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LESSON
9.1
Name
Measures of Center
and Spread
9.1
Explore
Use statistics appropriate to the shape of the data distribution to compare
center (median, mean) and spread (interquartile range, standard
deviation) of two or more different data sets.
Mathematical Practices
Game 1
Game 2
Game 3
Average Score
Caleb
151
153
146
150
Kim
122
139
189
150

Language Objective
Find Caleb’s average score over the three games and enter it in the table.
450
151 + 153 + 146 _
__
=
= 150
3
3
Explain the difference between a measure of center and a measure of
spread.
View the Engage section online. Discuss who might
participate in a town choir, and describe the four
sections that typically make up a choir: soprano, alto,
tenor, and bass. Then preview the Lesson
Performance Task.
Name
Complete the table.
MP.1 Problem Solving

Find Kim’s average score over the three games and enter it in the table.
450
122 + 139 + 189 _
__
=
= 150
3
3
© Houghton Mifflin Harcourt Publishing Company . Image Credits: ©Mike
Kemp/Rubberball/Corbis
PREVIEW: LESSON
PERFORMANCE TASK
Exploring Data
Caleb and Kim have bowled three games. Their scores are shown in the
chart below.
S-ID.2
Use the mean and median to describe and compare
the center of data sets. Use the range, interquartile
range, or standard deviation to describe and
compare the spread of data sets.
Measures of Center and Spread
Resource
Locker
The student is expected to:
Essential Question: How can you
describe and compare data sets?
Date
Essential Question: How can you describe and compare data sets?
Common Core Math Standards
ENGAGE
Class

How do their average scores compare?
Both have an average score of 150.

Caleb’s / Kim’s scores are more consistent.

Caleb’s scores are farther from / closer to the average than Kim’s.
They bowl a fourth game, where Caleb scores 150 and Kim scores a 175.
How does this affect their averages?
increases .

Caleb’s average stays the same .

Does the Game 4 score affect the consistency of their scores? Explain.

Kim’s average
No, Caleb’s scores are still consistent, and Kim’s scores are still inconsistent.
Module 9
Lesson 1
377
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Correction
Date
Class
Name
Measures
9.1
A1_MNLESE368170_U4M09L1.indd 377
of Center
d
and Sprea
sets?
are data
n,
and comp
describe
re center (media
ution to compa nt data sets.
data distrib
or more differe
shape of the
on) of two
riate to the
rd deviati
statistics appropuartile range, standa
S-ID.2 Use
spread (interq
mean) and
Data
the
Exploring
shown in
scores are
Explore
Their
.
games
bowled three
Kim have
Caleb and
Score
Average
chart below.
Game 3
ion: How
Quest
Essential
can you
Game 2
Game 1
Name
153
151
Caleb
139
122
Kim
the table.
Complete

Credits: ©Mike
189
the three
score over
s average
Find Caleb’
450
= 150
+ 146 = _
_
+ 153
3
151
_
3
HARDCOVER
Turn to Lesson 9.1 in the
hardcover edition.
150
150
games and
games and
over the three
average score
450
= 150
+ 189 = _
_
+ 139
3
122
_
3
compare?
average scores
150.
How do their
of
ge score
an avera
Both have
enter it in
the table.
enter it in
the table.
Find Kim’s


y . Image
g Compan
146
Resource
Locker
consistent.
game is more
Caleb’s / Kim’s
e than Kim’s.
to the averag
r from / closer
scores a 175.
are farthe
and Kim
Caleb’s scores
scores 150
where Caleb
a fourth game, averages?
increases .
They bowl
their
e
this affect
Kim’s averag
How does
same .
the
stays
e
? Explain.
Caleb’s averag
t.
of their scores
tency
inconsisten
consis
s are still
affect the
Kim’s score
Game 4 score
stent, and
Does the
consi
still
are
’s scores
No, Caleb

