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LAB PARTNER(S) _ _ _ _ _ __ REPORT FOR EXPERIMENT 10 Double Displacement Reactions Directions for completing table below: 1. Record your observations (Evidence of Reaction) of each experiment. Use the following terminology: (a) "Precipitate formed" (include the color), (b) "Gas evolved," (c) "Heat evolved," or (d) "No reaction observed." 2. Complete and balance the equation for each case in which a reaction occurred. First write the correct formulas for the products, taking into account the charges (oxidation numbers) of the ions involved. Then balance the equation by placing a whole number in front of each formula (as needed) to adjust the number of atoms of each element so that they are the same on both sides of the equation. Use (g) or (s) to indicate gases and precipitates. Where no evidence of reaction was observed, write the words "No reaction" as the righthand side of the equation. Evidence of Reactions Balanced Equations 1. NaCl + K2S04 - 2. CuS0 4 + Na 2C0 3 3. Na 2C0 3 + HCl- 4. NaOH + HCl - 5. CaC1 2 + H 2S0 4 6. NH40H + H2S04 - 7. CuS0 4 + ZnC12 - - 8. Na 2C03 + CaC12 - -- - 11. H 2S0 4 + NaOH FeC1 + NH 40H - 12. CaC0 3 + HCl - 9. 10. CuS04 + NH 4Cl 3 - 93 - REPORT FOR EXPERIMENT 10 (continued) NAME _ _ _ _ _ _ _ _ _ __ QUESTIONS AND PROBLEMS 1. The formation of what three classes of substances caused double displacement reactions to occur in this experiment? (a) (b) (c) 2. Write the equation for the decomposition of sulfurous acid. 3. Using three criteria for double displacement reactions, together with the Solubility Table in Appendix 2, predict whether a double displacement reaction will occur in each example below. If reaction will occur, complete and balance the equation, properly indicating gases and precipitates. If you believe no reaction will occur, write "no reaction" as the right-hand side of the equation. All reactants are in aqueous solution. (a) K2S + (b) NH40H + (c) KOH+ (d) NaC 2H 3 0 2 + (e) Na 2Cr04 + (f) (NH 4h804 + (g) BiC13 + (h) KC 2H 3 0 2 + (i) Na 2C03 + (j) ZnBr2 + CuS04 H2C204 ~ NH 4 Cl~ HClPb(C2 H 30 2 ) 2 - NaClNaOHCo804 HN0 3 - K3P04 - - 94 -