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FRANCK-HERTZ EXPERIMENT KEN CHENEY 5/22/2006 PICTURES http://www.paccd.cc.ca.us/instadmn/physcidv/physics/teachers/cheney/lab% 20manuals/WEB%20Image%20Folders/Frank-Hertz%20WEB.pdf ABSTRACT The energy to excite mercury atoms will be measured to demonstrate the existence of electron energy levels in atoms and to measure the energy required to excite a ground state electron to the first excited state. The effects of temperature, accelerating voltage, and mean free path will also be investigated. WARNING The oven gets HOT; it doesn’t look hot so check before getting close! HISTORY Bohr (1913) showed that spectral lines could be explained by electron energy levels in an atom. Franck and Hertz (1914) showed that these same energy levels could be detected with particles (electrons). This demonstration considerably increased confidence in the existence of these energy levels, and earned them a Nobel Prize in 1925!theory D:\565340916.doc Ken Cheney 1 EQUIPMENT OUTLINE A glass tube is heated to around 200C to vaporize mercury. An anode (much as in a CRT) emits electrons that are accelerated toward a grid by a voltage that sweeps from zero to a few tens of volts. Most of the electrons will go through the grid. On the far side of the grid from the anode is the cathode. The cathode has a negative voltage relative to the grid so low energy electrons cannot reach the cathode. An oscilloscope is connected to plot the anode-grid (accelerating) voltage on the x-axis and the current reaching the cathode on the y-axis. Frank-Hertz Tube Schematic Oscilloscope y axis A Anode Retarding Voltage Accelerating Voltage _ Grid + + Oscilloscope x axis Hg Gas _ Cathode D:\565340916.doc Ken Cheney 2 THEORY OUTLINE The “Accelerating Voltage” (Cathode to Grid) is greater than the “Retarding Voltage” (Grid to Anode) so if nothing interferes all the electrons from the cathode arrive at the anode and produce a current there. If the electrons moving from the cathode to the grid collide with a mercury atom the collision must be elastic if the kinetic energy of the electron is less than the minimum energy (4.67eV) to excite the mercury atom. Since the electron is much lighter than the mercury atom there is practically no energy exchange. However if the electrons moving from the cathode to the grid have enough energy to excite an electron in the mercury gas the electron can lose 4.67 eV if it excites the lowest energy state. More energy can be lost if it is available, mercury has many energy levels above the lowest energy level. The mean free path for collisions is much shorter than the distance between the cathode and grid. Therefore if the electrons gain enough energy to excite the mercury this will be very likely to occur. At low accelerating voltages the electron may not gain enough energy while approaching the gird to overcome the retarding voltage after passing the grid. These electrons will never reach the anode; they will end up on the grid. As the accelerating voltage is increased from a low value more and more electrons can reach the anode so the anode current increases steadily. But when the excitation voltage is reached suddenly most electrons lose energy to excitations and then never get enough energy to reach the anode. The anode current decrease very rapidly to a low value. As the accelerating voltage continues to increase eventually the electrons that have lost energy can gain enough energy to successfully excite the mercury again, and the anode current decreases again. This process occurs over and over again giving a succession of minimums in the anode current separated by a voltage equivalent to the excitation energy plus a little more. D:\565340916.doc Ken Cheney 3 WARNING The oven gets HOT; it doesn’t look hot so check before getting close! CONNECTIONS: Klinger: KA 6041 Franck-Hertz Oven KA 6045 Franck-Hertz Operating Unit Control Unit M FH Signal A H K Cathode FH Signal y-out 0…12v Ground Symbol UB/10 xout 0…7V PE Ground Symbol Oven Oscilloscope Digital Voltmeters M Use A H K Grid Filament Heater Cathode Voltage Proportional to Anode current Anode Current Y input Volts Ground Ground Ground X input Volts Cathode-Grid Voltage/10 Not used PRELIMINARY ADJUSTMENTS WARNING The oven gets HOT; it doesn’t look hot so check before getting close! From the Klinger instructions: 1. Set the oven to the desired temperature. It takes a long time to stabilize (hours?) so get this going at once. D:\565340916.doc Ken Cheney 4 2. Before turning on the control unit turn the controls for “Heater”, “Acceleration”, and “Amplitude” all the way down. Set “Reverse Bias” to the center position. 