Harcour t
n Mifflin
© Houghto
/Corbis
bberball
Kemp/Ru
Publishin




Lesson 1
377
Module 9
377
Lesson 9.1
L1.indd
0_U4M09
SE36817
A1_MNLE
377
3/28/14
4:22 PM
7/7/14 1:18 PM
.
EXPLORE
Reflect
1.
Discussion Is the average an accurate representation of Caleb’s bowling?
Yes, Caleb is a consistent bowler, and his scores are all very close to his average.
Exploring Data
2.
Discussion Is the average an accurate representation of Kim’s bowling?
No. Kim is an inconsistent bowler and has a fairly wide range of scores.
Explain 1
INTEGRATE MATHEMATICAL
PRACTICES
Focus on Modeling
MP.4 Graphing a data set and its mean on a number
Measures of Center: Mean and Median
Two commonly used measures of center for a set of numerical data are the mean and median. Measures of center
represent a central or typical value of a data set. The mean is the sum of the values in the set divided by the number
of values in the set. The median is the middle value in a set when the values are arranged in numerical order.
Example 1

line can help students visualize how close the values
are to the mean value.
Find the mean and median of each data set.
The number of text messages that Isaac received each day for a week is shown.
QUESTIONING STRATEGIES
47, 49, 54, 50, 48, 47, 55
How can you determine the mean value of a
data set? Find the sum of all the numbers,
then divide the sum by the number of values in the
data set.
Find the mean. Divide the sum by the numbers of data values.
350 = 50. The mean is 50 text messages a day.
_
7
Find the median. Rewrite the values in increasing order.
47, 47, 48, 49, 50, 54, 55. The median is 49 text messages a day.

The amount of money Elise earned in tips per day for 6 days is listed below.
EXPLAIN 1
$75, $97, $360, $84, $119, $100
835
_ = $139.17 The mean is $139.17 .
6
Find the median. Rewrite the values in increasing order.
75, 84 , 97 , 100 , 119 , 360
97 + 100
Find the mean of the middle two values. __ = 98.5
2
The median is
Module 9
$98.50 .
378
Measures of Center: Mean and
Median
© Houghton Mifflin Harcourt Publishing Company
Find the mean to the nearest $0.01. Divide the sum by the number of data values.
INTEGRATE MATHEMATICAL
PRACTICES
Focus on Critical Thinking
MP.3 Ask students what must be true about a data
set in order for the median to be one of the values in
the data set. Students should understand that when
the median is in the data set, either the set has an odd
number of values, or the set has an even number of
values and the two middle values are the same.
Lesson 1
PROFESSIONAL DEVELOPMENT
A1_MNLESE368170_U4M09L1.indd 378
Integrate Mathematical Practices
7/7/14 1:18 PM
This lesson provides an opportunity to address Mathematical Practices MP.1,
which calls for students to “make sense of problems and persevere in solving
them.” Students learn about statistical measures that describe the center and
spread of a set of numerical data. They will perform multi-step calculations to
find the mean, median, range, interquartile range, and standard deviation of a
data set, and they will use those measures to make sense of data.
Measures of Center and Spread
378
Reflect
QUESTIONING STRATEGIES
3.
What is a situation in which the mean
would not be the best measure of center?
Explain. Possible answer: A set of test scores in
which the scores are fairly consistent but there is
one very low score; the very low score will lower the
mean to below the typical value for the data set.
large value makes the data inconsistent.
Your Turn
Find the mean and median of each data set.
4.
If you had test scores that were mostly
clustered around a particular value, but one
score was a lot higher, would you prefer that your
teacher report your class grade using the median or
the mean of the scores? Explain. I would prefer the
mean, because the higher score would raise the
mean, but it would not affect the median much.
5.
Why must the median be found before the
first and third quartiles? The first and third
quartiles are the halfway points of the lower half
and upper half of the data, respectively. In order to
find these, you must first find the halfway point of
the data (the median).
The median: _____
= 72.5
2
72 + 73
Raul recorded the following golf scores in his last 7 games.
84, 94, 93, 89, 94, 81, 90
The median: 81, 84, 89, 90, 93, 94, 94
The mean is 89.3, and the median is 90.
Measures of Spread: Range and IQR
Explain 2
Measures of spread are used to describe the consistency of data values. They show the distance between data values
and their distance from the center of the data. Two commonly used measures of spread for a set of numerical data are
the range and interquartile range (IQR). The range is the difference between the greatest and the least data values.
Quartiles are values that divide a data set into four equal parts. The first quartile (Q 1)is the median of the lower half
of the set, the second quartile (Q 2) is the median of the whole set, and the third quartile (Q 3) is the median of the
upper half of the set. The interquartile range (IQR) of a data set is the difference between the third and first
quartiles. It represents the range of the middle half of the data.
Range : 9 -1 = 8
IQR: 7 - 3 = 4
© Houghton Mifflin Harcourt Publishing Company
QUESTIONING STRATEGIES
456
The mean: ___
= 76
6
625
The mean: ___
= 89.3
7
Measures of Spread: Range and IQR
Students may include the median in the upper and
lower halves of the data set when finding Q1 and Q3.
Remind them that the median is never included in
these halves.
Niles scored 70, 74, 72, 71, 73, and 96 on his 6 geography tests.
The mean is 76, and the median is 72.5.
EXPLAIN 2
AVOID COMMON ERRORS
Discussion For the data on tips, which measure of center is more accurate in describing the typical value?
Explain.
The median is more accurate. The mean is higher than all but one of the values. That one
1, 2, 2, 3, 3, 4, 4
First quartile (Q1): 3
5,
6, 6, 7, 7, 8, 8, 9
Third quartile (Q3): 7
Median (Q2): 5
Example 2

