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Charles’s Gas law: Volume-temperature
relationship
 Charles’s gas law –states that the volume of a fixed mass of
gas at a constant pressure varies directly with the Kelvin
temperature.
 Formula:
 V1 = V2
Kelvin (K) = oC + 273
 T1
T2
V1 and T1 are the beginning volume and Kelvin temperature
V2 and T2 are the ending volume and Kelvin temperature
Charles’s Gas law
 V1 = V2
 T1




T2
A sample of Neon gas occupies a volume of 752 mL at 25oC.
What volume will the gas occupy at 50oC?
So in order to answer this question you have to first: convert
the 25oC and 52oC to Kelvin temp.
25oC + 273 = 298 K and 50oC + 273 = 323 K
Then you must set up the equation correctly.
Charles’s Gas law
 V1 = V2
 T1






T2
V1 = 752 mL V2 = ?
T1 = 298K
T2 = 323 K
V2 must be on one side of the equation by itself. To do this
you have to cross multiply.
752mL = V2
752mL x 323 K = V2
298K
323K
298K
V2 = 815 mL Ne
Charles’s Gas law
 1. a sample of neon gas has a volume of 752 mL at 25oC.
What will the volume at 100oC be if the pressure is constant?
 2. a sample of nitrogen gas is contained in a piston with a
freely moving cylinder. At 0oC, the volume of the gas is
375mL. To what temperature must the gas be heated to
occupy a volume of 500mL?