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Parallel vs. Series Circuit Series Circuit • Only a single pathway • As more bulbs are added in series, the voltage in the circuit decreases. • Current remains the same. • If any bulb is removed then the circuit will not work Parallel Circuit • More than one path along which electrons can flow • As more bulbs are added, voltage remains the same • Current is split between pathways • If a bulb is removed, it will not affect the bulbs on separate paths Cells in Series • Connect dry cells end to end, positive to negative terminal • Voltage from each cell is combined /added together • E.g. 1.5V + 1.5V+1.5V= 4.5V The water analogy • 2 pumps are put together to lift water higher; more gravitational potential energy, more voltage Parallel Cells • Dry cells are connected side by side • Positive terminal connected to positive and negative to negative • Overall voltage remains the same, but lasts longer • Amount of electrons available is multiplied Current Through Loads in Series Current stays the same series. Isource=I1=I2=I3 The actual amount of current is inversely related to the amount of resistance and can be found using Ohm's law (ΔV = I • R), Voltage through loads in series Voltage is shared between loads in series Vload= Vsource/#of loads • For identical loads • Vsource= V1+V2+V3 Resistance in Series Resistance increases as you add loads in series Req=R1+R2+R3 Analogy: Series Current= car ; voltage= people house = load 0 1 3 2 Finding Voltage VT= V1 + V2 V1= VT- V2 = 120- 80 = 40V VT= V1 + V2+ V3 V2= VT- V1-V3 = 12- 3 -4 =5V Current through Loads in Parallel Current is shared between different loads in parallel Isource= I1+I2+I3 The sum of currents must equal the current entering at the connecting point Voltage through Loads in Parallel Voltage remains the same throughout a parallel circuit Vsource= V1=V2=V3 * Bulbs in parallel were all bright Analogy: Parallel Current= car ; voltage= people house = load Resistance in parallel Resistance decreases as you move from series to parallel 1 𝑅𝑒𝑞 = 1 𝑅1 1 + 𝑅2 + 1 𝑅3 *think lines in an amusement park Quiz #1 1. Find the total resistance equivalence • • • • a. Two 3-Ω resistors placed in series b. Three 3-Ω resistors placed in series c. Three 5-Ω resistors placed in parallel d. Three resistors with resistance values of 2-Ω , 4-Ω , and 6-Ω are placed in series. • e. Three resistors with resistance values of 5-Ω , 6-Ω , and 7-Ω are placed in series. • f. Three resistors with resistance values of 12-Ω, 3Ω, and 21-Ω are placed in parallel. • A. Req= R1 + R2 = 6Ω • B. Req= R1 + R2 + R3 = 9Ω • C. 1 𝑅𝑒𝑞 1 𝑅1 1 + 𝑅2 = 1 𝑅𝑒𝑞 = 3/5 1 + 𝑅3 Req= 5/3= 1.7Ω D. 12Ω • E. 18Ω • F. Req= 28/13= 2.15 Ω