Find the median, range, and interquartile range for the given data set.
The April high temperatures for 5 years in Boston are 77 °F, 86 °F, 84 °F, 93 °F, and 90 °F
Order the data values.
Median: 77, 84, 86, 90, 93
median
Range: 93 - 77 = 16
Interquartile range:
lower half
upper half
77, 84, 86, 90, 93
median
77 + 84
90 + 93
Q 1 = _ = 80.5 and Q 3 = _ = 91.5
2
2
IQR = Q 3 - Q 1 = 91.5 - 80.5 = 1
Module 9
379
Lesson 1
COLLABORATIVE LEARNING
A1_MNLESE368170_U4M09L1.indd 379
Peer-to-Peer Activity
Have students work in pairs. Have each pair write 10 different numbers on
separate slips of paper, then evenly divide the slips so that each student has 5
numbers to create a data set. Have students determine the standard deviations for
their data sets and compare results with their partners. Ask students how they
would select a data set so that the standard deviation is as small as possible. Have
them discuss strategies.
379
Lesson 9.1
3/27/14 10:42 PM
B
The numbers of runs scored by a softball team in 20 games are given.
3, 4, 8, 12, 7, 5, 4, 12, 3, 9, 11, 4, 14, 8, 2, 10, 3, 10, 9, 7
Order the data values.
2, 3, 3, 3, 4, 4, 4, 5 , 7 , 7 , 8 , 8 , 9 , 9, 10, 10, 11, 12, 12, 14
median
7 + 8
Median = __ =
2
Range = 14 - 2 = 12
7.5
Interquartile range.
4 + 4
10 + 10
Q 1 = __ = 4 and Q 3 = __ = 10
2
2
IQR = Q 3 - Q 1
= 10 - 4
= 6
7.5
The median is
The range is
12
The IQR is
6
.
.
.
Reflect
6.
Discussion Why is the IQR less than the range?
The IQR is less than the range because the range is the difference of the two extreme values, the
largest and smallest data values. The IQR is the difference between numbers within the ordered
set, so unless all of the values in the set are the same, Q 1 will be larger than the smallest element
of the set, and Q 3 will be smaller than the largest element of the set.
Find the median, range, and interquartile range for the given data set.
7.
21, 31, 26, 24, 28, 26
21, 24, 26, 26, 28, 31
The median is 26.
8.
(median is underlined and quartiles are double underlined)
Range = 31 - 21 = 10
IQR = 28 - 24 = 4
The high temperatures in degrees Fahrenheit on 11 days were 68, 71, 75, 74, 75, 71, 73, 71, 72, 74, and 79.
68, 71, 71, 71, 72, 73, 74, 74, 75, 75, 79
The median is 73.
Range = 79 - 68 = 11
Module 9
380
© Houghton Mifflin Harcourt Publishing Company
Your Turn
IQR = 75 - 71 = 4
Lesson 1
DIFFERENTIATE INSTRUCTION
A1_MNLESE368170_U4M09L1.indd 380
Critical Thinking
7/7/14 1:18 PM
Discuss whether the standard deviation of a data set (the square root of the
average squared deviation from the mean) is a better measure of spread than the
average unsquared deviation from the mean. Have students calculate and compare
the two measures for a few data sets. Students should realize that if deviations are
not squared, negative and positive deviations can cancel each other out, so a data
set with a large spread could have a very small average deviation. Squaring the
deviations makes all the numbers positive, so this does not happen. In addition,
squaring gives large deviations more weight than small deviations.
Measures of Center and Spread
380
Measures of Spread: Standard Deviation
Explain 3
EXPLAIN 3
Another measure of spread is the standard deviation, which represents the average of the distance between individual
data values and the mean.
Measures of Spread: Standard
Deviation
The formula for finding the standard deviation of the data set {x 1, x 2, x 2, x 2 ∙∙∙, x n}, with n elements and
mean x, is shown below.
INTEGRATE MATHEMATICAL
PRACTICES
Focus on Math Connections
MP.1 Discuss the meaning of the standard
A
______
standard deviation =
1
2
2
_
2
n
_
2
Find the standard deviation of 77, 86, 84, 93, 90.
Find the mean.
77 + 86 + 84 + 93 + 90
mean = ___
5
430
=_
5
= 86
deviation for a data set. Students should be aware that
a low standard deviation means that most data points
will be very close to the mean, while a high standard
deviation means that the data points are spread out
across a large range of values.
