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Lecture 11-1 Electric Current Current = charges in motion q dq Magnitude I lim x 0 t dt rate at which net positive charges move across a cross sectional surface I J d A A Units: [I] = C/s = A (ampere) Current is a scalar, signed quantity, whose sign corresponds to the direction of motion of net positive charges by convention J = current density (vector) in A/m² Lecture 11-2 Ohm’s Law Resistance (definition) V R I R I V constant R Ohm’s Law L R A Power dissipation : dU P IV I 2 R V 2 / R dt Lecture 11-3 EMF – Electromotive Force • An EMF device is a charge pump that can maintain a potential difference across two terminals by doing work on the charges when necessary. Examples: battery, fuel cell, electric generator, solar cell, fuel cell, thermopile, … • Converts energy (chemical, mechanical, solar, thermal, …) into electrical energy. Within the EMF device, positive charges are lifted from lower to higher potential. If work dW is required to lift charge dq, dW dq Volt EMF Lecture 11-4 Resistors in Series The current through devices in series is always the same. i R1 R2 i i Req ε ε iR1 iR2 0 iReq 0 Req ( R1 R2 ) For multiple resistors in series: Req R1 R2 R3 ... Same equation for parallel connected capacitors Lecture 11-5 Real Battery = Resistors in Series The current through devices in series is always the same. i Req terminal voltage ε iReq 0 ir iR 0 Req r R internal resistance i Rr , Vb Va ir R Rr Lecture 11-6 Resistors in Parallel i1 i2 i3 Req i1R1 i2 R2 i3R3 Devices in parallel has the same potential drop Generally, 1 1 1 1 or R1 R2 R3 Req Req R1 R2 R3 1 1 Req i Ri Same equation for capacitors connected in serial Lecture 11-7 Kirchhoff’s Rules Kirchhoff’s Rule 1: Loop Rule When any closed loop is traversed completely in a circuit, the algebraic sum of the changes in potential is equal to zero. V i 0 Coulomb force is conservative loop Kirchhoff’s Rule 2: Junction Rule The sum of currents entering any junction in a circuit is equal to the sum of currents leaving that junction. I I i in out j Conservation of charge In and Out branches Assign Ii to each branch Lecture 11-8 Circuit Analysis Tips • Simplify using equivalent resistors • Label currents with arbitary directions •If the calculated current is negative, the real direction is opposite to the one defined by you. • Apply Junction Rule to all the labeled currents. •Useful when having multiple loops in a circuit. • Choose independent loops and define loop direction •Imagine your following the loop and it’s direction to walk around the circuit. • Use Loop Rule for each single loop •If current I direction across a resistor R is the same as the loop direction, potential drop across R is ∆V = −I×R, otherwise, ∆V = I×R •For a device, e.g. battery or capacitor, rely on the direction of the electric field in the device and the loop direction to determine the Potential drop across the device • Solve simultaneous linear equations Lecture 11-9 Loop Example with Two EMF Devices V i 0 loop IR1 IR2 2 Ir2 IR3 1 Ir1 0 I 1 2 R1 R2 R3 r1 r2 If 1 <2, we have I<0 !? This just means the actual current flows reverse to the assumed direction. No problem! Lecture 11-10 Finding Potential and Power in a Circuit Va 0 12 I 1 V But what is I? Must solve for I first! I 12 4 0.5 ( A) 0 1 5 5 1 4 Va 12 0.5 1 11.5(V ) Vb Va I 5 9(V ) P12V The rest? Just means 0 V here supplied by 12 0.5 6(W ) 12V battery PR 0.52 16 4 (W ) dissipated by into 4V battery (charging) resistors P4V 4 0.5 2(W ) Lecture 11-11 Charging a Battery • Positive terminal to positive terminal • Charging EMF > EMF of charged device good battery (12V) Say, R+r1+r2=0.05 (R is for jumper cables). Then, 12 11(V ) I 20( A) 0.05 () battery being charged (11V) P 2 11 20 220 (W ) power into battery 2 • If connected backward, 12 11 I 460 ( A) 0.05 Large amount of gas produced Huge power dissipation in wires Lecture 11-12 Using Kirchhoff’s Laws in Multiple Loop Circuits • Identify nodes and use Junction Rule: i3 i1 i2 • Identify independent loops and use Loop Rule: 1 i1R1 i2 R2 2 i1R1 0 2 i1 i2 R1 i2 R2 2 i1 i2 R1 0 2 i1 i2 R1 i1R1 1 i1R1 i1 i2 R1 0 Only two are independent. Lecture 11-13 Warm-up quiz I1+I2 I2 • What’s the current I1 ? I1 (a). 2.0A (b). 1.0A (c). -2.0A (d). -1.0A (e). Need more information to calculate the value. Lecture 11-14 Answer for the Warm-up quiz I1+I2 I2 • Sketch the diagram • Simplify using equivalent resistors I1 • Label currents with directions • Use Junction Rule in labeling • Choose independent loops • Use Loop Rule Replace by equivalent R=2 first. • Solve simultaneous linear equations 18 12( I1 I 2 ) 6 I1 0 3I1 2 I 2 3 3I 2 21 2 I 2 6 I1 0 6 I1 5I 2 21 I 2 3( A), I1 1( A) Lecture 11-15 Ammeter and Voltmeter Ammeter: an instrument used to measure currents • It must be connected in series. • The internal resistance of an ammeter must be kept as small as possible. Voltmeter: an instrument used to measure potential differences • It must be connected in parallel. • The internal resistance of a voltmeter must be made as large as possible. Lecture 11-16 Galvanometer Inside Ammeter and Voltmeter Galvanometer: a device that detects small currents and indicates its magnitude. Its own resistance Rg is small for not disturbing what is being measured. galvanometer Ammeter: an instrument used to measure currents shunt resistor Voltmeter: an instrument used to measure potential differences galvanometer Lecture 11-17 PHYS241 – Quiz 11A What is the current through R1 ? 30 30 a. 0.575A b. 0.5A c. 0.75A d. 0.33A e. 1.5A 45V R1 R3 R2 30 45V Lecture 11-18 PHYS241 – Quiz11B What is the current through R2 ? 10 10 a. 0.33A b. 2.5A c. 0.75A d. 1.5A e. 0.5A 15V R1 R3 R2 10 15V Lecture 11-19 PHYS241 – Quiz 11C What is the current through R3 ? 20 20 a. 0.375A b. 0.5A c. 0.75A d. 1A e. 1.5A 30V R1 R3 R2 20 30V