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Chapter 24 - Capacitance I. Introduction: Consider two conductors connected to the terminals of a battery. The battery will supply an equal amount of charge to each of the conductors, but the charge on each of the conductors will have opposite signs. The equation that gives the potential difference in terms of the b electric field Va Vb E d l can be used to derive expressions that relate the potential difference a between two conductors to the charge on the conductors. A. Two conducting parallel plates separated by a distance d with charges +Q and -Q. The potential difference between the plates (from one plate to the other) is area, A +Q Qd Va Vb V Ed d A o o B. d -Q Two conducting concentric spheres of radii a and b. The potential difference between the spheres is Va Vb V Q 1 1 4 o a b b +Q a -Q C. Coaxial cable (two concentric conducting cylinders) of length L. The inside conductor has a radius a with charge + and the inside surface of the outside conductor is b with charge -. Va Vb V b Q b ln ln 2 o a 2 oL a b +Q a -Q 24-1 D. Note that in all cases that the charge Q is proportional to the potential difference or voltage, V, and that the proportionality constant only depends on constants and the geometry (arrangement and size) of the charged conductors, that is, Q V. Because of this, a constant C, can be introduced such that Q = CV. E. This constant C is defined as the capacitance of the system and depends on the geometry of the system. Electrically, the capacitance, C, represents F. For units: C Q Coulomb V volt farad F . Common values of capacitance vary from microfarads, F (10-6 farads) to picofarads, pF (10-12 farads). II. What are the capacitances for the above arrangements of conductors? A. Two parallel plates: Example: There are electrical devices that are designed to store energy in this fashion. These devices are referred to a "capacitors." To get an idea of the magnitude of the unit Farad, find how large a parallel plate capacitor must be in order to have a capacitance of one Farad (1.0 F). Let the distance between the plates to be 0.1 mm – approximately the thickness of a sheet of paper. B. Concentric spheres of radii a and b: C. Coaxial cable – In this case, the coaxial cable can have different lengths. Because of this we find the capacitance per unit length: 24-2 III. Capacitors in Electrical Circuits A. Real capacitors – some examples B. The circuit diagram of a capacitor C. You can "charge" a capacitor by connecting the capacitor to a battery (power supply). Remember that in the electrostatic situation the wires (conductors) are equipotentials. D. Combinations of Capacitors 1. Capacitors in Parallel: Find one capacitor, Ceq , that is equivalent to the capacitors in parallel (does the same job as the capacitors in + parallel). "top to top, bottom to bottom" "left to left, right to right" voltage V "The voltage is the same across all capacitors in parallel." 24-3 _ C1 C2 C3 2. Capacitors in Series: Find the equivalent capacitance, Ceq. + "one after another" - similar to a train engine pulling its cars C1 "The charge is the same for all capacitors connected in series. voltage V C2 C3 _ Special case: Two capacitors in series: 3. Parallel and series combinations: Example 1: Find the charge on each capacitor and the voltage across each capacitor. 2 F 3 F 4 F 12 v + _ 24-4 Example 2: Find the equivalent capacitance between points A and B. 4 F 6 F 3 F 8 F A B 2 F Example 3: Find the equivalent capacitance between points A and B. 3 F 6 F A 2 F B 24-5 8 F 4 F Example 4: A 3 F and a 6 F capacitor are connected in parallel and are charged by a 12 volt battery, as shown. After the capacitors are charged, the battery is then disconnected from the circuit. The capacitors are then disconnected from each other and reconnected after the 6 F capacitor is inverted. Find the charge on each capacitor and the voltage across each. + A B 12 v 3 F C D 6 F A B D C _ Example 5: Place the two capacitors in example 4 in series and connect the 12 v power supply. After the capacitors are charged, disconnect the capacitors and reconnect them so that the A and C leads are together and the B and D leads are together. + A B 3 F C D 6 F 12 v _ 24-6 IV. Energy stored in the capacitor. A. When a capacitor is being "charged" by a battery (or power supply), work is done by the battery to move charge from one plate