Complete the table.
_
_
Data Value, x
Deviation from Mean, x - x
Squared Deviation, (x - x) 2
77
77 - 86 = -9
(-9)2 = 81
86
86 - 86 = 0
02 = 0
84
84 - 86 = -2
(-2)2 = 4
93
93 - 86 = 7
72 = 49
90
90 - 86 = 4
42 = 16
QUESTIONING STRATEGIES
Find the mean of the squared deviations.
© Houghton Mifflin Harcourt Publishing Company
How do the three measures of spread—range,
interquartile range, and standard deviation—
differ? How is each one related to measures of center
for a data set? The range measures the spread of the
entire data set, but it is not based on any measure of
center. The IQR depends on the median; it measures
the spread of the middle half of the data. The
standard deviation measures the spread of the data
relative to the mean.
_
x - x) + (x - x) + ∙∙∙ + (x - x)
√ (____
n
81 + 0 + 4 + 49 + 16
mean squared deviation = __
5
150
=_
5
= 30
―
Find the square root of the mean of the squared deviations, rounding to the nearest tenth. √30 = 5.5
The standard deviation is approximately 5.5.
B
Find the standard deviation of 3, 4, 8, 12, 7, 5, 4, 12, 3, 9, 11, 4, 14, 8, 2, 10, 3, 10, 9, 7.
Find the mean.
2+
3 + 3 + 3 + 4 + 4 + 4 + 5 + 7 + 7 + 8 + 8 + 9 + 9 + 10 + 10 + 11 + 12 + 12 + 14
________
20
145
=_
20
mean =
= 7.25
Module 9
381
Lesson 1
LANGUAGE SUPPORT
A1_MNLESE368170_U4M09L1.indd 381
Connect Vocabulary
Review the explanations of measures of center, mean, and median. Students may
be familiar with the concept of average, but not with the academic term mean, or
they may understand that mean is another word for average, but may not grasp
the concept of median. Remind them to ask for additional clarification before
moving forward if they don’t understand the terms. Remind them that they can
also use the glossary as a resource.
381
Lesson 9.1
7/7/14 1:18 PM
Complete the table.
Data Value, x
_
Deviation from Mean, x -x
2
2-
3
3-
7.25 = −5.25
7.25
−4.25
=
3
−4.25
3
−4.25
4
4-
7.25
4
−3.25
4
−3.25
5
7
8
=
0.75
0.75
8
9
7.25
9 - 7.25 = 1.75
1.75
−3.25
) = 10.5625
(
(
−2.25
)=
)=
2
5.0625
2
−0.25
0.0625
0.0625
( 0.75 ) =
2
0.5625
0.5625
( 1.75 ) =
2
3.0625
3.0625
( 2.75 ) =
© Houghton Mifflin Harcourt Publishing Company
9
(
2
10.5625
−0.25
8-
2
10.5625
7.25 = −0.25
7
2
18.0625
5 - 7.25 = −2.25
7-
( −5.25 ) = 27.5625
( −4.25 ) = 18.0625
18.0625
−3.25
=
_
Squared Deviation, (x - x) 2
2
10
10 - 7.25 = 2.75
2.75
10
7.25 = 3.75
7.5625
7.5625
( 3.75 ) = 14.0625
2
11
11 -
12
12 - 7.25 = 4.75
( 4.75 ) = 22.5625
12
4.75
22.5625
14
14 - 7.25 = 6.75
(−6.25) = 45.5625
2
Module 9
A1_MNLESE368170_U4M09L1.indd 382
382
2
Lesson 1
7/7/14 1:18 PM
Measures of Center and Spread
382
Find the mean of the squared deviations.
ELABORATE
27.5625 + 3(18.0625) + 3(10.5625) + 5.0625 + 2(0.0625) +
2(0.5625) + 2(3.0625) + 2(7.5625) + 14.0625 + 2(22.5625)
+ 45.5625
mean squared deviation = _______
20
INTEGRATE MATHEMATICAL
PRACTICES
Focus on Technology
MP.5 Explain that measures of center and spread
245.75
=_
20
= 12.2875
――――
Find the square root of the mean of the squared deviations, rounding to the nearest tenth.
√ 12.2875 = 3.5
can also be found using a computer spreadsheet. If
spreadsheet software is available, demonstrate how to
enter the data into cells of a spreadsheet and use the
statistical functions available within the software.
The standard deviation is approximately
9.
In terms of data values used, what makes calculating the standard deviation different from calculating
the range?
The range uses only the largest and smallest values, while the standard deviation
measures the average distance from each data point to the mean.
Your Turn
10. Find the standard deviation of 21, 31, 26, 24, 28, 26.
21 + 24 + 2(26) + 28 + 31
156
mean =
=
= 26
6
6
_
_
Data Value, x
Deviation from Mean, x - x
Squared Deviation, (x - x) 2
___ _
© Houghton Mifflin Harcourt Publishing Company
SUMMARIZE THE LESSON
21
-5
25
24
-2
4
26
0
0
26
0
0
28
2
4
31
5
25
mean of the squared deviations =
――
11. Find the standard deviation of 68, 71, 75, 74, 75, 71, 73, 71, 72, 74, and 79.
