption
“Q is False” together with the premise “P is True”
leads to a contradiction.
CS218 © Peter Lo 2004
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Example
n
Counterexamples
Let n be a positive integer. Given a proof by contradiction
that if n is a prime number different from 2, then n is odd.
n
n
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Example 1
n
u
CS218 © Peter Lo 2004
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The difference of any two odd integers is odd.
For all integers n, n 2 - n + 11 is a prime number.
Let R be the relation on the set Z+ of positive integers
defined by aRb if and only if a=b. Prove or give a counterexample to determine the following properties:
u Reflexivity
u Symmetry
u
CS218 © Peter Lo 2004
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Example 2
Disprove the following statements by giving a
counterexample.
u The product of any two prime numbers is prime.
u
The universally quantified statement P(x) is False
if for at least one x in the domain of discourse, the
proposition P(x) is False. A value x in the domain
of discourse that makes P(x) false is called
Counterexample to the statement P(x).
(Do Ex. 7)
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Transitivity
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Mathematical Induction
Principle of M.I.
n
Mathematical induction is a method of proving a law or
theorem by showing that it holds in the first case and
showing that, if it holds for all case preceding a given one,
then it also holds for this case.
n
The essential steps of the proof:
u Prove the theorem for the first case.
u Prove that if the theorem is true for the n th case (or for
the fist through nth case), then it is true for the (n+1 ) th
case.
CS218 © Peter Lo 2004
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Example 1
n
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Example 2
Use Mathematical Induction to prove that
n
CS218 © Peter Lo 2004
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Use mathematical induction to prove that
3
3∑ 5 = (5n +1 − 1)
4
k =0
k
whenever n is a nonnegative integer.
CS218 © Peter Lo 2004
whenever n is a nonnegative integer.
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Example 3
n
A function, f (n), defined for positive integers n, satisfies
the following conditions:
f (1) = 2
f (n + 1) = 2f (n) for n = 1,2,3,...
Use Mathematical Induction to prove that f (n) = 2n
for n = 1,2,3,....
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Example 4
n
Prove by mathematical induction that
n
∑κ
k=1
2
=
n(n + 1)(2n + 1)
6
for n=1,2,3,...
CS218 © Peter Lo 2004
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Example 5
n
n
Example 6
Prove by mathematical induction that Un = n2 + n –1 for all
integers n ≥ 1.
n
Prove by mathematical induction that
n
∑2
j
= 2 n +1 − 2
j =1
Answer
Let P(n) be the statement U n = n 2 + n –1
Step 1: Prove true for n=1.
LHS=1,RHS=1, so true for n=1
Step 2: Prove that if P(n) is true, then P(n+1) is true.
U n+1= U n + 2n + 2
= n 2 + n–1+2n+2
= (n+1) 2 + (n+1)–1
And so if P(n) is true, P(n+1) is true
whenever n is a positive integer.
CS218 © Peter Lo 2004
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