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Chapter 7.3 Warm up Solve each system using substitution: y = 4x -3 y + 5x = 4 y = -2x + 2 Y = 2x + 15 y = 7x – 20 3x -17 = 2y I can manipulate an equation as much as I want as long as I do the same to both sides 5=5 3x = 15 We will eliminate y because the sum of the coefficients is zero 5x – 6y = -32 3x + 6y = 48 I can ELIMINATE a variable by adding my second equation to the first! This strategy is called the elimination method. 2y + x = 7 -2y + 3x = -3 How can I manipulate one of the equations so that I can use the elimination method? 2x + 5y = -22 10x + 3y = 22 -2x + 15y = -32 7x – 5y = 17 3x – 10y = -25 4x + 40y = 20 Challenge 4x – 3y = 11 3x – 5y = -11 I cannot manipulate 3x to equal 4x and I cannot manipulate 3y to equal 5y. HOWEVER, I can manipulate BOTH equations Challenge 6x + 3y = 27 -4x +7y = 27 Elimination Steps Homework • Page 356-357 #’s 1-6, 17-28, 35