68
+ 3(71) + 72 + 73 + 2(74) + 2(75) + 79
____________________________
= 73
11
mean of the squared deviations =
――
√7.64 ≈ 2.8
Module 9
A1_MNLESE368170_U4M09L1.indd 383
Lesson 9.1
25
+ 4 + 25 + 4
58
___________
= __
≈ 9.67
6
6
√9.67 ≈ 3.1 The standard deviation is approximately 3.1.
mean =
383
.
Reflect
You may wish to point out that the standard deviation
formula taught in this lesson should be used when a
data set includes an entire population. A slightly
different formula, with n - 1 in the denominator
instead of n, is used when the data set is only a
sample of a population. The two formulas are
available as different functions in spreadsheet
software.
How can you determine the first and third
quartile of a data set? First, determine the
median. This allows you to determine the lower and
upper half of the data set. The first quartile is the
median of the lower half of the data set, and the third
quartile is the median of the upper half of the data
set. Find the median of each half of the data set the
same way you find the median of the entire data set.
3.5
25
+ 5(4) + 3(1) + 36
_______________
≈ 7.64
11
The standard deviation is approximately 2.8.
383
Lesson 1
7/7/14 1:18 PM
Elaborate
EVALUATE
12. In Your Turn 11, what is the mean of the deviations before squaring? Use your answer to explain why
squaring the deviations is helpful.
The mean of the deviations is 0. Squaring the deviations is helpful because it prevents the
positive and negative deviations from averaging to 0.
13. How can you determine the first and third quartiles of a data set?
First, determine the median. This allows you to determine the lower and upper half of the
data set. The first quartile is the median of the lower half of the data set, and the third
quartile is the median of the upper half of the data set. Find the median of each half of the
ASSIGNMENT GUIDE
data set the same way you find the median of the entire data set.
14. How can you determine the standard deviation of a data set?
Find the mean of the data. Then find the square of the distance between each data value
and the mean. Find the mean of the squared values. The standard deviation is the square
root of this mean.
15. Essential Question Check-In What does the measure of center of a data set indicate?
The measure of center identifies either a central or typical value of the data.
Evaluate: Homework and Practice
1.
The data set {13, 24, 14, 15, 14} gives the times of Tara’s one-way ride to school
(in minutes) for one week. Is the average (mean) of the times a good description of
Tara’s ride time? Explain.
The numbers of hours Cheri works each day are 3, 7, 4, 6, and 5.
3____________
+7+4+6+5
25
= __
=5
5
5
median: 3, 4, 5, 6, 7
3.
The median is 5.
The weights in pounds of 6 members of a basketball team are 125, 136, 150, 119, 150, and 143.
125
+ 136 + 150 + 119 + 150 + 143
823
_______________________
= ___
≈ 137.2
6
6
136 + 143
median: 119, 125, 136, 143, 150, 150 The median is _______
= 139.5.
2
mean =
4.
Lesson 1
384
Exercise
A1_MNLESE368170_U4M09L1.indd 384
Depth of Knowledge (D.O.K.)
Mathematical Practices
2 Skills/Concepts
MP.2 Reasoning
2–8
1 Recall of Information
MP.2 Reasoning
9–23
2 Skills/Concepts
MP.2 Reasoning
24–27
3 Strategic Thinking
MP.3 Logic
1
Exercises 2–8 ,
26–27
Example 2
Measures of Spread: Range and IQR
Exercises 9–15,
22, 25
Example 3
Measures of Spread: Standard
Deviation
Exercises 16–21,
23–24
• Measures of center preserve information about
the values in a data set, while measures of spread
do not.
The median is 12.
Module 9
Example 1
Measures of Center: Mean
and Median
• Measures of center tell how the data clusters
around a value, while measures of spread tell how
the data is spread out from a central value.
36
+ 18 + 12 + 10 + 9
85
_______________
= __
= 17
5
5
median: 9, 10, 12, 18, 36
Exercise 1
between measures of center and measures of spread.
Answers should include information such as the
following:
36, 18, 12, 10, 9
mean =
Explore
Exploring Data
INTEGRATE MATHEMATICAL
PRACTICES
Focus on Communication
MP.3 Ask students to describe the differences
© Houghton Mifflin Harcourt Publishing Company
Find the mean and median of each data set.
mean =
Practice
• Online Homework
• Hints and Help
• Extra Practice
No. The day the trip took 24 minutes will skew the value of the average to be too high.
2.
Concepts and Skills
7/7/14 1:18 PM
Measures of Center and Spread
384
5.
MULTIPLE REPRESENTATIONS
The average yearly gold price for the period from 2000–2009:
$279.11, $271.04, $309.73, $363.38, $409.72, $444.74, $603.46,
$695.39, $871.96, $972.35
When finding the standard deviation of a data set,
students may benefit from plotting the values on a
number line, marking the mean, and identifying the
distance of each data value from the mean.
279.11 + 271.04 + 309.73 + 363.38 + 409.72 + 444.74 + 603.46 + 659.39 + 871.96 + 972.35
____________________________________________________________
10
5220.88
= ______
= 522.008, or $522.01
mean =
10
median: 271.04, 279.11, 309.73, 363.38, 409.72, 444.74, 603.46, 695.39, 871.96, 972.35
854.46
The median is ___________
= _____
= $427.23.
2
2
409.72 + 444.74
6.
AVOID COMMON ERRORS
There are 28, 30, 29, 26, 31, and 30 students in a school’s six Algebra 1 classes.
mean =
Remind students that in order to determine the
median of a data set, they must list the values in
numerical order. Failing to order the data values
before finding the median may result in an incorrect
solution.
28 + 30 + 29 + 26 + 31 + 30
174
___________________
= ____
= 29
6
6
median: 26, 28, 29, 30, 30, 31
7.
The median is _____
= 29.5.
2
29 + 30
13, 14, 18, 13, 12, 17, 15, 12
13
+ 14 + 18 + 13 + 12 + 17 + 15 + 12
114
_________________________
= ___
= 14.25
8
8
13 + 14
median: 12, 12, 13, 13, 14, 15, 17, 18
The median is _____
= 13.5.
2
mean =
8.
The numbers of members in five karate classes are 13, 12, 10, 16, and 19.
mean =
13
+ 12 + 10 + 16 + 19
70
_______________
= __
= 14
5
5
median: 10, 12, 13, 16, 19
9.
The median is 13.
Find the range and interquartile range for 3, 7, 4, 6, and 5.
3, 4, 5, 6, 7
Range = 7 - 3 = 4
The interquartile range is IQR = 6.5 - 3.5 = 3.
10. Find the range and interquartile range for 125, 136, 150, 119, 150, and 143.
119, 125, 136, 143, 150, 150
Range = 150 - 119 = 31
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The interquartile range is IQR = 150 - 125 = 25.
11. Find the range and interquartile range for 36, 18, 12, 10, and 9.
9, 10, 12, 18, 36
Range = 36 - 9 = 27
The interquartile range is IQR = 27 - 9.5 = 17.5.
12. Find the range and interquartile range for $279.11, $271.04, $309.73, $363.38,
$409.72, $444.74, $603.46, $695.39, $871.96, and $972.35.
271.04, 279.11, 309.37, 363.38, 409.72, 444.74, 603.46, 695.39, 871.96, 972.35
Range = 972.35 - 271.04 = 701.31
The interquartile range is IQR = 695.39 - 309.73 = 385.66.
13. Find the range and interquartile range for 28, 30, 29, 26, 31, and 30.
26, 28, 29, 30, 30, 31
Range = 31 - 26 = 5
The interquartile range is IQR = 30 - 28 = 2.
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14. Find the range and interquartile range for 13, 14, 18, 13, 12, 17, 15, and 12.
CRITICAL THINKING
Range = 18 - 12 = 6
12, 12, 13, 13, 14, 15, 17, 18
Challenge students to give an example of a data set
for which the mean is twice the median. Have
students present and explain their answers, then
compare the different data sets that students created.
The interquartile range is IQR = 16 - 12.5 = 3.5.
15. Find the range and interquartile range for 13, 12, 15, 17, and 9.
9, 12, 13, 15, 17
Range = 17 - 9 = 8
The interquartile range is IQR = 16 - 10.5 = 5.5.
16. Find the standard deviation of 3, 7, 4, 6, and 5.
The mean is 5.
The mean of the squared deviations is
―
4____________
+1+0+1+4
= 2.
5
The standard deviation is √2 ≈ 1.4.
17. Find the standard deviation of 125, 136, 150, 119, 150, and 143.
The mean is 137.17.
The mean of the squared deviations is
330.03
