Exercise 4
... 5. Thirty percent of all customers who enter a store will make a purchase. Suppose that 6 customers enter the store and that these customers make independent purchase decisions. (a) Let X= the number of the six customers who will make a purchase. Write the binomial formula for this situation. (b) Wh ...
... 5. Thirty percent of all customers who enter a store will make a purchase. Suppose that 6 customers enter the store and that these customers make independent purchase decisions. (a) Let X= the number of the six customers who will make a purchase. Write the binomial formula for this situation. (b) Wh ...
Chapter 1
... • Bayes’ formula is relevant if we know that E occurred and we want to know which of the F’s occurred. P Fj | E ...
... • Bayes’ formula is relevant if we know that E occurred and we want to know which of the F’s occurred. P Fj | E ...
Unit 4 Summary : Probability (Part 1)
... 5. How to modify a sample space to an altered sample space for conditional probability: P(rolling 3 | rolling odd) --> the sample space was originally {1, 2, 3, 4, 5, 6} but the alterned sample space is {1, 3, 5}. 6. How to use tree diagrams to solve probabilities. 7. How to use the "And" formula to ...
... 5. How to modify a sample space to an altered sample space for conditional probability: P(rolling 3 | rolling odd) --> the sample space was originally {1, 2, 3, 4, 5, 6} but the alterned sample space is {1, 3, 5}. 6. How to use tree diagrams to solve probabilities. 7. How to use the "And" formula to ...
Probability 1
... An experiment consists of two steps: first flipping two coins and then if the coins both land heads up a die is rolled otherwise a coin flipped. (Outcomes are listed like HH3 or THH.) ...
... An experiment consists of two steps: first flipping two coins and then if the coins both land heads up a die is rolled otherwise a coin flipped. (Outcomes are listed like HH3 or THH.) ...
Chapter 6: Probability
... 1. What is probability? 2. Do “independent” and “disjoint” mean the same thing? 3. How can probability rules be used to determine the probability of an outcome? Knowledge: You should be able to define, illustrate, or calculate the following: ...
... 1. What is probability? 2. Do “independent” and “disjoint” mean the same thing? 3. How can probability rules be used to determine the probability of an outcome? Knowledge: You should be able to define, illustrate, or calculate the following: ...
Probability theory – Syllabus 2014
... The course is intended for the 1st year students of the PhD programme in Economics. The purposes of this course are: (i) to explain, at an intermediate level, the basis of probability theory and some of its more relevant theoretical features; (ii) to explore those aspects of the theory most used in ...
... The course is intended for the 1st year students of the PhD programme in Economics. The purposes of this course are: (i) to explain, at an intermediate level, the basis of probability theory and some of its more relevant theoretical features; (ii) to explore those aspects of the theory most used in ...
NAME - Net Start Class
... diagram showing the possible outcomes. What is the probability of getting at least 2 tails? ...
... diagram showing the possible outcomes. What is the probability of getting at least 2 tails? ...
SOLUTIONS to EXAM 3
... (1) A random variable X has E(X) = −4 and E(X 2 ) = 30. Let Y = −3X + 7. Compute: (a) V (X) = E(X 2 ) − E(X)2 = 14 (b) V (Y ) = (−3)2 V (X) = 126 (c) E((X + 5)2 ) = E(X 2 + 10X + 25) = E(X 2 ) + 10E(X) + 25 = 15 (d) E(Y 2 ) = V (Y ) + E(Y )2 = 126 + (−3E(X) + 7)2 = 487 (2) A deck has only face cards ...
... (1) A random variable X has E(X) = −4 and E(X 2 ) = 30. Let Y = −3X + 7. Compute: (a) V (X) = E(X 2 ) − E(X)2 = 14 (b) V (Y ) = (−3)2 V (X) = 126 (c) E((X + 5)2 ) = E(X 2 + 10X + 25) = E(X 2 ) + 10E(X) + 25 = 15 (d) E(Y 2 ) = V (Y ) + E(Y )2 = 126 + (−3E(X) + 7)2 = 487 (2) A deck has only face cards ...
