PDF - mockies – Mockiesgateacademy
... aims of alchemy that emerged with time were the quest for the elixir of life (the drinking of which would endue the alchemist with immortality), and the search for the philosopher’s stone, which would turn base metals into gold. Improbable as these ideas might seem today, the alchemists continued th ...
... aims of alchemy that emerged with time were the quest for the elixir of life (the drinking of which would endue the alchemist with immortality), and the search for the philosopher’s stone, which would turn base metals into gold. Improbable as these ideas might seem today, the alchemists continued th ...
chemistry-c7-what-you-should
... I can recall that the feedstocks of nitrogen and hydrogen for the Haber process are made from air, natural gas and steam I in the context of the Haber process: a. I understand that the reaction between hydrogen and nitrogen to form ammonia is a reversible reaction b. I understand how the yield of am ...
... I can recall that the feedstocks of nitrogen and hydrogen for the Haber process are made from air, natural gas and steam I in the context of the Haber process: a. I understand that the reaction between hydrogen and nitrogen to form ammonia is a reversible reaction b. I understand how the yield of am ...
AP Chemistry Notes and Worksheets 2014
... covalent bonds-created when two or more nonmetals share electrons molecule- atoms held together by covalent bonds ions- charged particles formed by the loss or gain of electrons ionic bonds- compounds created when one atom loses an electron and another gains it; are held together by electros ...
... covalent bonds-created when two or more nonmetals share electrons molecule- atoms held together by covalent bonds ions- charged particles formed by the loss or gain of electrons ionic bonds- compounds created when one atom loses an electron and another gains it; are held together by electros ...
The reaction pathways of hydrogen peroxide in
... breakdown of the intermediate have been calculated. The metal-catalyzed pathway of hydrogen peroxide is dealing with the effect of hydroxyl radicals created by the Fenton reaction and their potential to oxidize the disulfide bridge of small peptides. Based on the reduction potential, which is an ind ...
... breakdown of the intermediate have been calculated. The metal-catalyzed pathway of hydrogen peroxide is dealing with the effect of hydroxyl radicals created by the Fenton reaction and their potential to oxidize the disulfide bridge of small peptides. Based on the reduction potential, which is an ind ...
Dr David`s Chemistry Test Answers
... pressure would make the process less economic due to the increased costs of equipment and maintenance and a lower temperature would slow the reaction again reducing the overall economy. 2. Nitric acid the, Ostwald process: Ammonia is oxidised in air using a catalyst of rhodium and platinum at a temp ...
... pressure would make the process less economic due to the increased costs of equipment and maintenance and a lower temperature would slow the reaction again reducing the overall economy. 2. Nitric acid the, Ostwald process: Ammonia is oxidised in air using a catalyst of rhodium and platinum at a temp ...
In Class Problems and Notes AP Chemistry General Equilibrium
... Case II: In this case, the activation energy of the reverse reaction is much smaller, meaning you will need more reactants to make the reactions occur at an equal rate. Since you will have more reactants at equilibrium, Keq will be less than one. Case III: In this case the activation energies for th ...
... Case II: In this case, the activation energy of the reverse reaction is much smaller, meaning you will need more reactants to make the reactions occur at an equal rate. Since you will have more reactants at equilibrium, Keq will be less than one. Case III: In this case the activation energies for th ...
1 of 52
... Give the balanced equation for each of the following chemical reactions. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.) (a) Glucose (C6H12O6) reacts with oxygen gas to produce gaseous carbon dioxide and water vapor. ...
... Give the balanced equation for each of the following chemical reactions. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.) (a) Glucose (C6H12O6) reacts with oxygen gas to produce gaseous carbon dioxide and water vapor. ...
PDF Chapter 14 Chemical Kinetics
... The frequency of collisions was the first consideration we examined when thinking about what controls reaction rates. The more collisions, the faster the rate should be. And that’s generally but not always true. There are two ways to increase the frequency of collisions between molecules: crowd mo ...
... The frequency of collisions was the first consideration we examined when thinking about what controls reaction rates. The more collisions, the faster the rate should be. And that’s generally but not always true. There are two ways to increase the frequency of collisions between molecules: crowd mo ...
Principles of Chemistry 1 and 2 Notes
... The arrow shows the shift of electron density towards fluorine (more electronegative) which leads to charge separation. Hydrogen will have a partial positive charge (positive end)and fluorine will have a partial negative charge (negative end). Partial charge confirmed by electrical field (turning it ...
... The arrow shows the shift of electron density towards fluorine (more electronegative) which leads to charge separation. Hydrogen will have a partial positive charge (positive end)and fluorine will have a partial negative charge (negative end). Partial charge confirmed by electrical field (turning it ...
PDF Electrochemistry- II
... externally. This is how the cell delivers current during its operation. Current direction, by convention, is taken to be the direction of flow of positive charge which means that it is opposite to the direction of flow of electrons. In the above representation of the cell (eqn. 11) by convention oxi ...
... externally. This is how the cell delivers current during its operation. Current direction, by convention, is taken to be the direction of flow of positive charge which means that it is opposite to the direction of flow of electrons. In the above representation of the cell (eqn. 11) by convention oxi ...