+ 148.03 + 1.36 + 34.02 + 164.69 + 164.69
842.83
_________________________________
≈ _____
≈ 140.5.
6
6
――
The standard deviation is √140.5 ≈ 11.9.
18. Find the standard deviation of 36, 18, 12, 10, and 9.
The mean is 17.
The mean of the squared deviations is
――
64
+ 49 + 25 + 1 + 361
_______________
= 100.
5
The standard deviation is √100 = 10.
19. Find the standard deviation of $279.11, $271.04, $309.73, $363.38, $409.72, $444.74,
$603.46, $695.39, $871.96, and $972.35. Round the mean to the nearest $0.01 and the
squared deviations to the nearest whole number.
The mean is 522.09.
63,025
+ 59,038 + 45,096 + 25,188 + 12,627 + 5983 + 6621 + 30,034 + 122,410 + 202,736
___________________________________________________________
= 57,258.
10
―――
The standard deviation is √57,258 ≈ 239.3.
20. Find the standard deviation of 28, 30, 29, 26, 31, and 30.
The mean is 29.
9 + 3(1) + 4
The mean of the squared deviations is ________
= 2.67.
6
――
The standard deviation is √2.67 ≈ 1.6.
21. Find the standard deviation of 13, 14, 18, 13, 12, 17, 15, and 12.
© Houghton Mifflin Harcourt Publishing Company
The mean of the squared deviations is
The mean is 14.25.
The mean of the squared deviations (rounded).
mean =
――
(5.06) + 2(1.56) + 0.06 + 0.56 + 7.56 + 14.06
2______________________________
= 4.44
8
√4.44 = 2.1
The standard deviation is approximately 2.1.
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Measures of Center and Spread
386
22. Determine whether or not the third quartile has the same value as a member of the
data set. Select the correct answer for each lettered part.
JOURNAL
Have students describe the steps to take to find the
standard deviation and the interquartile range for a
data set. Students should include how to find the
mean as a step in finding the standard deviation, as
well as how to find the first and third quartiles as a
step in finding the interquartile range.
A. {79, 91, 90, 99, 91, 80, 80, 90}
✗
Yes
No
B. {98, 96, 96, 95, 91, 81, 87}
✗
Yes
No
C. {88, 95, 89, 93, 88, 93, 84, 93, 85, 92}
✗
Yes
No
D. {97, 84, 96, 82, 93, 88, 82, 91, 94}
Yes
✗
No
E. {94, 85, 95, 80, 97}
Yes
✗
No
F. {85, 89, 81, 89, 85, 84}
✗
Yes
No
Use this data for Exercises 23 and 24. The numbers of members
in 6 yoga clubs are 80, 74, 77, 71, 75, and 91.
23. Find the standard deviation of the numbers of members to
the nearest tenth.
The mean:
80
+ 74 + 77 + 71 + 75 + 91
468
___________________
= ___
= 78
6
6
The mean of the squared deviations
is
49
+ 16 + 9 + 1 + 4 + 169
_________________
= 41.33.
6
――
The standard deviation is √41.33 ≈ 6.4.
© Houghton Mifflin Harcourt Publishing Company . Image Credits: ©Kristian
Sekulic/Getty Images
H.O.T. Focus on Higher Order Thinking
24. Explain the Error Suppose a person in the club with 91 members transfers to the
club with 71 members. A student claims that the measures of center and the measures
of spread will all change. Correct the student’s error.
There are 6 elements in the set, so the IQR is the difference between the 5th element and
the 2nd. The only values that are changing are the first and last. This will not affect the IQR.
The median is the average of the 3rd and 4th elements and likewise remains unchanged.
The mean will also remain unchanged because the sum of all the elements doesn’t change.
The range will change from 20 to 18. The standard deviation will also decrease because the
value of both the first and last elements will be closer to the mean.
25. What If? If all the values in a set are increased by 10, does the range also increase by
10? Explain.
No, the highest and lowest values both increase by 10, so their difference, the range, will
stay the same.
26. Communicate Mathematical Ideas Jorge has a data set with the following values:
92, 80, 88, 95, and x. If the median value for this set is 88, what must be true about x?
Explain.
x ≤ 88; for 5 ordered values, the median is the 3rd. Since 95 and 92 > 88,
they must be 4th and 5th, so x must be ≤ the median.
