N5 Chemistry 2014
... 11. Chlorine can be produced commercially from concentrated sodium chloride solution in a membrane cell. Only sodium ions can pass through the membrane. These ions move in the direction shown in the diagram. Cl2(g) ...
... 11. Chlorine can be produced commercially from concentrated sodium chloride solution in a membrane cell. Only sodium ions can pass through the membrane. These ions move in the direction shown in the diagram. Cl2(g) ...
James Ruse with Solutions
... A soft drink may be decarbonated by heating. In observing the results, the equilibrium between gaseous and dissolved carbon dioxide can be examined. CO2 (g) ...
... A soft drink may be decarbonated by heating. In observing the results, the equilibrium between gaseous and dissolved carbon dioxide can be examined. CO2 (g) ...
AP Chem Summer Assignment KEY
... Forming binary ionic compounds A. In a binary ionic compound the total positive charges must equal the total negative charges. The best way to write correct formula units for ionic compounds is to use the “Criss Cross Method”. B. Sample problem: What ionic compound would form when calcium ions combi ...
... Forming binary ionic compounds A. In a binary ionic compound the total positive charges must equal the total negative charges. The best way to write correct formula units for ionic compounds is to use the “Criss Cross Method”. B. Sample problem: What ionic compound would form when calcium ions combi ...
CHAPTER 21 NONMETALLIC ELEMENTS AND THEIR COMPOUNDS
... Eventually, the sodium hydrogen carbonate precipitates (the water solvent evaporates since NaHCO3 is not hygroscopic). Thus, most of the white solid is NaHCO3 plus some Na2CO3. ...
... Eventually, the sodium hydrogen carbonate precipitates (the water solvent evaporates since NaHCO3 is not hygroscopic). Thus, most of the white solid is NaHCO3 plus some Na2CO3. ...
Acids, Bases, and pH
... Strong bases completely dissociate into cation and OH– ions. The first step in calculating the pH of a strong base is to determine concentration of OH– ions. Some strong bases will produce more than one OH– ion for each formula unit of the base. For example, Ca(OH)2 will dissociate in water accordin ...
... Strong bases completely dissociate into cation and OH– ions. The first step in calculating the pH of a strong base is to determine concentration of OH– ions. Some strong bases will produce more than one OH– ion for each formula unit of the base. For example, Ca(OH)2 will dissociate in water accordin ...
The hydrogen bonding of cytosine with guanine
... The enthalpy of hydrogen-bond formation between guanine (G) and cytusine (C) in o-dichlorobenzene and in chloroform at 25°C has been determined by direct calorimetric measurement. We derivatized 2’-deoxyguanosine and 2‘-deoxycytidine at the 5’- and 3’-hydroxyls with triisopropylsilyl groups; these g ...
... The enthalpy of hydrogen-bond formation between guanine (G) and cytusine (C) in o-dichlorobenzene and in chloroform at 25°C has been determined by direct calorimetric measurement. We derivatized 2’-deoxyguanosine and 2‘-deoxycytidine at the 5’- and 3’-hydroxyls with triisopropylsilyl groups; these g ...
Unit 8 Test Review
... Apply the Law of Conservation of Mass to get the same number of atoms of every element on each side of the equation. Tip: Start by balancing an element that appears in only one reactant and product. Once one element is balanced, proceed to balance another, and another, until all elements are balance ...
... Apply the Law of Conservation of Mass to get the same number of atoms of every element on each side of the equation. Tip: Start by balancing an element that appears in only one reactant and product. Once one element is balanced, proceed to balance another, and another, until all elements are balance ...
Chemistry - Higher tier - Paper 4 - Sample assessment material
... It is made using the reaction between the alkali ammonia and sulfuric acid. 2NH3 + H2SO4 (NH4)2SO4 (i) ...
... It is made using the reaction between the alkali ammonia and sulfuric acid. 2NH3 + H2SO4 (NH4)2SO4 (i) ...
Reaction of niobium with water
... Current methodology involves the separation of tantalum from these acid solutions using a liquid-liquid extraction technique. In this process tantalum salts are extracted into the ketone MIBK (methyl isobutyl ketone, 4-methyl pentan-2-one). The niobium remains in the HF solution. This solvent extrac ...
... Current methodology involves the separation of tantalum from these acid solutions using a liquid-liquid extraction technique. In this process tantalum salts are extracted into the ketone MIBK (methyl isobutyl ketone, 4-methyl pentan-2-one). The niobium remains in the HF solution. This solvent extrac ...
