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Transcript
1
§ 8.4 Quadratic Functions and their
Graphs
2
Graphs of Quadratic Functions
The graph of a quadratic function has the shape
of a parabola. But, what exactly is parabola?
3
Graphs of Quadratic Functions
The graph of a quadratic function has the shape
of a parabola. But, what exactly is parabola?
The curve formed by the set of points in a plane
that are equally distant from both a given
line(called the directrix) and a given point
(called the focus) that is not on the line.
4
Graphing Quadratic Functions
𝑓 π‘₯ = π‘₯2
5
Graphing Quadratic Functions
𝑓 π‘₯ = π‘₯2
We need to choose values for π‘₯ to give us 𝑦
values that will help us plot points on a
coordinate graph. In general, choosing values
around 0 helps. So numbers such as -3,-2,1,0,1,2,3.
6
Quadratics of the Form π‘Žπ‘₯2.
1.) If the coefficient of the term with π‘₯ 2 is a
positive number, then the parabola will open
upwards.
2.) If the coefficient of the term with π‘₯ 2 is a
negative number, then the parabola will open
downwards.
This will be true always no matter what the
coefficients are for the other less degree terms.
7
Quadratics of the Form π‘Žπ‘₯2.
1.) If the coefficient of the term with π‘₯ 2 is a
positive number, then the parabola will open
upwards.
2.) If the coefficient of the term with π‘₯ 2 is a
negative number, then the parabola will open
downwards.
This will be true always no matter what the
coefficients are for the other less degree terms.
E.g.: Looking at 𝑓 π‘₯ = βˆ’2π‘₯ 2 .
8
Graphing Quadratic Functions
𝑓 π‘₯ = π‘₯2
We need to choose values for π‘₯ to give us 𝑦 values
that will help us plot points on a coordinate graph. In
general, choosing values around 0 helps. So
numbers such as -3,-2,-1,0,1,2,3.
Now looking at 𝑔 π‘₯ = π‘₯ 2 βˆ’ 2.
9
Graphing Quadratic Functions
𝑓 π‘₯ = π‘₯2
We need to choose values for π‘₯ to give us 𝑦 values
that will help us plot points on a coordinate graph. In
general, choosing values around 0 helps. So
numbers such as -3,-2,-1,0,1,2,3.
Now looking at 𝑔 π‘₯ = π‘₯ 2 βˆ’ 2.
Now looking at β„Ž π‘₯ = (π‘₯ βˆ’ 2)2 .
What is the difference?
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
10
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
The graph of 𝑠 π‘₯ is just the graph of π‘₯ 2 , but
shifted to the left 3 units and raised 4 units up.
11
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
The graph of 𝑠 π‘₯ is just the graph of π‘₯ 2 , but
shifted to the left 3 units and raised 4 units up.
I like to have the notion of β€œoutside” and β€œinside” of
the parenthesis. The 3 is β€œinside” and the 4 is
β€œoutside”.
12
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
The number that you add/subtract in the β€œinside”
will shift the graph of π‘₯ 2 to the left/right that many
units while the number that you add/subtract in the
β€œoutside” will shift the graph of π‘₯ 2 up/down that
many units.
13
14
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
The quadratic equation here is in what is called
Standard Form. Basically, it is in the form,
𝑓 π‘₯ = π‘Ž(π‘₯ βˆ’ β„Ž)2 +π‘˜
Where our π‘Ž = 1, β„Ž = βˆ’3, π‘˜ = 4.
15
Combinations of Transformations
Let’s look at,
𝑠 π‘₯ = (π‘₯ + 3)2 + 4
The quadratic equation here is in what is called
Standard Form. Basically, it is in the form,
𝑓 π‘₯ = π‘Ž(π‘₯ βˆ’ β„Ž)2 +π‘˜
Where our π‘Ž = 1, β„Ž = βˆ’3, π‘˜ = 4. The vertex of a
parabola is the point with coordinates β„Ž, π‘˜ . It is
basically the lowest/highest point on the parabola.
16
Axis of Symmetry
The Axis of symmetry has the equation,
π‘₯=β„Ž
Where β„Ž comes from the equation
𝑓 π‘₯ = π‘Ž(π‘₯ βˆ’ β„Ž)2 +π‘˜.
It is the vertical line that basically β€œcuts the
parabola is half”.
17
Vertex Formula
To get the π‘₯-coordinate of the vertex point from
the quadratic in the form π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐, it’s just
βˆ’π‘
π‘₯=
2π‘Ž
18
Vertex Formula
To get the π‘₯-coordinate of the vertex point from
the quadratic in the form π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐, it’s just
βˆ’π‘
π‘₯=
2π‘Ž
To get your 𝑦-coordinate, just plug in your result
for π‘₯ back into the quadratic equation.
19
Vertex Formula
To get the π‘₯-coordinate of the vertex point from
the quadratic in the form π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐, it’s just
βˆ’π‘
π‘₯=
2π‘Ž
To get your 𝑦-coordinate, just plug in your result
for π‘₯ back into the quadratic equation.
Let’s graph,
𝑓 π‘₯ = π‘₯ 2 + 6π‘₯ + 5.
20
Number of Real Solutions
 If the graph of a parabola intersects the x-
axis twice, then the quadratic equation has 2
real solutions.
 If the graph of a parabola intersects the xaxis at a single point, then the quadratic
equation has 1 real solution.
 If the graph of a parabola does not intersect
the x-axis at all, then the quadratic equation
has no real solutions.
22
Graphing functions of the form π‘Žπ‘₯2 + 𝑏π‘₯ + 𝑐
by Completing the Square
We will need to use completing the square for a
quadratic function of the form π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 to get it in
the form π‘Ž(π‘₯ βˆ’ β„Ž)2 +π‘˜.
E.g.:
3π‘₯ 2 βˆ’ 12π‘₯ + 8
23
Sketch the graph
𝑓 π‘₯ = βˆ’2π‘₯ 2 + 12π‘₯ βˆ’ 10
1.) Find the coordinates of the vertex.
2.) What is the axis of symmetry?
3.) Is it going to open upward or downward?
4.) Choose values for x around the h value of
the vertex and make a β€œT table” to get points.
24
Sketch the graph
𝑓 π‘₯ = βˆ’2π‘₯ 2 + 12π‘₯ βˆ’ 10
1.) Find the coordinates of the vertex.
2.) What is the axis of symmetry?
3.) Is it going to open upward or downward?
4.) Choose values for x around the h value of
the vertex and make a β€œT table” to get points.
Also, recall, that to find the x-intercepts, set the
quadratic function equal to 0 and to find the yintercept, set the x’s equal to 0.