Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Number Systems We are used to working with a decimal currency system, based on ‘10’, but this was not always the case. In the UK we used to use ‘imperial currency’ (or pounds, shillings and pence) in which a pound was 240 pence. Many things were based on ‘12’ of something e.g. ‘a dozen eggs’, ‘12 inches in a foot’ and ‘12 pence in a shilling’. Number Systems Sometimes a different way of counting or representing numbers can be useful. One of the most common ‘alternative’ systems in use is binary. In the decimal system, we have ‘column headings’ which are powers of 10. 104 103 102 101 100 Number Systems The binary system has column headings which are powers of 2, as shown. 4 2 16 3 28 2 24 1 22 0 21 Number Systems Can you work out what each of the following numbers is? 24 23 22 21 20 Number 1 0 2 1 0 1 5 1 1 0 1 0 26 1 1 1 1 1 31 Number Systems The binary system is the basis for a ‘magic’ trick (cards on next slide) in which the audience member has to choose a number and then say which cards the number appears on. The ‘magician’ then identifies the number. • How does the magician do it? • What numbers would go on the sixth card and how would the others be amended? A 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 B 2 3 6 7 10 11 14 15 18 19 22 23 26 27 30 31 C 4 5 6 7 12 13 14 15 20 21 22 23 28 29 30 31 D 8 9 10 11 12 13 14 15 24 25 26 27 28 29 30 31 E 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 F Number tricks and proofs There is a simple way to tell if a number is divisible by 9. Simply add the digits of the number together and if the digit sum is divisible by 9, then the number itself is divisible by 9. 19 is not divisible by e.g. 9, so 1567 is also 1567 1+5+6+7 = 19 not divisible by 9 2367 2+3+6+7=18 19 is divisible by 9, so 2367 is also divisible by 9 Number tricks and proofs Can you prove that this ‘rule’ is true for all two digit numbers? What about three digit numbers? Number tricks and proofs Hint If we think of a two digit number such as 67, the 6 is in the ‘tens’ column, so a general two digit number would be: 10 1 A B Number tricks and proofs ‘Indian’ two digit multiplication. On the internet, a video shows an easy way to multiple two digit numbers. The example given is 18 x 14 The next slide shows how to do it. Number tricks and proofs 18 x 14 Take the 4 from the 14 and add it to the 18 22 x 10 = 220 Now multiple the 8 and the 4 8 x 4 = 32 Add them together 220+32 = 252 Number tricks and proofs Can you prove that this always works? Number tricks and proofs There are many ‘tricks’ to help multiply numbers together. One method is to use your fingers to help with the ‘trickier’ numbers such as 7 x 8. It is interesting to try this out and then to see if you can justify why it works. • Number each finger and thumb as shown 8 9 10 7 7 6 8 9 6 10 • Put the 7 and the 8 together to form a ‘bridge’ 9 10 8 7 6 6 • The ‘tens’ digit is given by the number of fingers (and thumbs) making the bridge and under the bridge. In this case there are 5, so ‘50’ • The ‘ones’ digit is found by multiplying the number of fingers above the bridge on one side by the number above it on the other. • • 3x2=6 so with the ‘50’, that’s 56. Teacher notes: Number Systems and puzzles In this edition we look at number systems and number ‘puzzles’. The content is suitable for a wide range of ages and attainment levels as the activities themselves are easily accessible, but the corresponding reasoning and proof activity is often far more challenging. One of the activities also highlights the dangers of simply accepting a method without really testing it or proving that it always works – reasoning and justification are key! Teacher notes: Number Systems Binary card activity. Simply add each of the powers of two (which is the first number of the card) of all the cards the ‘secret’ number appears on. Card F would have all of the numbers from 32 to 63. Card A would have all the odd numbers. Card B would have subsequent pairs of numbers Card C would have subsequent groups of 4 numbers etc. Teacher notes: Number Systems Multiples of 9 Writing a two digit number as ‘AB’ is really writing it as 10A+B When the rule is used, one is checking whether A+B is a multiple of 9 or not. If it is then the whole number is a multiple of 9. Starting with 10A+B, this can be re-written as 9A+(A+B) 9A is clearly a multiple of 9, so if A+B is a multiple of 9 then 10A+B will also be a multiple of 9. Similarly, with a three digit number ‘DEF’ this is really 100D+10E+F This can be re-written as 99D+9E+(D+E+F) Teacher notes: Number Systems ‘Indian’ two digit multiplication The example given is 18 x 14. The elements of this are 10x10, 8x10, 10x4, 8x4 Rearranging it to be (22x10) + (8x4) we essentially have (10+8+4) x 10 + (8x4) which has the same elements. However, what is not acknowledged in the video is that this only works when the ‘tens’ digit is the same in both numbers. Breaking down the elements should help to see why. Exploring this should highlight to students the danger of simply picking up something that ‘looks easy’ from the internet and using it. Teacher notes: finger multiplication Firstly, check what happens with 6 x 7 or with 6 x 6. There is a ‘tens’ to carry from the unit multiplication. It is a little challenging to prove this algebraically, so one way to prove it is by exhaustion. It can, however, be proved as follows: • Consider the general case, a x b a b Teacher notes: finger multiplication a b For the ‘tens’ (on the bridge and below the bridge) On the left hand there are (a-5) fingers. On the right hand there are (b-5) fingers So a+b-10 will go in the ‘tens’ column. Teacher notes: finger multiplication a b For the ‘units’ (above the bridge) On the left hand there are (10-a) fingers. On the right hand there are (10-b) fingers (10-a)(10-b) will go in the ‘units’ column. Teacher notes: finger multiplication (10-a)(10-b) in the ‘units’ column. a+b-10 in the ‘tens’ column, so this has to be multiplied by 10. 10(a+b-10) + (10-a)(10-b) = 10a+10b-100+100-10a-10b+ab= ab a b