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... distribution. Once they arrive at the teller, service time is exponentially distributed based on a rate of 4 minutes per transaction, a. What is the probability that a customer will not have to wait for service? b. How many customers are most likely in line (waiting) at any one point in time? c. Wha ...
... distribution. Once they arrive at the teller, service time is exponentially distributed based on a rate of 4 minutes per transaction, a. What is the probability that a customer will not have to wait for service? b. How many customers are most likely in line (waiting) at any one point in time? c. Wha ...
Solutions_Activity_07
... P(x=4) is 0.24 since all the probabilities need to add to 1. c. Determine E(X), the mean rating given by females. {HINT: Find (rating*probability) for each rating, and then add up those values.} E(X) = (1)(.04) + 2(.05) + 3(.09) + 4(.24) + 5(.32) + 6(.26) = .04+.10+.27+.96+1.60+1.56 = 4.53 d. Find t ...
... P(x=4) is 0.24 since all the probabilities need to add to 1. c. Determine E(X), the mean rating given by females. {HINT: Find (rating*probability) for each rating, and then add up those values.} E(X) = (1)(.04) + 2(.05) + 3(.09) + 4(.24) + 5(.32) + 6(.26) = .04+.10+.27+.96+1.60+1.56 = 4.53 d. Find t ...