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Objectives The student will be able to: MFCR Ch. 4-4 GCF and Factoring by Grouping 1-7-14 1. find the greatest common factor (GCF) for a set of monomials. The Greatest Common Factor (GCF) of 2 or more numbers is the largest number that can divide into all of the numbers. 4) Find the GCF of 42 and 60. 4) Find the GCF of 42 and 60. 42 = 60 = 2 • 3 • 7 2•2•3•5 What prime factors do the numbers have in common? Multiply those numbers. The GCF is 2 • 3 = 6 6 is the largest number that can go into 42 and 60! 5) Find the GCF of 40a2b and 48ab4. 40a2b = 2 • 2 • 2 • 5 • a•a•b 48ab4 = 2 • 2 • 2 • 2 • 3 • a • b • b • b • b What do they have in common? Multiply the factors together. GCF = 8ab What is the GCF of 48 and 64? 1. 2. 3. 4. 2 4 8 16 Objectives The student will be able to: Factor using the greatest common factor (GCF). Review: What is the GCF of 25a2 and 15a? 5a Let’s go one step further… 1) FACTOR 25a2 + 15a. Find the GCF and divide each term 25a2 + 15a = 5a( ___ 5a + ___ 3 ) 25a 2 5a 15a 5a Check your answer by distributing. 2) Factor 18x2 - 12x3. Find the GCF 6x2 Divide each term by the GCF 18x2 - 12x3 = 6x2( ___ 3 - ___ 2x ) 18 x 2 6x2 12 x 3 6 x2 Check your answer by distributing. 3) Factor 2 28a b + 2 56abc . GCF = 28ab Divide each term by the GCF 28a2b + 56abc2 = 28ab ( ___ a + ___ 2c2 ) 28a 2b 28ab 56abc 2 28ab Check your answer by distributing. 28ab(a + 2c2) Factor 1. 2. 3. 4. x(20 – 24y) 2x(10x – 12y) 4(5x2 – 6xy) 4x(5x – 6y) 2 20x - 24xy 5) Factor 28a2 + 21b - 35b2c2 GCF = 7 Divide each term by the GCF 28a2 + 21b - 35b2c2 = 7 ( ___ 4a2 + ___ 3b - ____ 5b2c2 ) 28a 2 7 21b 7 35b 2 c 2 7 Check your answer by distributing. 7(4a2 + 3b – 5b2c2) Factor 1. 2. 3. 4. 2 16xy 2y2(8x – 12z + 20) 4y2(4x – 6z + 10) 8y2(2x - 3z + 5) 8xy2z(2 – 3 + 5) - 2 24y z + 2 40y Objective The student will be able to: use grouping to factor polynomials with four terms. Factoring Chart This chart will help you to determine which method of factoring to use. Type Number of Terms 1. GCF 2. Grouping 2 or more 4 1. Factor 12ac + 21ad + 8bc + 14bd Do you have a GCF for all 4 terms? No Group the first 2 terms and the last 2 terms. (12ac + 21ad) + (8bc + 14bd) Find the GCF of each group. 3a (4c + 7d) + 2b(4c + 7d) The parentheses are the same! (3a + 2b)(4c + 7d) 2. Factor rx + 2ry + kx + 2ky Check for a GCF: None You have 4 terms - try factoring by grouping. (rx + 2ry) + (kx + 2ky) Find the GCF of each group. r(x + 2y) + k(x + 2y) The parentheses are the same! (r + k)(x + 2y) 3. Factor 2 2x - 3xz - 2xy + 3yz Check for a GCF: None Factor by grouping. Keep a + between the groups. (2x2 - 3xz) + (- 2xy + 3yz) Find the GCF of each group. x(2x – 3z) + y(- 2x + 3z) The signs are opposite in the parentheses! Keep-change-change! x(2x - 3x) - y(2x - 3z) (x - y)(2x - 3z) 4. Factor 3 16k - 2 2 4k p - 28kp + 3 7p Check for a GCF: None Factor by grouping. Keep a + between the groups. (16k3 - 4k2p2 ) + (-28kp + 7p3) Find the GCF of each group. 4k2(4k - p2) + 7p(-4k + p2) The signs are opposite in the parentheses! Keep-change-change! 4k2(4k - p2) - 7p(4k - p2) (4k2 - 7p)(4k - p2)