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How to quantize infinitesimally-braided symmetric monoidal categories
How to quantize infinitesimally-braided symmetric monoidal categories

... for this to be a ring containing Q. In general our algebras, etc., will be infinite-dimensional, but a representation of some algebraic structure will always mean a finite-dimensional representation (when K is not a field, it should be a finitely generated (topologically) free K-module). So Vect wil ...
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... Remark: If E is a Hermitian space, the proof of Lemma 4.1.3 can be easily adapted to prove that there is an orthonormal basis (u1, . . . , un) with respect to which the matrix of f is upper triangular. In terms of matrices, this means that there is a unitary matrix U and an upper triangular matrix T ...
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SYMPLECTIC QUOTIENTS: MOMENT MAPS, SYMPLECTIC

... (2) If K is compact, then any action of K on X is proper. Theorem 1.3. Let K be a Lie group acting freely and properly on a smooth manifold X; then there is a unique structure of a smooth manifold on X/K such that π : X → X/K is a submersion. Furthermore, π : X → X/K is a principal K-bundle. Proof. ...
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... Definition 8 (symmetric pair) Let G be a connected Lie group and K a closed subgroup. The pair (G, K) is called a symmetric pair if there exists an involutive analytic automorphism σ of G s.t. (Gσ )0 ⊂ K ⊂ Gσ , where Gσ is the set of fixed points of σ in G and (Gσ )0 is the identity component of Gσ . ...
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... property that ω k is in H. Write m = n/k. Then the group Cm of all mth roots of unity consisting of powers of ω k , which is an element in H. Thus Cm is a subset of H. Conversely, if ω ℓ is an element in H, then we may recycle an argument to show that ℓ is divisible by k. Now H = Cm is more or less ...
arXiv:math/0007066v1 [math.DG] 11 Jul 2000
arXiv:math/0007066v1 [math.DG] 11 Jul 2000

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... 1. Prove that rank (A) is equal to the number of nonzero eigenvalues. 2. Prove that rank (A) = rank (Ak ) for all k = 1, 2, . . . 3. Prove that A is nilpotent iff A = 0. 4. If trace (A) = 0 then rank (A) 6= 1. Let A = XΛX −1 We prove each item individually. 1. The rank is invariant to similarity. Th ...
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3. Nilpotent and solvable Lie algebras I can`t find my book. The

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... Note that the universal enveloping algebra construction is not inverse to the formation of AL : if we start with an associative algebra A, then UAL ! A. The beauty of this construction is that is preserves the representation theory: the representations of g are in bijection with modules over Ug , an ...
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... We need the following consequence of Theorem 3.1: Corollary 3.3. Suppose there exists a surjective strong morphism G → L|V where L is a Lie group and V a symmetric open neighborhood of the identity in L. Then G is locally isomorphic to a topological group. Proof. Shrinking V and restricting G accord ...
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Invariant convex cone

In mathematics, an invariant convex cone is a closed convex cone in a Lie algebra of a connected Lie group that is invariant under inner automorphisms. The study of such cones was initiated by Ernest Vinberg and Bertram Kostant.For a simple Lie algebra, the existence of an invariant convex cone forces the Lie algebra to have a Hermitian structure, i.e. the maximal compact subgroup has center isomorphic to the circle group. The invariant convex cone generated by a generator of the Lie algebra of the center is closed and is the minimal invariant convex cone (up to a sign). The dual cone with respect to the Killing form is the maximal invariant convex cone. Any intermediate cone is uniquely determined by its intersection with the Lie algebra of a maximal torus in a maximal compact subgroup. The intersection is invariant under the Weyl group of the maximal torus and the orbit of every point in the interior of the cone intersects the interior of the Weyl group invariant cone.For the real symplectic group, the maximal and minimal cone coincide, so there is only one invariant convex cone. When one is properly contained in the other, there is a continuum of intermediate invariant convex cones.Invariant convex cones arise in the analysis of holomorphic semigroups in the complexification of the Lie group, first studied by Grigori Olshanskii. They are naturally associated with Hermitian symmetric spaces and their associated holomorphic discrete series. The semigroup is made up of those elements in the complexification which, when acting on the Hermitian symmetric space of compact type, leave invariant the bounded domain corresponding to the noncompact dual. The semigroup acts by contraction operators on the holomorphic discrete series; its interior acts by Hilbert–Schmidt operators. The unitary part of their polar decomposition is the operator corresponding to an element in the original real Lie group, while the positive part is the exponential of an imaginary multiple of the infinitesimal operator corresponding to an element in the maximal cone. A similar decomposition already occurs in the semigroup.The oscillator semigroup of Roger Howe concerns the special case of this theory for the real symplectic group. Historically this has been one of the most important applications and has been generalized to infinite dimensions. This article treats in detail the example of the invariant convex cone for the symplectic group and its use in the study of the symplectic Olshanskii semigroup.
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