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F net
F net

Chap #3
Chap #3

... Example: What is the weight of an 80-kg person standing on Mars where the acceleration due to gravity is 3.7 m/s2? W = mg = 80 kg × 3.7 m/s 2 =296 N Compare this with a weight of 800 N for the same person standing here on the Earth. Friction and Air Drag Forces Sliding friction and air resistance ar ...
L9N - University of Iowa Physics
L9N - University of Iowa Physics

... energy of an object. When we push an object that is at rest, we are doing work on it. The work  we do then appears as the kinetic energy of the object that is moving. If there is friction however,  the  block  does  not  continue  moving  but  slows  down  and  stops.  What  became  of  the  kinetic ...
Chapter 4 – Newton`s Laws of Motion
Chapter 4 – Newton`s Laws of Motion

... Chapter 4 – Laws of Motion This is the first of two chapters on Newton’s laws of motion. Isaac Newton was one of the greatest scientists of all time and his work provides the foundation of classical mechanics. In addition to the laws of motion, Newton also discovered the law of universal gravitation ...
hw4a4b_help hint
hw4a4b_help hint

... a.) The maximum angle of the incline for which the crate will stay at rest is: b.)-e.) If the angle of the incline were instead the two amounts shown below, please fill in the rest of the values on the chart below: angle of incline: component of weight acting parallel to incline: (size only) frictio ...
Motion & Newton`s Laws
Motion & Newton`s Laws

... wheels but doesn’t move. Rolling friction makes a wheel roll forward or backward. A car stuck in the mud doesn’t have enough rolling friction to keep the wheels from slipping. ...
Forces all around us - 8th Grade Physical Science
Forces all around us - 8th Grade Physical Science

Lecture 13.Work
Lecture 13.Work

Document
Document

... Blocks 1 and 2 of masses m I and m2, respectively, are connected by light strings as shown above. These blocks are further connected to a block of mass M by another light string that passes over a pulley of negligible mass and friction. Blocks 1 and 2 move with a constant velocity v down the incline ...
3.3 Forces Adv B 2 MODIFIED
3.3 Forces Adv B 2 MODIFIED

... Analysis of results • a = g(m – uM) / (M + m) • This will give + acceleration (down and to the right) if m > uM, and a = 0 if m = uM. • The function is undefined if m < uM since negative a makes no physical sense; it will never fall “up” and to the left. The reality is a will stay at zero if a≤ 0. ...
AP Physics IB
AP Physics IB

Version A
Version A

Physics 513 Name Vaughan Worksheet Newton`s Second Law
Physics 513 Name Vaughan Worksheet Newton`s Second Law

... 21. A hockey puck (with a mass of 0.5 kg) is sliding across the ice with an initial velocity of 4 m/s East. It slows down and comes to rest over 100 meters. a) What is the magnitude and direction of the frictional force? b) What is the coefficient of friction? 22. Find the coefficient of kinetic fr ...
Chapter 5 Using Newton`s Laws: Friction, Circular Motion
Chapter 5 Using Newton`s Laws: Friction, Circular Motion

... Sliding friction is called kinetic friction. Approximation of the frictional force: Ffr = μkFN . Here, FN is the normal force, and μk is the coefficient of kinetic friction, which is different for each pair of surfaces. ...
Four Basic Forces
Four Basic Forces

... restrains the person with a force of 21,000 N bring them to rest in the car. How far does the person travel before coming to rest? ...
Chapters 5&6
Chapters 5&6

... • Direction of friction – opposite to the direction of attempted sliding (along the surface) • The origin of friction – bonding between the sliding surfaces (microscopic cold-welding) ...
Physics 102 Introduction to Physics
Physics 102 Introduction to Physics

... When the force of gravity is the only force acting on an object. No supporting force. ...
Forces and the Laws of Motion
Forces and the Laws of Motion

... d. none of the above _____ 10. A car goes forward along a level road at constant velocity. The additional force needed to bring the car into equilibrium is a. greater than the normal force times the coefficient of static friction. b. equal to the normal force times the coefficient of static friction ...
F n
F n

chapter 06
chapter 06

... 31. (II) Electric energy units are often expressed in the form of “kilowatt-hours.” (a) show that one kilowatt-hour (kWh) is equal to 3.6 x 106 J. (b) If the typical family of four in the Unites States uses Electric energy at an average rate of 500 W, how many kWh would their electric bill be for on ...
Solutions to
Solutions to

Force and Motion
Force and Motion

Laws of Motion PPT
Laws of Motion PPT

... What causes friction? Friction occurs between two objects because the surfaces of those objects are rough, and contain bumps and hollows. This roughness means that a force is needed to move the two objects over each other. ...
Calculating Net Force with the Second Law
Calculating Net Force with the Second Law

Chapter 4 Forces and Newton’s Laws of Motion continued
Chapter 4 Forces and Newton’s Laws of Motion continued

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Friction

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