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Thermodynamics: Energy Relationships in Chemistry The Nature of Energy •What is force: •What is work: Thermodynamics: Energy Relationships in Chemistry •Mechanical work w=F •What is energy: * d Thermodynamics: Energy Relationships in Chemistry E= joule = 1kg-m2/s2 4.184 J = 1 cal Thermodynamics: Energy Relationships in Chemistry Sample problem: A 145g baseball is thrown with a speed of 25.0 m/s. Calculate the kinetic energy of the ball in joules and calories Thermodynamics: Energy Relationships in Chemistry System and Surroundings Thermodynamics: Energy Relationships in Chemistry First law of thermodynamics: Thermodynamics: Energy Relationships in Chemistry Thermodynamics: Energy Relationships in Chemistry + E = q + w + Thermodynamics: Energy Relationships in Chemistry + - Thermodynamics: Energy Relationships in Chemistry Thermodynamics: Energy Relationships in Chemistry Sample problem: During the course of a reaction a system loses 550 J of heat to its surroundings. As the gases in the system expand, the piston moves up. The work on the piston by the gas is determined to be 240 J. What is the change in the internal energy of the system, w q •A State Function is… Thermodynamics: Energy Relationships in Chemistry Thermodynamics: Energy Relationships in Chemistry P-V work Thermodynamics: Energy Relationships in Chemistry Let work w = -P V If E = q + w, then E = q + -P V When a reaction is carried out in a constant-volume container ( V = 0) then, E = q v When a reaction is carried out at constant pressure container then, E = q p - P V, or q p = E + P V Thermodynamics: Energy Relationships in Chemistry •Chemical reactions usually occur under conditions where the pressure is held constant, therefore: change in enthalpy: H = E + P V H = q p •Since chemical reactions usually occur under conditions where the volume of the system undergoes little change: H = E • Since H= H final + H initial, then for any type of chemical reaction, H= H products - H reactants Thermodynamics: Energy Relationships in Chemistry Some things you may never have wished to know about enthalpy •Enthalpy is an extensive property CH4(g) + 2O2(g) CO2(g) + 2H2O(g) -75 kJ 0kJ -393.5kJ -242kJ Sample problem: How much heat is produced when 4.50 g of methane gas (CH4) is burned in a constant pressure environment CH4(g) + 2O2(g) CO2(g) + 2H2O(g) (4.50 g CH4) (1mol CH4) (-802 kJ) (16.0 g) (1 mole CH4) = -226 kJ •The enthalpy change for a reaction is equal in magnitude but opposite in sign to H for the reverse reaction •The enthalpy change for a reaction depends on the state of the reactants and products Assume: CH4(g) + 2O2(g) CO2(g) + 2H2O(l) H = -890 kJ •The following process would also produce the same result CH4(g) + 2O2(g) CO2(g) + 2H2O(g) H = -802 kJ 2H2O(g) 2H2O(l) H = -88kJ CH4(g) + 2O2(g) CO2(g) + 2H2O(l) H = -890 kJ •Here is a second reaction pathway which produces the same results Thermodynamics: Energy Relationships in Chemistry Calorimetry: Things are heating up Calorimetry: Measurement of heat flow Molar Heat capacity: The energy required to raise the temperature of 1 mole of a substance by 1C (C = q/T, J/mol-C ) q = n (molar heat capacity)T Specific Heat: The energy required to raise the temperature of 1 gram of a substance by 1C (C = q/T, J/g-C ) q = m sT Thermodynamics: Energy Relationships in Chemistry Sample exercise: The specific heat of Fe2O3 is 0.75 J/g-C. A.) What is the heat capacity of a 2.00 kg brick of Fe2O3. B.) What quantity of heat is required to increase the temperature of 1.75 g of Fe2O3 from 25 C to 380 C . Thermodynamics: Energy Relationships in Chemistry Constant Pressure Calorimetry Sample exercise: 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH are reacted together in a ‘coffee cup’ calorimeter.* The temperature of the resulting solution increased from 21.0 C to 27.5 C . Calculate the enthalpy change of the reaction (the specific heat of water = 4.18 J/g-C). Heat capacity of a metal What is the heat capacity of a 5.05g chunk of an unknown metal. The metal was heated in boiling water and then placed in 50 mL of water in a coffee cup calorimeter at a temperature of 24.5ºC. The highest temperature achieved was 28.9ºC. What is the heat capacity of the metal. Thermodynamics: Energy Relationships in Chemistry Bomb Calorimetry Thermodynamics: Energy Relationships in Chemistry Sample exercise:When 1.00 g of the rocket fuel, hydrazine (N2H2) is burned in a bomb calorimeter, the temperature of the system increases by 3.51 C. If the calorimeter has a heat capacity of 5.510 kJ/ C what is the quantity of heat evolved. What is the heat evolved upon combustion of one mole of N2H4. HESS’S Law: If a reaction is carried out in a series of steps, H for the reaction will be equal to the sum of the enthalpy changes for the individual steps. CH4 (g) + 2O2(g) CO(g) + 2H2O + 1/2 O2 H = -607 kJ CO(g) + 2H2O + 1/2 O2 CO2(g) + 2H2O H = -283 kJ CH4 (g) + 2O2(g) CO2(g) + 2H2O H = -890 kJ Sample exercise: Calculate the H for the reaction: 2C(s) + H2(g) C2H2(g) given the following reactions and their respective enthalpy changes C2H2(g) + 5/2O2 2CO2(g) + H2O(l) H = -1299.6 kJ C(s) + O2(g) CO2(g) H = -393.5 kJ H2(g) + 1/2O2 H2O(l) H = -285.9 kJ Practice Exercise : Calculate the H for the reaction: NO(g) + O(g) NO2(g) given the following reactions and their respective enthalpy changes NO(g) + O3 NO2(g) + O2(g) H = -198.9 kJ O3(g) 3/2O2(g) H = -142.3 kJ O2(g) 2O (g) H = 495.0 kJ NO(g) + O3 NO2(g) + O2(g) 3/2O2(g) O3(g) H = -198.9 kJ H = 142.3 kJ O (g) 1/2O2(g) ) H = -247.5 kJ NO(g) + O(g) NO2(g) H = -304.1 kJ Heats of formation, Hºf • A thermodynamic description of the formation of •compounds from their constituent elements. Heat of vaporization: H for converting liquids to gases Heat of fusion: H for melting solids Heat of combustion: H for combusting a substance in oxygen • A thermodynamic description of the formation of •compounds under standard conditions (1 atm, 298 K •(25 C)) is called the standard heat of formation, Hºf Thermodynamics: Energy Relationships in Chemistry The standard heat of formation for one mole of ethanol is the enthalpy change for the following reaction 2C(graphite) + 3H2(g) + ½ O2(g) C2H5OH H f = -277.7 kJ note: the standard heat of formation of the most stable form of any element is 0. Thermodynamics: Energy Relationships in Chemistry Thermodynamics: Energy Relationships in Chemistry Sample exercise: The quantity of heat produced from one gram of propane (C3H8) is -50.5 kJ/gram. How does this compare with the heat produced from one gram of benzene (C6H6)? C6H6(l) + 15 2 O2 6CO2(g) + 3H2O(l) H rxn = n H f (products) - m H f (reactants)