CONForces
... STRAIGHT LINE unless acted upon by an outside force. ◦ Simply put…objects like to keep doing what they’re doing. ...
... STRAIGHT LINE unless acted upon by an outside force. ◦ Simply put…objects like to keep doing what they’re doing. ...
109 solar system prt 1.p65.p65
... Show all working, including any rearranging of equations. 1. What is the cause of the centripetal force keeping planets in their orbits? Which direction does it act? 2. Describe and explain what would happen to any object moving in a circular path if the centripetal force were removed. 3. The radius ...
... Show all working, including any rearranging of equations. 1. What is the cause of the centripetal force keeping planets in their orbits? Which direction does it act? 2. Describe and explain what would happen to any object moving in a circular path if the centripetal force were removed. 3. The radius ...
Inclined Planes:
... gravitational potential energy of mgh.The expression really gives a difference in potential energy between the value that the object has at the Earth’s surface and the value it has at height h. If we choose a point where PE = 0, ie. infinity, this is where the gravitational field strength of any obj ...
... gravitational potential energy of mgh.The expression really gives a difference in potential energy between the value that the object has at the Earth’s surface and the value it has at height h. If we choose a point where PE = 0, ie. infinity, this is where the gravitational field strength of any obj ...
Document
... its rate of change of momentum. Notes: • We have defined the newton (N) so that ∑F = ∆p/∆t • Since p = mv, ∑F = ∆mv/∆t we have two cases (a) m constant: ∑F = m∆v/∆t = ma (b) v constant: ∑F = v∆m/∆t ...
... its rate of change of momentum. Notes: • We have defined the newton (N) so that ∑F = ∆p/∆t • Since p = mv, ∑F = ∆mv/∆t we have two cases (a) m constant: ∑F = m∆v/∆t = ma (b) v constant: ∑F = v∆m/∆t ...
File
... • Consider the flying motion of birds. A bird flies by use of its wings. The wings of a bird push air downwards. In turn, the air reacts by pushing the bird upwards. • The size of the force on the air equals the size of the force on the bird; the direction of the force on the air (downwards) is opp ...
... • Consider the flying motion of birds. A bird flies by use of its wings. The wings of a bird push air downwards. In turn, the air reacts by pushing the bird upwards. • The size of the force on the air equals the size of the force on the bird; the direction of the force on the air (downwards) is opp ...
Powerpoint
... for the last leg of the race: • Drive East at 50 MPH for 30 minutes and • Then go 30 degrees East of North for 45 minutes at 60 MPH 1. What would be your average speed from the pit stop to the finish line? 2. What would be the magnitude and direction of your average velocity during this time? 3. Fin ...
... for the last leg of the race: • Drive East at 50 MPH for 30 minutes and • Then go 30 degrees East of North for 45 minutes at 60 MPH 1. What would be your average speed from the pit stop to the finish line? 2. What would be the magnitude and direction of your average velocity during this time? 3. Fin ...
Newton`s Laws PPT
... The size of the force on the air equals the size of the force on the bird; the direction of the force on the air (downwards) is opposite the direction of the force on the bird (upwards). Action-reaction force pairs make it possible for birds to fly. ...
... The size of the force on the air equals the size of the force on the bird; the direction of the force on the air (downwards) is opposite the direction of the force on the bird (upwards). Action-reaction force pairs make it possible for birds to fly. ...
Pushes and Pulls Content 3. Daily examples of force
... • When the cue hits the ball, the ball also “hits” the cue. Action: the man pushes on the wall. Reaction: the wall pushes on the man. ...
... • When the cue hits the ball, the ball also “hits” the cue. Action: the man pushes on the wall. Reaction: the wall pushes on the man. ...
Energy unit review solutions.
... 10. Jane, whose mass is 50.0 kg, needs to swing across a river (having width D) filled with man-‐‑eating crocodiles to save Tarzan from danger. She must swing into a wind exerting constant horizontal force F, on a vine having length L and initially ...
... 10. Jane, whose mass is 50.0 kg, needs to swing across a river (having width D) filled with man-‐‑eating crocodiles to save Tarzan from danger. She must swing into a wind exerting constant horizontal force F, on a vine having length L and initially ...
Chapter 5 - TTU Physics
... The forces are applied perpendicularly to each other The resultant (or net) force is the hypotenuse Forces are vectors, so you must use the rules for vector addition to find the net force acting on an object ...
... The forces are applied perpendicularly to each other The resultant (or net) force is the hypotenuse Forces are vectors, so you must use the rules for vector addition to find the net force acting on an object ...
Chapter 10: Dynamics of rotational motion
... • Torque: Is it a force? • torques rotational motion (just as forces linear accelerations) • combination of translation and rotation: rolling objects • Calculation of work done by a torque • Angular momentum conservation • rotational dynamics and angular momentum: they are related ...
... • Torque: Is it a force? • torques rotational motion (just as forces linear accelerations) • combination of translation and rotation: rolling objects • Calculation of work done by a torque • Angular momentum conservation • rotational dynamics and angular momentum: they are related ...
Chapter 5 PPT
... The forces are applied perpendicularly to each other The resultant (or net) force is the hypotenuse Forces are vectors, so you must use the rules for vector addition to find the net force acting on an object ...
... The forces are applied perpendicularly to each other The resultant (or net) force is the hypotenuse Forces are vectors, so you must use the rules for vector addition to find the net force acting on an object ...
Lab 9: Uniform Circular Motion
... where v is the speed of the object and r is the radius of the circle in which it moves. The centripetal force that produces this acceleration is determined from Newton’s 2 nd law of motion: ...
... where v is the speed of the object and r is the radius of the circle in which it moves. The centripetal force that produces this acceleration is determined from Newton’s 2 nd law of motion: ...
Motion - Evangel University
... • Graphical representation using vectors: length = magnitude; arrowheads = direction ...
... • Graphical representation using vectors: length = magnitude; arrowheads = direction ...