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ch1_Logic_and_proofs
ch1_Logic_and_proofs

... 1. Assume p is true and q is false 2. Show that ~p is also true. 3. Then we have that p ^ (~p) is true. 4. But this is impossible, since the statement p ^ (~p) is always false. There is a contradiction! 5. So, q cannot be false and therefore it is true. ...
counting linear extensions of
counting linear extensions of

CS 2742 (Logic in Computer Science) Lecture 6
CS 2742 (Logic in Computer Science) Lecture 6

A(x)
A(x)

... Formula A is true in interpretation I, |=I A, if for all possible valuations v holds that |=I A[v]. Model of formula A is interpretation I, in which is A true (that means for all valuations of free variables). Formula A is satisfiable, if there is interpretation I, in which A is satisfied (i.e., if ...
Partial Correctness Specification
Partial Correctness Specification

... A proof in Floyd-Hoare logic is a sequence of lines, each of which is either an axiom of the logic or follows from earlier lines by a rule of inference of the logic u ...
Palo Alto 2016 - Stanford Introduction to Logic
Palo Alto 2016 - Stanford Introduction to Logic

... properly, we can create another variable called index that only increments when the satisfied.add(i) command is run. This would eliminate the need for the second for loop and make the program have an efficiency of O(n). As a result of this exercise, the students were able to draw connections to diff ...
AC Series/Parallel
AC Series/Parallel

Math 151 Solutions to selected homework problems Section 3.7
Math 151 Solutions to selected homework problems Section 3.7

Sentential Logic 2 - Michael Johnson's Homepage
Sentential Logic 2 - Michael Johnson's Homepage

... they are all either true or false. There are two truth-values: true and false. So, for example, the sentence “My name is Michael” is true, and the sentence “Today is Wednesday” is false. Since a translation of a sentence is true when the original sentence is true and false when it is false, “M” is t ...
Implication
Implication

Final with solutions
Final with solutions

Inference IV: Approximate Inference
Inference IV: Approximate Inference



Logic and Automata - Cheriton School of Computer Science
Logic and Automata - Cheriton School of Computer Science

... Theorem. A set of integers is definable in Th(N, +, Vk ) if and only if its characteristic sequence is k-automatic. Proof. First we show how to construct a finite automaton Mϕ corresponding to any formula ϕ of Th(N, +, Vk ). The idea again is that Mϕ will accept the base-k representations of all n-t ...
Notes and exercises on First Order Logic
Notes and exercises on First Order Logic

... Examples of relational structures are partially ordered sets and graphs. On the other hand groups, rings, fields, lattices and Boolean algebras are examples of algebras. We are aiming of course to establish when a formula is true in a structure U. The next example shows that the truth value of a for ...
A Note on Assumptions about Skolem Functions
A Note on Assumptions about Skolem Functions

Solutions: Section 2.6
Solutions: Section 2.6

PHIL12A Section answers, 9 February 2011
PHIL12A Section answers, 9 February 2011

... 2. How many different ternary sentential connectives are there? How did you arrive at this number? You should not try to list them all! We calculate the number of ternary connectives in the same way as we calculated the number of binary connectives in the last question. A truth table for a ternary ...
Introduction to Theoretical Computer Science, lesson 3
Introduction to Theoretical Computer Science, lesson 3

... An argument is valid iff the conclusion is true in every model of the set of the premises. But the set of models can be infinite! And, of course, we cannot examine an infinite number of models; but we can verify the ‘logical form’ of the argument, and check whether the models of premises do satisfy ...
1.3.4 Word Grammars
1.3.4 Word Grammars

an interpretation of aristotle`s syllogistic and a certain fragment of set
an interpretation of aristotle`s syllogistic and a certain fragment of set

Math 2534 Test 1B Fall 2008 Name
Math 2534 Test 1B Fall 2008 Name

Automata for the modal µ-calculus and related results
Automata for the modal µ-calculus and related results

Predicate logic
Predicate logic

Algebraic Representation of Linear Equations in Two
Algebraic Representation of Linear Equations in Two

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Boolean satisfiability problem

In computer science, the Boolean Satisfiability Problem (sometimes called Propositional Satisfiability Problem and abbreviated as SATISFIABILITY or SAT) is the problem of determining if there exists an interpretation that satisfies a given Boolean formula. In other words, it asks whether the variables of a given Boolean formula can be consistently replaced by the values TRUE or FALSE in such a way that the formula evaluates to TRUE. If this is the case, the formula is called satisfiable. On the other hand, if no such assignment exists, the function expressed by the formula is identically FALSE for all possible variable assignments and the formula is unsatisfiable. For example, the formula ""a AND NOT b"" is satisfiable because one can find the values a = TRUE and b = FALSE, which make (a AND NOT b) = TRUE. In contrast, ""a AND NOT a"" is unsatisfiable.SAT is one of the first problems that was proven to be NP-complete. This means that all problems in the complexity class NP, which includes a wide range of natural decision and optimization problems, are at most as difficult to solve as SAT. There is no known algorithm that efficiently solves SAT, and it is generally believed that no such algorithm exists; yet this belief has not been proven mathematically, and resolving the question whether SAT has an efficient algorithm is equivalent to the P versus NP problem, which is the most famous open problem in the theory of computing.Despite the fact that no algorithms are known that solve SAT efficiently, correctly, and for all possible input instances, many instances of SAT that occur in practice, such as in artificial intelligence, circuit design and automatic theorem proving, can actually be solved rather efficiently using heuristical SAT-solvers. Such algorithms are not believed to be efficient on all SAT instances, but experimentally these algorithms tend to work well for many practical applications.
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