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Charles’s Gas law: Volume-temperature relationship Charles’s gas law –states that the volume of a fixed mass of gas at a constant pressure varies directly with the Kelvin temperature. Formula: V1 = V2 Kelvin (K) = oC + 273 T1 T2 V1 and T1 are the beginning volume and Kelvin temperature V2 and T2 are the ending volume and Kelvin temperature Charles’s Gas law V1 = V2 T1 T2 A sample of Neon gas occupies a volume of 752 mL at 25oC. What volume will the gas occupy at 50oC? So in order to answer this question you have to first: convert the 25oC and 52oC to Kelvin temp. 25oC + 273 = 298 K and 50oC + 273 = 323 K Then you must set up the equation correctly. Charles’s Gas law V1 = V2 T1 T2 V1 = 752 mL V2 = ? T1 = 298K T2 = 323 K V2 must be on one side of the equation by itself. To do this you have to cross multiply. 752mL = V2 752mL x 323 K = V2 298K 323K 298K V2 = 815 mL Ne Charles’s Gas law 1. a sample of neon gas has a volume of 752 mL at 25oC. What will the volume at 100oC be if the pressure is constant? 2. a sample of nitrogen gas is contained in a piston with a freely moving cylinder. At 0oC, the volume of the gas is 375mL. To what temperature must the gas be heated to occupy a volume of 500mL?