Term 111, Final Exam (All correct choices are A): 1. What is the
... A) an element with a large Ei and an element with a small negative Eea B) an element with a small Ei and an element with a small negative Eea C) elements with equal values of Ei and Eea D) an element with a large Ei and an element with a large negative Eea E) an element with a small Ei and an elemen ...
... A) an element with a large Ei and an element with a small negative Eea B) an element with a small Ei and an element with a small negative Eea C) elements with equal values of Ei and Eea D) an element with a large Ei and an element with a large negative Eea E) an element with a small Ei and an elemen ...
base hydrolysis of cobalt(iii)
... If the S N 2 reaction were correct then the role of OH would be to attack cobalt and form [Coen 2 NO 2 (OH)]+ (Eq. 13). Clearly that is not the role of OH - , because [Coen 2NO 2 (OH)]+ does not react with NO 2- (Eq. 15). However, a mixture of [Coen 2 NO 2 Cl], NO 2 - , and OH readily afford [Coen 2 ...
... If the S N 2 reaction were correct then the role of OH would be to attack cobalt and form [Coen 2 NO 2 (OH)]+ (Eq. 13). Clearly that is not the role of OH - , because [Coen 2NO 2 (OH)]+ does not react with NO 2- (Eq. 15). However, a mixture of [Coen 2 NO 2 Cl], NO 2 - , and OH readily afford [Coen 2 ...
chemistry notes on the mole - lessons
... undertaken by the Ministry of Health revealed a huge rise in carbon monoxide poisonings associated with the ice storm. The most common sources of poisoning were generators, and barbeques being used indoors in locations such as basements and garages. Carbon monoxide CO is similar to CO2 which is foun ...
... undertaken by the Ministry of Health revealed a huge rise in carbon monoxide poisonings associated with the ice storm. The most common sources of poisoning were generators, and barbeques being used indoors in locations such as basements and garages. Carbon monoxide CO is similar to CO2 which is foun ...
regents chemistry midterm - irondequoit 2014_entire exam w key
... A glass tube is filled with hydrogen gas at low pressure. An electric current is passed through the gas, causing it to emit light. This light is passed through a prism to separate the light into the bright, colored lines of hydrogen’s visible spectrum. Each colored line corresponds to a particular w ...
... A glass tube is filled with hydrogen gas at low pressure. An electric current is passed through the gas, causing it to emit light. This light is passed through a prism to separate the light into the bright, colored lines of hydrogen’s visible spectrum. Each colored line corresponds to a particular w ...
Chemistry Standards Clarification
... unstable isotopes of a particular type. Illustrate how elements can change in nuclear reactions using balanced equations. (recommended) Describe the potential energy changes as two protons approach each other. (recommended) Describe how and where all the elements on earth were formed. (recommended) ...
... unstable isotopes of a particular type. Illustrate how elements can change in nuclear reactions using balanced equations. (recommended) Describe the potential energy changes as two protons approach each other. (recommended) Describe how and where all the elements on earth were formed. (recommended) ...
Dr. Spencer`s PPT
... Nonelectrolytes are not dissociated into ions in solution Extent of dissolution does not dictate strong or weak electrolyte solution (i.e., HC2H3O2 is very soluble but is a weak electrolyte while Ba(OH)2 is only slightly soluble is a strong electrolyte) ...
... Nonelectrolytes are not dissociated into ions in solution Extent of dissolution does not dictate strong or weak electrolyte solution (i.e., HC2H3O2 is very soluble but is a weak electrolyte while Ba(OH)2 is only slightly soluble is a strong electrolyte) ...
study material(2014-15) class xii-chemistry
... Tips and Techniques for teaching/learning each chapter. Students‘ common errors, un-attempted questions and their remediation. Reviewed Support Materials of the previous year. In order to ensure that the participants come well-prepared for the Workshop, the topics/chapters were distributed among the ...
... Tips and Techniques for teaching/learning each chapter. Students‘ common errors, un-attempted questions and their remediation. Reviewed Support Materials of the previous year. In order to ensure that the participants come well-prepared for the Workshop, the topics/chapters were distributed among the ...
The Free High School Science Texts
... textbooks you probably own or use. • We know people copy textbooks illegally but we would LOVE it if you copied our’s - go ahead copy to your hearts content, legally! • Publishers’ revenue is generated by controlling the market, we don’t want any money, go ahead, distribute our books far and wide - ...
... textbooks you probably own or use. • We know people copy textbooks illegally but we would LOVE it if you copied our’s - go ahead copy to your hearts content, legally! • Publishers’ revenue is generated by controlling the market, we don’t want any money, go ahead, distribute our books far and wide - ...
ChemistryReview
... correctly? Explain your answer. If the equation was not balanced correctly, write the correctly balanced equation. 77. How many moles of nitrogen are contained in 4.20 1024 atoms of nitrogen? 78. How many grams of O2 are in 5.0 mol of the element? ...
... correctly? Explain your answer. If the equation was not balanced correctly, write the correctly balanced equation. 77. How many moles of nitrogen are contained in 4.20 1024 atoms of nitrogen? 78. How many grams of O2 are in 5.0 mol of the element? ...
