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Transcript
EXPONENTS AND THEIR PROPERTIES
Basic Definitions and Notation
2 3 means 2 • 2 • 2 or 8
x 4 means x • x • x • x
The number 3 is the exponent. The number 2 is the base.
4 is the exponent; x is the base.
WARNING!
The base of an exponent is the symbol directly in front of the exponent.
- 2 3 means - (2 • 2 • 2)
(-2) 3 means (-2)(-2)(-2)
The symbol directly in front of the exponent is 2.
The symbol directly in front of the exponent is a parenthesis. The exponent
belongs to everything in the parentheses.
3x 4 means 3 (x • x • x • x)
(3x) 4 means (3x)(3x)(3x)(3x)
-x 4 means - (x • x • x • x)
x –3
means
1
x3
A negative exponent means the reciprocal of the base with a positive
exponent. It does not indicate a negative number!
– x–3 = –
1
x3
The negative sign in front remains. The negative exponent produces a
reciprocal.
Properties of Exponents
1. xa • xb = x a + b
Product Rule: When multiplying 2 quantities with the same base, keep the
common base and add the exponents.
Example: 5 3 • 5 4 = (5 • 5 • 5) • (5 • 5 • 5 • 5) = (5 • 5 • 5 • 5 • 5 • 5 • 5) = 5 7 = 5 3+4
2.
xa
= xa–b
xb
(x ≠ 0)
Example:
Quotient Rule: When dividing 2 quantities with the same base, keep the common
base and subtract the denominator exponent from the numerator exponent.
36
3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3 3/ ⋅ 3/ ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3
=
=
= 3 • 3 • 3 • 3 = 3 4 = 3 6-2
2
3
3⋅3
3/ ⋅ 3/
Department of Mathematics, Sinclair Community College, Dayton, OH
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3. x 0 = 1
Zero Exponent: Any base (except 0) raised to the zero power equals 1.
(x ≠ 0)
Examples:
50 = 1
15432 0 = 1
(x 3 y 34 z) 0 = 1
4. Power Rules
a) (xa)b = x ab
If an exponential expression is raised to another power, keep the base,
multiply the exponents.
Example: (32)3 = (32) (32) (32) = (3 • 3)(3 • 3)(3 • 3) = 3 • 3 • 3 • 3 • 3 • 3 = 3 6 = 3(3•2)
Warning:
(32)3 and 3 2 • 3 3 are different situations with different exponent rules! Learn to tell them apart!
(32)3 = 32 • 3 = 3 6
3 2 • 3 3 = 3 2+3 = 3 5
b) (xy) a = x a y a
If you have a product being raised to a power, you can raise each factor in
the product to that power.
Example: (2x) 3 = (2x)(2x)(2x) = (2)(2)(2)(x)(x)(x) = 23x3 or 8x3
a
x
xa
c)   = a
y
y
If you have a quotient being raised to a power, you can raise both the
numerator and the denominator to that power.
4
 2
 2  2  2
Example:   =      
 3
 3  3  3
5
24
2⋅2⋅2⋅2
 2
= 4
  =
3⋅3⋅3⋅3
3
 3
Negative Exponents:
a) x –a =
Examples:
1
xa
A negative exponent means the reciprocal of the base with
a positive exponent.
(xyz)−5 =
1
(xyz)5
5−2 =
1
1
=
2
25
5
x 2 (3y) −3 =
x2
x2
x2
=
=
(3y)3 33 y3 27y3
Department of Mathematics, Sinclair Community College, Dayton, OH
2
x -a
yb
= a
y -b
x
b)
The factor in the numerator with a negative exponent moves to the
denominator. The factor in the denominator with a negative exponent
moves to the numerator. Both exponents become positive.
4-3
52
25
=
=
-2
3
64
5
4
Examples:
xy -5
 x
=  2
2
-6
z w
z
-5
 y 
 x
  -6  =  2
 w 
z
6
xw 6
 w 
=
 5 
z 2 y5
 y 
Warning:
This only works with factors. It will not work if sums or differences are involved.
x −2 + y −1
z −3
c)
x
 
y
-a
y
=  
x
cannot be inverted to the form
a
A quotient with a negative exponent outside the parentheses may be
inverted inside the parentheses, with a positive exponent on the
outside.
-3
Examples:
z3
!
x 2 + y1
3
33
27
5
 3
=
=
=
 