of the capacitor to the other plate. As the capacitor is being charged, we can say that the capacitor is storing energy (What kind of energy?). Find the stored energy. Consider a capacitor being charged by a battery. After a time t elapses, the voltage across the capacitor is V and an amount of charge q has accumulated (so far) on the plates of the capacitor. To move an additional amount of charge dq from one plate to the other, the battery must do an amount of work dW, where dW = (dq)V. (Remember from before that Wab Ua Ub qVa Vb , or W = qV is the work done moving a charge q through a voltage V.) dq + +q V -q - V at time t, before being fully charged B. Where is the energy stored? (What was different after the capacitor was charged?) C. What is the density of the energy stored in the electric field, or what is the energy density, uE , in Joules/m3 ? 24-7 Example: How much energy is stored in the electric field between two concentric conducting spheres. The inner sphere has a charge +Q and radius R1, and the outer sphere has a charge –Q and inner radius R2. (Remember that energy density has units of joules/m3, so if energy density is multiplied by a volume you get energy.) -Q R2 +Q R1 V. How will dielectrics (insulators) affect a capacitor? A. mechanically - simpler to construct capacitor B. dielectrics change the capacitance 1. Polar and nonpolar atoms and molecules in electric fields a. polar b. nonpolar 24-8 C. Compare parallel plate capacitors - one without a dielectric and one with a dielectric. Assume that the plates of the capacitors have the same amount of charge. (The diagram is not to scale. The area of the plates is very large and the distance between the plates is small.) Compare charges Q, electric fields E, voltages V, and capacitances C. without dielectric with dielectric + + + + + + + + + + + +o +Qo +Qo + + + + + + + + + + + +o -Qi _ _ _ _ _ _ -i d -Qo _ _ _ _ _ _ _ _ _ _ _ -o + +Qi -Qo Without Dielectric _ + _ _ + _ _ + _ With Dielectric _ + _ _ + _ _ -o +i Relative Values Electric Field Potential Difference Capacitance 1. To relate the effectiveness of a dielectric, we define a constant called the dielectric constant (kappa) as the ratio of the capacitance with the dielectric to the capacitance without the dielectric: C , Co C = Co or Some values -- vacuum: = 1, glass: = 5 to 10, mica: = 3 to 6, strontium titinate =233 Related quantity: dielectric strength - for air = 3 x 106 V/m, for strontium titinate = 14 x 106 V/m 2. For a parallel plate capacitor: 24-9 D. 3. Note how the capacitance, voltage, and electric field are related to each other in a capacitor with a dielectric and without a dielectric: 4. How is the charge on the conducting plates of the capacitor, Qo , related to the induced charge on the surfaces of the dielectric, Qi ? Examples: For examples 1 and 2, assume that you have a parallel capacitor whose plates have an area of 10 cm2 and are separated by a distance of 0.05 mm. In the first case nothing is between the plates and in the second case a dielectric with dielectric constant = 5 completely fills the space between the plates of the capacitor. 1. Suppose that the capacitor is first connected to a battery, receives a charge of 2.00 x 10 -9 C. and is then disconnected from the battery maintaining the charge. Find the following: with nothing between the plates the capacitance of the capacitor the voltage across the capacitor the electric field between the plates 24-10 with the dielectric between the plates the energy stored in the capacitor the energy density between the plates 2. Suppose the capacito5r is connected to a 6.00 volt battery, and the battery remains connected. Find the following: with nothing between the plates the capacitance of the capacitor the charge on the plates of the capacitor the electric field between the plates the energy stored in the capacitor the energy density between the plates 24-11 with the dielectric between the plates 3. 4. A parallel plate capacitor is constructed so that a dielectric fills only part of the space between the plates. The area of the plates is A, and the thickness of the dielectric is x. Find the capacitance of this capacitor. area A d-x x Find the capacitance of the capacitor shown. The total area of the plate is A. The area covered by each of the dielectrics A1 and A2. A1 A2 1 5. Find the capacitance of the capacitor shown. A/2 d A/2 2 1 3 24-12 2 d/2 d/2