M for Moles - Shop
... List of Relative Atomic Mass How to use this e-book Finding calculations in chemistry difficult to learn? Don’t know how/when to or why use moles in chemistry? Confuse about molecular weights and their relationships to moles and chemical equations? This e-book teaches you how to do mole calculations ...
... List of Relative Atomic Mass How to use this e-book Finding calculations in chemistry difficult to learn? Don’t know how/when to or why use moles in chemistry? Confuse about molecular weights and their relationships to moles and chemical equations? This e-book teaches you how to do mole calculations ...
Molecules, Moles and Chemical Equations File
... new compounds. In its written representation of nature, therefore, the chemical equation must not “create or destroy” atoms. To uphold this condition, we must have the same number of atoms of each element on both sides of the chemical equation (see Figure 3.4). An equation that does not meet this co ...
... new compounds. In its written representation of nature, therefore, the chemical equation must not “create or destroy” atoms. To uphold this condition, we must have the same number of atoms of each element on both sides of the chemical equation (see Figure 3.4). An equation that does not meet this co ...
Lab # 18
... 1. Equations must be balanced so that the number of atoms of each element is equal on the left side (reactants) and on the right side (products) of the reaction. 2. We MUST NOT change the subscripts of any of the reactants or products; if we did that, we would be changing the very nature of the subs ...
... 1. Equations must be balanced so that the number of atoms of each element is equal on the left side (reactants) and on the right side (products) of the reaction. 2. We MUST NOT change the subscripts of any of the reactants or products; if we did that, we would be changing the very nature of the subs ...
Thermodynamics Practice Problems Presentation
... 1 mol each of H–H and F–F bonds are broken The bonds formed are 2 mol of H–F bonds ∆H= (nH-HDH-H + nF-FDF-F) – nH-FDH-F (1 mol x 432KJ) + (1 mol x 154 KJ) - (2 mol x 565 KJ mol mol mol ∆H = -544 KJ The enthalpy change for the reaction of 1 mol hydrogen gas and 1 mol fluorine gas to ptoduce 2 mol. Hy ...
... 1 mol each of H–H and F–F bonds are broken The bonds formed are 2 mol of H–F bonds ∆H= (nH-HDH-H + nF-FDF-F) – nH-FDH-F (1 mol x 432KJ) + (1 mol x 154 KJ) - (2 mol x 565 KJ mol mol mol ∆H = -544 KJ The enthalpy change for the reaction of 1 mol hydrogen gas and 1 mol fluorine gas to ptoduce 2 mol. Hy ...
chemistry-resource
... Tips and Techniques for teaching/learning each chapter. Students’ common errors, un-attempted questions and their remediation. Reviewed Support Materials of the previous year. In order to ensure that the participants come well-prepared for the Workshop, the topics/chapters were distributed among the ...
... Tips and Techniques for teaching/learning each chapter. Students’ common errors, un-attempted questions and their remediation. Reviewed Support Materials of the previous year. In order to ensure that the participants come well-prepared for the Workshop, the topics/chapters were distributed among the ...
WORD - SSS Chemistry
... 10. What volume of 2.50 M Li2CO3 would need to be evaporated in order to obtain 47.232 g of solid Li2CO3? Include proper units in your work and in your answers. ...
... 10. What volume of 2.50 M Li2CO3 would need to be evaporated in order to obtain 47.232 g of solid Li2CO3? Include proper units in your work and in your answers. ...
Redox
Redox reactions include all chemical reactions in which atoms have their oxidation state changed; in general, redox reactions involve the transfer of electrons between species. The term ""redox"" comes from two concepts involved with electron transfer: reduction and oxidation. It can be explained in simple terms: Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom, or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.Although oxidation reactions are commonly associated with the formation of oxides from oxygen molecules, these are only specific examples of a more general concept of reactions involving electron transfer.Redox reactions, or oxidation-reduction reactions, have a number of similarities to acid–base reactions. Like acid–base reactions, redox reactions are a matched set, that is, there cannot be an oxidation reaction without a reduction reaction happening simultaneously. The oxidation alone and the reduction alone are each called a half-reaction, because two half-reactions always occur together to form a whole reaction. When writing half-reactions, the gained or lost electrons are typically included explicitly in order that the half-reaction be balanced with respect to electric charge.Though sufficient for many purposes, these descriptions are not precisely correct. Oxidation and reduction properly refer to a change in oxidation state — the actual transfer of electrons may never occur. The oxidation state of an atom is the fictitious charge that an atom would have if all bonds between atoms of different elements were 100% ionic. Thus, oxidation is better defined as an increase in oxidation state, and reduction as a decrease in oxidation state. In practice, the transfer of electrons will always cause a change in oxidation state, but there are many reactions that are classed as ""redox"" even though no electron transfer occurs (such as those involving covalent bonds).There are simple redox processes, such as the oxidation of carbon to yield carbon dioxide (CO2) or the reduction of carbon by hydrogen to yield methane (CH4), and more complex processes such as the oxidation of glucose (C6H12O6) in the human body through a series of complex electron transfer processes.