3. Set the toggle switch “Man, Ramp/60 Hz” to “Ramp”. This will sweep the accelerating voltage. 4. Oscilloscope a. Connect the x to the "UB/10" (this is the accelerating voltage divided by 10) and the y to the "FH Signal y-out" b. Set the oscilloscope to xy mode so the x signal moves the trace horizontally and the y signal moves the trace vertically c. Adjust the x and y sensitivity for as large a pattern as possible, you will have to change this from time to time. 5. Adjust the heater voltage to approximately 8v. This “heater” is the filament to heat the cathode so it will emit electrons. 6. Adjust the accelerating voltage to 40v-50v. 7. “Amplitude” just changes the output voltage of the FH signal, it does not affect the experiment. 8. The “Reveries Bias” is the retarding voltage. Adjust for the best curve (lots of max and min). 9. Adjust the accelerating voltage to about 80v and tune the other settings for the best curve. ACCURATE READINGS OF THE VOLTAGES OF THE MINIMUM ANODE CURRENT Of course you cannot expect to read an oscilloscope very accurately. Do expand the area of interest as much as possible, check that the knobs are on “calibrate”, remember to multiply the x voltage by 10, use the curser if you have on your oscilloscope, etc. Much more accurate readings can be made with a pair of digital voltmeters. 1. Get a good curve and make a sketch showing your oscilloscope readings for the accelerating voltages of the minimum. 2. Disconnect the oscilloscope and replace it with two digital voltmeters. 3. Find the successive minimum of the FH signal (anode current), at each minimum; record the UB/10 (accelerating voltage) on the other digital voltmeter. D:\565340916.doc Ken Cheney 5 TO DO Check whether the energy differences (minimum to minimum) are close to the minimum energy to excite mercury (4.67 eV). MORE EXTENSIVE ANALYSIS An article by Rapior, Sengstock and Baev in the American Journal of Physics suggests a way to obtain much more information from this experiment. They suggest that after reaching the energy to excite a mercury atom ( Ea ) the electrons accelerate through one free path lambda ( ) before striking and exciting a mercury atom and losing all their kinetic energy. The mean free path is for reasonable conditions much shorter than the distance between the cathode and grid (L) so the extra energy n gained per collision by this means is, for a voltage resulting in n collisions: n n L Ea The total gained for n collisions ( En ) then is: En n( Ea n ) (1) The energy difference from one minimum to the next on the plot (remember these are for different accelerating voltages): E (n ) En En 1 1 (2n 1) Ea L Notice that this difference is not Ea (as we might hope!) or quite linear. (2) We have measured E (n ) and n and we can (being careful not to get burned) measure L. If we multiply (2) out (a form like y=A+Bn) we can do a least squares curve fit to our data and extract Ea and . If there is time data obtained from other temperatures would give more values to average. is a function of the tempter. The higher the temperature the greater the vapor pressure of the mercury, hence the shorter the distance between the mercury atoms. Equations quoted are: D:\565340916.doc Ken Cheney 6 1 kT B N p (3) and: p 8.7 10(9(3110 / T )) Pa (4) Check as much of this is you can! Symbols T p Temperature in K Pressure in Pascal Mean Free Path N Atomic Number Density Cross-section for collision with excitation, about (2.1 0.1) 1019 m2 Boltzman’s constant kB Lowest energy to excite mercury atom Ea Extra energy per collision for an accelerating voltage resulting in n n minimum (collisions) L Distance from cathode to grid Energy gained by electron for the n’th minimum En E (n ) The difference in energy between minimum for n and n-1 collisions n The number of collisions resulting in exciting the atom REFERENCES Gerald Rapior, Klaus Sengstock, and Valery Baev, “American Journal of Physics”, 74 (5), May 2006 FRANCK-HERTZ EXPERIMENT, Klinger Educational Products Corp. D:\565340916.doc Ken Cheney 7