10.2 The Unit Circle: Cosine and Sine
... In Example 10.2.1, it was quite easy to find the cosine and sine of the quadrantal angles, but for non-quadrantal angles, the task was much more involved. In these latter cases, we made good use of the fact that the point P (x, y) = (cos(θ), sin(θ)) lies on the Unit Circle, x2 + y 2 = 1. If we subst ...
... In Example 10.2.1, it was quite easy to find the cosine and sine of the quadrantal angles, but for non-quadrantal angles, the task was much more involved. In these latter cases, we made good use of the fact that the point P (x, y) = (cos(θ), sin(θ)) lies on the Unit Circle, x2 + y 2 = 1. If we subst ...
Alternate Interior Angles
... Something interesting occurs if the two lines being cut by the transversal happen to be parallel. It turns out that every time I measure the corresponding angles, they turn out to be equal. You might use a protractor to measure the corresponding angles below. Since that seems to be true all the time ...
... Something interesting occurs if the two lines being cut by the transversal happen to be parallel. It turns out that every time I measure the corresponding angles, they turn out to be equal. You might use a protractor to measure the corresponding angles below. Since that seems to be true all the time ...
2.4 Vertical Angles
... aRSU and aUST are a linear pair. By the Linear Pair Postulate, they are supplementary. To find maRSU, subtract maUST from 180. maRSU 180 maUST 180 62 118 ...
... aRSU and aUST are a linear pair. By the Linear Pair Postulate, they are supplementary. To find maRSU, subtract maUST from 180. maRSU 180 maUST 180 62 118 ...
Ch 4 Angles - Parallel lines
... Something interesting occurs if the two lines being cut by the transversal happen to be parallel. It turns out that every time I measure the corresponding angles, they turn out to be equal. You might use a protractor to measure the corresponding angles below. Since that seems to be true all the time ...
... Something interesting occurs if the two lines being cut by the transversal happen to be parallel. It turns out that every time I measure the corresponding angles, they turn out to be equal. You might use a protractor to measure the corresponding angles below. Since that seems to be true all the time ...
