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How to quantize infinitesimally-braided symmetric monoidal categories
... for this to be a ring containing Q. In general our algebras, etc., will be infinite-dimensional, but a representation of some algebraic structure will always mean a finite-dimensional representation (when K is not a field, it should be a finitely generated (topologically) free K-module). So Vect wil ...
... for this to be a ring containing Q. In general our algebras, etc., will be infinite-dimensional, but a representation of some algebraic structure will always mean a finite-dimensional representation (when K is not a field, it should be a finitely generated (topologically) free K-module). So Vect wil ...
Chapter 4 Basics of Classical Lie Groups: The Exponential Map, Lie
... Remark: If E is a Hermitian space, the proof of Lemma 4.1.3 can be easily adapted to prove that there is an orthonormal basis (u1, . . . , un) with respect to which the matrix of f is upper triangular. In terms of matrices, this means that there is a unitary matrix U and an upper triangular matrix T ...
... Remark: If E is a Hermitian space, the proof of Lemma 4.1.3 can be easily adapted to prove that there is an orthonormal basis (u1, . . . , un) with respect to which the matrix of f is upper triangular. In terms of matrices, this means that there is a unitary matrix U and an upper triangular matrix T ...
SYMPLECTIC QUOTIENTS: MOMENT MAPS, SYMPLECTIC
... (2) If K is compact, then any action of K on X is proper. Theorem 1.3. Let K be a Lie group acting freely and properly on a smooth manifold X; then there is a unique structure of a smooth manifold on X/K such that π : X → X/K is a submersion. Furthermore, π : X → X/K is a principal K-bundle. Proof. ...
... (2) If K is compact, then any action of K on X is proper. Theorem 1.3. Let K be a Lie group acting freely and properly on a smooth manifold X; then there is a unique structure of a smooth manifold on X/K such that π : X → X/K is a submersion. Furthermore, π : X → X/K is a principal K-bundle. Proof. ...
Normal Subgroups The following definition applies. Definition B.2: A
... Let H be the subset of G consisting of matrices whose upper-right entry is zero; that is, matrices of the form ...
... Let H be the subset of G consisting of matrices whose upper-right entry is zero; that is, matrices of the form ...
1 The Lie Algebra of a Lie Group
... This generates a flow where φt : U (1) → U (1) is rotation by the angle is the same as multiplication by etv ∈ U (1). So ...
... This generates a flow where φt : U (1) → U (1) is rotation by the angle is the same as multiplication by etv ∈ U (1). So ...
Symmetric Spaces
... Definition 8 (symmetric pair) Let G be a connected Lie group and K a closed subgroup. The pair (G, K) is called a symmetric pair if there exists an involutive analytic automorphism σ of G s.t. (Gσ )0 ⊂ K ⊂ Gσ , where Gσ is the set of fixed points of σ in G and (Gσ )0 is the identity component of Gσ . ...
... Definition 8 (symmetric pair) Let G be a connected Lie group and K a closed subgroup. The pair (G, K) is called a symmetric pair if there exists an involutive analytic automorphism σ of G s.t. (Gσ )0 ⊂ K ⊂ Gσ , where Gσ is the set of fixed points of σ in G and (Gσ )0 is the identity component of Gσ . ...
Chapter 3: Roots of Unity Given a positive integer n, a complex
... property that ω k is in H. Write m = n/k. Then the group Cm of all mth roots of unity consisting of powers of ω k , which is an element in H. Thus Cm is a subset of H. Conversely, if ω ℓ is an element in H, then we may recycle an argument to show that ℓ is divisible by k. Now H = Cm is more or less ...
... property that ω k is in H. Write m = n/k. Then the group Cm of all mth roots of unity consisting of powers of ω k , which is an element in H. Thus Cm is a subset of H. Conversely, if ω ℓ is an element in H, then we may recycle an argument to show that ℓ is divisible by k. Now H = Cm is more or less ...
Using the Quadratic Formula to Find Complex Roots (Including
... Using the Quadratic Formula to Find Complex Roots (Including Complex Conjugates) ...
... Using the Quadratic Formula to Find Complex Roots (Including Complex Conjugates) ...
Full text
... The understanding of the self-similar structure of the symbolic system and its geometric relations on the torus and the circle, using the semigroup, plays an important role in the construction of the geodesic lamination, given in [8], and also in the proofs of other dynamical properties of these sys ...
... The understanding of the self-similar structure of the symbolic system and its geometric relations on the torus and the circle, using the semigroup, plays an important role in the construction of the geodesic lamination, given in [8], and also in the proofs of other dynamical properties of these sys ...
MA 723: Theory of Matrices with Applications Homework 2
... 1. Prove that rank (A) is equal to the number of nonzero eigenvalues. 2. Prove that rank (A) = rank (Ak ) for all k = 1, 2, . . . 3. Prove that A is nilpotent iff A = 0. 4. If trace (A) = 0 then rank (A) 6= 1. Let A = XΛX −1 We prove each item individually. 1. The rank is invariant to similarity. Th ...
... 1. Prove that rank (A) is equal to the number of nonzero eigenvalues. 2. Prove that rank (A) = rank (Ak ) for all k = 1, 2, . . . 3. Prove that A is nilpotent iff A = 0. 4. If trace (A) = 0 then rank (A) 6= 1. Let A = XΛX −1 We prove each item individually. 1. The rank is invariant to similarity. Th ...
Universal Enveloping Algebras (and
... Note that the universal enveloping algebra construction is not inverse to the formation of AL : if we start with an associative algebra A, then UAL ! A. The beauty of this construction is that is preserves the representation theory: the representations of g are in bijection with modules over Ug , an ...
... Note that the universal enveloping algebra construction is not inverse to the formation of AL : if we start with an associative algebra A, then UAL ! A. The beauty of this construction is that is preserves the representation theory: the representations of g are in bijection with modules over Ug , an ...
GLOBALIZING LOCALLY COMPACT LOCAL GROUPS 1
... We need the following consequence of Theorem 3.1: Corollary 3.3. Suppose there exists a surjective strong morphism G → L|V where L is a Lie group and V a symmetric open neighborhood of the identity in L. Then G is locally isomorphic to a topological group. Proof. Shrinking V and restricting G accord ...
... We need the following consequence of Theorem 3.1: Corollary 3.3. Suppose there exists a surjective strong morphism G → L|V where L is a Lie group and V a symmetric open neighborhood of the identity in L. Then G is locally isomorphic to a topological group. Proof. Shrinking V and restricting G accord ...