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U Fourier analysis Fourier series: A review Let f (t ) be a real valued periodic function with time period T0 that satisfies following conditions [Dirchelet’s conditions]. Then, it can be expressed in either of the following equivalent forms. a) f (t ) a 0 a n 1 n Where 0 cos n 0 t bn sin n 0 t n 1 2 is called fundamental frequency and n0 , n th harmonic where T0 n - is an integer. b) f (t ) n c e n jn 0t n In (a), the coefficients ( a i and bi ) are real valued, while in (b), coefficient cn may be complex. Both forms (a) and (b) are equivalent. (b) can be obtained from (a) by following substitutions. e jn0t e jn0t cos n 0 t 2 jn0t e _ e jn0t sin n0t 2j Thus, a n , bn and cn are related as follows. c0 a 0 an jbn 2 an jbn 2 cn c n n0 In other words, c n c * n , the usage of exponential form also introduces the concept of negative frequency. It can be interpreted in the following way. e jn0t (n 0) represents a phasor of unit magnitude rotating in anticlockwise direction at speed of n0 rad/s. e jn0t represents a phasor of unit magnitude rotating in clockwise direction at speed of n0 rad/s. The coefficients a n , bn and cn can be computed using the following expressions. 2 T0 an 0 2 2 T0 T0 1 2 1 = 0 bn = T0 0 0 f (t ) cos n 0 t dt f ( 0 t ) cos n 0 t d ( 0 t ) f (t ) sin n0 t dt f ( 0 t ) sin n 0 t d ( 0 t ) T 1 1 a0 f (t ) dt T0 2 2 f ( t ) d t 0 0 0 T 1 cn f (t ) e jn0t dt T0 1 2 2 f (t ) e jn0t d0 t 0 Since, many of the voltage and current phasor estimation methods are based upon Least square estimation, it is a worthwhile intellectual exercise to show that Fourier series truncated at some ‘n’ can be interpreted through Least square estimation theory. We define the concept of mean square error (MSE). MSE is defined as 2 r 1 2 MSE f ( t ) ( t ) i i dt t 2 t1 t1 i 1 t The interval t 2 t1 for periodic function should be time period T0 , while i (t ) should be sine/cosine function (or) exponential function of the Fourier series. Our job is to find the coefficient i ' s so as to minimize the mean square error. Thus, the optimization problem is given by min MSE Consider f (t ) approximated by n functions i as follows. f (t ) 11 (t ) 22 (t ) rr (t ) (1) In truncated Fourier series, i (t ) belong to the set 1, cos m0 t , sin m0 t ; m integer}. To evaluate the quality of approximation, Now, 2 t 1 2 f (t ) 11 (t ) 22 (t ) rr (t ) dt MSE t 2 t1 t1 2 2 2 2 2 2 2 1 2 [ f (t ) 1 1 (t ) 2 2 (t ) r r (t ) t 2 t1 t1 21 f (t )1 (t ) 2 2 f (t )2 (t ) 2 r f (t )r (t )] dt t t 1 r r 2 j ii (t ) j (t ) dt t 2 t1 j 1 i 1 t1 i j (2) Now, if we choose i (t ) to be either cos n 0 t or sin n0 t from the trigonometric form of Fourier series, then the expression for the MSE simplifies drastically. It can be verified that with i (t ) cos n0 t and j (t ) cos m 0 t (m n) T0 (t ) i j (t ) dt 0 T0 = cos n0 t cos m0 t dt 0 T 1 0 = [cos n m 0 t cos n m 0 t ] dt 20 = 0; This, infact is analogous to the statement that we cannot have non-zero average power exchange over a time-interval (T0 ) if the voltages and currents belong to different frequencies of the harmonic spectrum. Similarly, with i cos n0 t and j sin m 0 t , it can be verified that T0 (t ) i 0 T0 j (t ) dt = cos n0 t sin m0 t dt 0 T0 = 1 [sin n m 0t sin n m 0t ] dt = 0; 2 0 (3) Equation (3) holds true even when n m ; when n m ; the remarks made earlier on interaction of harmonic frequencies apply. When n m , we have the analogy of interaction between voltage and current phasors separated by 90 , which leads to zero average power. The concept of zero average power interaction at (1) sines and cosines harmonic at different frequencies and (2) sines and cosines at same frequency can be generalized by the concept of orthogonal functions. Orthogonal functions: A set of complex valued functions i (t ), j (t ), t [a, b] , are said to be orthogonal if b (t ) i * j (t ) 0 i j a The definition obviously applies to real valued functions where in *j i . Clearly, the functions used in Fourier series (both in trigonometric and complex exponential form) are orthogonal. Many more set of orthogonal functions like Walsh, Harr etc and corresponding approximate series can be found in the literature of signal processing. They also have applications in power quality. However, for our use, Fourier series suffices. From the discussion so far, we conclude that in case of Fourier series over a time period T0 , the second term in (2) vanishes. Hence 2 2 2 2 2 2 2 1 0 [ f (t ) 1 1 (t ) 2 2 (t ) n n (t ) MSE T0 0 21 f (t )1 (t ) 2 2 f (t )2 (t ) 2 n f (t )n (t )] dt T Now, for dc signal (n 0, cos n0 t ) T 1 0 2 (t ) dt 1 T0 0 Also, for (t ) to be sin m0 t , or cos n 0 t ; T 1 0 1 cos 2n0 t 1 0 2 dt = 1 sin n0 t dt = 2 T0 0 2 T0 0 T (4) Hence, T 12 22 n2 1 2 MSE f (t ) dt T0 0 2 2 1 T0 1 T0 T 0 T0 0 2 f (t )1 (t ) dt n T0 T0 f (t ) n (t ) dt 0 2 2 T0 2 2 f 2 (t ) dt 1 1 f (t ) 1 (t ) dt n n T0 0 T0 2 2 T0 f (t ) 0 n (t ) dt At the minimum, the partial derivative of MSE with variable i should be zero. Now, MSE 2 0 i i T0 i 2 T0 T0 f (t ) (t ) dt 0 i 0 T0 f (t ) (t ) dt i 0 Thus, when we substitute i (t ) cos n0 t , we get coefficient a n , similarly by substituting i (t ) sin n0 t , we get coefficient bn Finally, for dc signal, which is defined by i (t ) 1 2 0 T0 T0 f (t ) dt 0 These coefficients infact are nothing but the coefficients of Fourier series. This leads us to a very important conceptual result viz. coefficients in Fourier series minimize the MSE. This establishes the linkage between Fourier series and Least square methods. Similar series can be developed for other set of orthogonal functions. [See Q:2] U Review Questions: 1) For the square periodic wave form as shown in Fig-1 4 n odd Show that C n n n even 0 Interpret you answers in terms of a n and bn . 2) A class of function known as Walsh function are defined as follows 0 t 1, 0 t 1 1 1 0t 2 1 t 1 1 t 1 2 1 3 1 0 t , t 1 1 4 4 2 t 1 1 t 1 4 1 1 3 1 0t , t 4 2 4 22 t 1 1 3 1 t , t 1 4 2 4 1 k 2 t 0 t m 2 m( 2k11) t 1 (1) k 1 m( k ) 2t 1 t 1 2 m 1, 2, 3,... k 1, 2,....,2 m 1 1 mk 2t 0t 2 m( 2k1) t 1 (1) k m( k ) 2t 1 t 1 2 a) Plot the functions b) Show that they are orthogonal c) What advantages can they have in DSP 3) Function n d Sin ( 0 ) A 2 Ans : Fn d t n 0 d 2 4) State Dirchelet’s conditions