 
3
125
5
 3
5
 x3 y 
 2 
 z 
-7
 z2 
=  3 
x y
7
More Examples and Using the Properties Together
Simplify the following:
1)
x 3 y2 x 4
= x 3 x 4 y2
= x 3+ 4 y 2
= x 7 y2
The properties of exponents apply only when the bases are the same. Start by
grouping like bases together.
Use the product rule and add exponents.
Cannot be simplified further (bases are not the same).
Department of Mathematics, Sinclair Community College, Dayton, OH
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2)
(5x 3 ) 2
Use the power rule to distribute the exponent and square each factor of the
product.
Use the power rule (raising x 3 to second power) and multiply exponents.
Note: If your base is a number, you may multiply it out if you wish or you may
leave it in exponential form. Either form is acceptable. As a rule of thumb,
multiply it out if it’s easy, leave it in exponential form if it’s too much work.
= 5 2 (x 3 ) 2
= 52 x6
= 25x 6
3)
4)
- x 2 (x 3 ) 4
= - x 2 • x 12
= - (x 2 • x 12 )
= - (x 14 )
= - x 14
 x 4 y3z 7 


2
5 
 17 x yz 
Tricky - be careful! Start with the (x 3 ) 4 and simplify.
Both bases are x’s (the negative sign is not involved) so you can simplify further.
0
This “looks” like a difficult problem. Resist the urge to simplify inside the
parentheses first. Look at the exponent outside those parentheses.
Any base (except 0) raised to the zero power equals 1.
=1
5)
 2x 4 
 3 
 3x 
5
You may raise each factor in numerator and denominator to the fifth power or you
may simplify inside the parentheses first.
25 (x 4 )5
= 5 3 5
3 (x )
OR
2 5 x 20
= 5 15
3 x
 2 x4 
=  i 3
3 x 
2

=  i x 4 −3 
3

=
2 5 x 20
• 15
35
x
2

=  i x1 
3

=
25
• x 20−15
5
3
 2x 
= 
 3 
25
= 5 • x5
3
5
25 x 5
=
35
25 x 5
=
35
5
5
5
Cannot be simplified further; bases are not the same.
Department of Mathematics, Sinclair Community College, Dayton, OH
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6)
Since the bases are the same, we don’t need to use any negative exponent
properties for this problem. Just use the quotient rule.
x5
x −4
= x 5 – (- 4)
= x 5+4
= x9
( x − 3y )
7)
−4
Use the negative exponent rules to invert the quotient with positive
exponents.
( xy )
2 −7
( xy )
2 7
=
8)
( x − 3y )
(5
−1
x −3 )
( 3x
or
4
−2
4
2 3
Here's a jumble of positive and negative exponents all mixed up.
A simple way to proceed is to first raise all the inner factors,
including those with exponents, to their outer exponents.
3 −2
(5 ) ( x ) ( 2 ) ( x ) ( y )
( 3 )( x ) ( y )
−1 −1
=
( x − 3y )
( 2xy )
y )
−1
Remember: (a + b)m ≠ am + bm !
(x – 3y)4 cannot be further simplified.
x 7 y14
−3 −1
−2 −2
−2
3
3
2 3
3 −2
Use the power rule to multiply exponents.
51 x 3 23 x 3 y 6
3−2 x 4 y −6
Group numbers and like bases in the numerator. Multiply numbers
and use the product rule on the variables to simplify.
40 x 6 y 6
3−2 x 4 y −6
Separate terms with positive exponents from those with negative
exponents
=
40 x 6 y 6
1
1
i −2 i −6
4
x
3
y
Use the negative exponent property to create reciprocals with
positive exponents
=
40 x 6 y 6 32 y 6
i
i
1
1
x4
Use the product and quotient rules on like variables.
=
40 i 9 x (6− 4) y (6 + 6) = 360 x 2 y12
=
* =
* The quotient rule could have been applied at this step on the variables.
Department of Mathematics, Sinclair Community College, Dayton, OH
5
Problems
Simplify:
1) x 4 x 9 x 2
2) (7y) 4 (7y) 3
3) 5x 3 (3x 2 )
4)
5)
x 8 y10 z 5
x 4 y10 z
7)
 5z 5 
 3 
 z 
9)
 4x 3 y 2 z 5 


 3xy 
11)
x2 + x5
13)
 a −1 b 
 2 
 c 
3y 5
2y 2
6) (2xy 4 ) 3
2
8)
2
10)
 − 2x 4 


2 
xy


4
 5x 5 y10 z 8 


2
 8xz

0
12)
(5m)4 (5m)-3
14)
(7x –6 z4) -3
−2
Answers
1) x 15
4)
3y 3
2
7) 5 2 z 4 or 25z 4
10) 1
12) 5m
8)
2) 7 7 y 7 or (7y) 7
3) 15x 5
5) x 4 z 4
6) 2 3 x 3 y 12 or 8x 3 y 12
2 4 x 12
16x 12
or
y8
y8
9)
4 2 x 4 y 2 z10
16 x 4 y 2 z 10
or
9
32
11) x 2 + x 5 (Trick question. x 2 and x 5 are not like terms and cannot be
added. There are no exponent properties that apply to this situation!)
13)
a 2 c4
b2
14)
x18
343z12
Department of Mathematics, Sinclair Community College, Dayton, OH
6