27. Critical Thinking If the value for the median of a set is not found in the data set,
what must be true about the data set? Explain.
The data set must have an even number of values. When a data set has an
odd number of values, the median is always found in the data set.
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Lesson Performance Task
CONNECT VOCABULARY
Some students may not be familiar with the terms
soprano, alto, tenor, and bass. Explain that they
describe types of singing voices, with the soprano
section of a choir singing the highest notes and the
bass section singing the lowest. Ask for volunteers in
the class who sing in a choir to explain or
demonstrate these four vocal ranges.
The table lists the ages of the soprano and bass singers in a town choir. Find the mean, median,
range, interquartile range, and standard deviation for each type of singer in the data set. Interpret
each result. What can you conclude about the ages of the different types of singers?
Age of Soprano
Singers
63
42
28
45
36
48
32
40
57
49
Age of Bass
Singers
32
34
53
35
43
41
29
35
24
34
Soprano Singers
63
+ 42 + 28 + 45 + 36 + 48 + 32 + 40 + 57 + 49
440
________________________________
= ___
= 44
10
10
42
+ 45
87
_____
__
Median age of sopranos:
= 2 = 43.5
2
Mean age of sopranos:
QUESTIONING STRATEGIES
Which of the statistics that you calculated are
measures of center? What does comparing
each of these measures for the sopranos to the same
measures for the basses tell you about the two
groups? Mean and median; comparing tells you
whether the typical age of a soprano is greater or
less than the typical age of a bass.
Range of ages of sopranos: 63 - 28 = 35
Interquartile range of ages of sopranos: IQR = 49 - 36 = 13
Standard deviation =
Bass Singers
―――――――――――――――
――
+ 4 + 256 + 1 + 64 + 16 + 44 + 16 + 169 + 25
1056
_________________________________
= √____
= √――
105.6 ≈ 10.3
√361
10
10
32
+ 34 + 53 + 35 + 43 + 41 + 29 + 35 + 24 + 34
360
________________________________
= ___
= 36
10
10
34
+
35
69
__
Median bass singer age: _____
=
=
34.5
2
2
Mean bass singer age:
Range of bass singer ages: 53 - 24 = 29
Which of the statistics that you calculated are
measures of spread? What does comparing
each of these measures for the sopranos to the same
measures for the basses tell you about the two
groups? Range, interquartile range, and standard
deviation; it tells you whether the ages of the
sopranos are closer together or farther apart than
the ages of the basses.
Interquartile range of bass singer ages: IQR = 41 - 32 = 9
――――――――――――――
――
16 + 4 + 289 + 1 + 49 + 25 + 49 + 1 + 144 + 4
582
Standard deviation = √ ______________________________
= √___
= √――
58.2 = 7.6
10
10
The age of a soprano singer is generally greater than the age of a bass singer.
Module 9
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© Houghton Mifflin Harcourt Publishing Company
The ages of the bass singers are more tightly clustered than the ages of the soprano singers.
Lesson 1
EXTENSION ACTIVITY
A1_MNLESE368170_U4M09L1.indd 388
Have students consider the following scenario. A 17-year-old high school student
and his 55-year-old father both join the bass section of the choir. How would
adding their ages to the data set given in the Lesson Performance Task affect your
conclusions?
Students should find that the mean, median, and interquartile range of the ages in
the bass section would remain the same, but the range would increase to 38, and
the standard deviation would increase to 10.4. The soprano section would still
have the greater typical age, but the ages of the bass singers would be more spread
out than the ages of the sopranos.
7/7/14 1:18 PM
Scoring Rubric
2 points: Student correctly solves the problem and explains his/her reasoning.
1 point: Student shows good understanding of the problem but does not fully
solve or explain his/her reasoning.
0 points: Student does not demonstrate understanding of the problem.
Measures of Center and Spread
388