1 o = 8.55 x10 12 C2 / Nm2 F = 1 4 0 Q1Q2 r2 ˆr
... A dipole is located at the origin, and is composed of particles with charges e and –e, separated by a distance 2×10-10 m along the xaxis. Calculate the magnitude of the E field at <0,2×10-8,0> m. ...
... A dipole is located at the origin, and is composed of particles with charges e and –e, separated by a distance 2×10-10 m along the xaxis. Calculate the magnitude of the E field at <0,2×10-8,0> m. ...
Experiment 1G Uniform Circular Motion
... By substituting this for v in the equation for centripetal force, we arrive at formula (1): ...
... By substituting this for v in the equation for centripetal force, we arrive at formula (1): ...
Document
... disrupts the ambient air. On top of a rising parcel, you ‘d expect a high (i.e. a positive pressure perturbation), simply because that rising parcel pushes into its surroundings. The resulting ‘perturbation’ pressure gradient enables compensating lateral and downward displacement as the parcel rises ...
... disrupts the ambient air. On top of a rising parcel, you ‘d expect a high (i.e. a positive pressure perturbation), simply because that rising parcel pushes into its surroundings. The resulting ‘perturbation’ pressure gradient enables compensating lateral and downward displacement as the parcel rises ...
428KB - NZQA
... Compares the two distances travelled in 14 s correctly, and is therefore able to say that Francis is the only rider to have travelled over 200 m around the track after 14 s (or vice versa). ...
... Compares the two distances travelled in 14 s correctly, and is therefore able to say that Francis is the only rider to have travelled over 200 m around the track after 14 s (or vice versa). ...
Wednesday, Aug. 31, 2005
... Assuming that the electric force on a toner particle must exceed twice its weight in order to ensure sufficient attraction, compute the required electric field strength near the surface of the drum. The electric force must be the same as twice the gravitational force on the toner particle. So we can ...
... Assuming that the electric force on a toner particle must exceed twice its weight in order to ensure sufficient attraction, compute the required electric field strength near the surface of the drum. The electric force must be the same as twice the gravitational force on the toner particle. So we can ...
Weightlessness
Weightlessness, or an absence of 'weight', is an absence of stress and strain resulting from externally applied mechanical contact-forces, typically normal forces from floors, seats, beds, scales, and the like. Counterintuitively, a uniform gravitational field does not by itself cause stress or strain, and a body in free fall in such an environment experiences no g-force acceleration and feels weightless. This is also termed ""zero-g"" where the term is more correctly understood as meaning ""zero g-force.""When bodies are acted upon by non-gravitational forces, as in a centrifuge, a rotating space station, or within a space ship with rockets firing, a sensation of weight is produced, as the contact forces from the moving structure act to overcome the body's inertia. In such cases, a sensation of weight, in the sense of a state of stress can occur, even if the gravitational field was zero. In such cases, g-forces are felt, and bodies are not weightless.When the gravitational field is non-uniform, a body in free fall suffers tidal effects and is not stress-free. Near a black hole, such tidal effects can be very strong. In the case of the Earth, the effects are minor, especially on objects of relatively small dimension (such as the human body or a spacecraft) and the overall sensation of weightlessness in these cases is preserved. This condition is known as microgravity and it prevails in orbiting spacecraft.