
Problem solving and proving via generalisation
... BB ! and CC ! connecting corresponding vertices are concurrent in a point O, then the respective intersections X, Y and Z of the corresponding sides (extended if necessary) are collinear (lie on a line), and of course, conversely, the other way round. Now this theorem is quite difficult to prove in ...
... BB ! and CC ! connecting corresponding vertices are concurrent in a point O, then the respective intersections X, Y and Z of the corresponding sides (extended if necessary) are collinear (lie on a line), and of course, conversely, the other way round. Now this theorem is quite difficult to prove in ...
Predicate logic - Teaching-WIKI
... “Anyone passing his Intelligent System exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Gary wo ...
... “Anyone passing his Intelligent System exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Gary wo ...
Predicate logic
... “Anyone passing his Intelligent System exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Gary wo ...
... “Anyone passing his Intelligent System exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Gary wo ...
03_Artificial_Intelligence-PredicateLogic
... “Anyone passing his Artificial Intelligence exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Ga ...
... “Anyone passing his Artificial Intelligence exam and winning the lottery is happy. But any student who studies for an exam or is lucky can pass all his exams. John did not study but John is lucky. Anyone who is lucky wins the lottery. Mary did not win the lottery, however Mary passed her IS exam. Ga ...
CPS130, Lecture 1: Introduction to Algorithms
... Definition 1P: A proposition is a statement that is either true or false but not both. For example, “Betsy is a smart dog”, is a proposition that is true. We might call it p1. Definition 1B: A Boolean expression is a variable, say xi, which takes on value xi = 1 or xi = 0 but not both. We could be m ...
... Definition 1P: A proposition is a statement that is either true or false but not both. For example, “Betsy is a smart dog”, is a proposition that is true. We might call it p1. Definition 1B: A Boolean expression is a variable, say xi, which takes on value xi = 1 or xi = 0 but not both. We could be m ...
Chapter 1: The Foundations: Logic and Proofs
... P is a sufficient condition for Q Q if P Q whenever P Q is a necessary condition for P ...
... P is a sufficient condition for Q Q if P Q whenever P Q is a necessary condition for P ...
p q
... Common phrasings for the biconditional • p if and only if q • p is necessary and equivalent for q • p is equivalent to q ...
... Common phrasings for the biconditional • p if and only if q • p is necessary and equivalent for q • p is equivalent to q ...
Predicate Logic Review
... matter, because if φ is a closed sentence, its truth won’t vary from one assignment to the next.) The strategy for defining truth in a model that we have just outlined is due in its essentials to Alfred Tarski. It was one of his great achievements, because it showed logicians how to use semantic not ...
... matter, because if φ is a closed sentence, its truth won’t vary from one assignment to the next.) The strategy for defining truth in a model that we have just outlined is due in its essentials to Alfred Tarski. It was one of his great achievements, because it showed logicians how to use semantic not ...
Document
... Boolean Algebras (Chapter 11) Boolean algebra provides the operations and the rules for working with the set {0, 1}. These are the rules that underlie electronic and optical circuits, and the methods we will discuss are fundamental to VLSI design. ...
... Boolean Algebras (Chapter 11) Boolean algebra provides the operations and the rules for working with the set {0, 1}. These are the rules that underlie electronic and optical circuits, and the methods we will discuss are fundamental to VLSI design. ...
Practice Problem Set 1
... • These problems will not be graded. • Mutual discussion and discussion with the instructor/TA is strongly encouraged. 1. [From HW1, Autumn 2011] Use the proof system of first order logic studied in class to prove each of the following sequents. You must indicate which proof rule you are applying at ...
... • These problems will not be graded. • Mutual discussion and discussion with the instructor/TA is strongly encouraged. 1. [From HW1, Autumn 2011] Use the proof system of first order logic studied in class to prove each of the following sequents. You must indicate which proof rule you are applying at ...