Stoichiometry Worksheet #4
... 6. Given the following equation: Na2O + H2O ---> 2 NaOH How many grams of NaOH is produced from 1.20 x 102 grams of Na2O? ...
... 6. Given the following equation: Na2O + H2O ---> 2 NaOH How many grams of NaOH is produced from 1.20 x 102 grams of Na2O? ...
Chemical Equations and Reactions
... place at lower temperatures in the presence of a catalyst. A catalyst is a substance that changes the rate of a chemical reaction but can be recovered unchanged. To show that a catalyst is present, the formula for the catalyst or the word catalyst is written over the reaction arrow. In many reaction ...
... place at lower temperatures in the presence of a catalyst. A catalyst is a substance that changes the rate of a chemical reaction but can be recovered unchanged. To show that a catalyst is present, the formula for the catalyst or the word catalyst is written over the reaction arrow. In many reaction ...
Chapter 7: Solutions
... compound will significantly dissolve in water. Predict whether a precipitation reaction will occur when two specified aqueous solutions of ionic compounds are mixed; if a precipitation reaction will occur, write a balanced chemical equation for the reaction. Compare the relative solubilities of orga ...
... compound will significantly dissolve in water. Predict whether a precipitation reaction will occur when two specified aqueous solutions of ionic compounds are mixed; if a precipitation reaction will occur, write a balanced chemical equation for the reaction. Compare the relative solubilities of orga ...
unit_k_reading_notes
... Let us begin with defining stoichiometry. Most texts break it down into 2 categories. The first one we’ve already seen—it’s composition stoichiometry, which is the study of mass relationships of elements in compounds. Examples of this include calculating percentage composition, and determination of ...
... Let us begin with defining stoichiometry. Most texts break it down into 2 categories. The first one we’ve already seen—it’s composition stoichiometry, which is the study of mass relationships of elements in compounds. Examples of this include calculating percentage composition, and determination of ...
2015_Final Exam Study Guide
... The definition of pH is a. –log [H3O+]. b. the percent of hydronium ions. c. the parts per million of hydronium ions. d. log [OH–]. A buffer keeps a solution's pH constant by a. providing neutralizing ions. b. increasing the concentration of H2O molecules. c. changing the [H3O+]. d. releasing or abs ...
... The definition of pH is a. –log [H3O+]. b. the percent of hydronium ions. c. the parts per million of hydronium ions. d. log [OH–]. A buffer keeps a solution's pH constant by a. providing neutralizing ions. b. increasing the concentration of H2O molecules. c. changing the [H3O+]. d. releasing or abs ...
Thermochemistry
... As the following example show, we can study the heat of acid-base reactions using a constant-pressure calorimeter. 1.00 x 102 mL of 0.500 M HCl is mixed with 1.00 x 102 mL of 0.500 M NaOH in a constant-pressure calorimeter that has a heat capacity of 335 J/oC. The initial temperature of the HCl and ...
... As the following example show, we can study the heat of acid-base reactions using a constant-pressure calorimeter. 1.00 x 102 mL of 0.500 M HCl is mixed with 1.00 x 102 mL of 0.500 M NaOH in a constant-pressure calorimeter that has a heat capacity of 335 J/oC. The initial temperature of the HCl and ...
Openstax - Chemistry - Answer Key
... 11. The mixture can have a variety of compositions; a pure substance has a definite composition. Both have the same composition from point to point. 13. Molecules of elements contain only one type of atom; molecules of compounds contain two or more types of atoms. They are similar in that both are c ...
... 11. The mixture can have a variety of compositions; a pure substance has a definite composition. Both have the same composition from point to point. 13. Molecules of elements contain only one type of atom; molecules of compounds contain two or more types of atoms. They are similar in that both are c ...
No Slide Title
... Calculate the quantity of heat absorbed by 50.0 kg of rocks if their temperature increases by 12 C. Assume that the specific heat of the rocks is 0.821 J/ g K. What temperature change would these rocks undergo if they absorbed 450 kJ of heat? 3. A 25-g piece of gold (specific heat = 0.129 J/g K) an ...
... Calculate the quantity of heat absorbed by 50.0 kg of rocks if their temperature increases by 12 C. Assume that the specific heat of the rocks is 0.821 J/ g K. What temperature change would these rocks undergo if they absorbed 450 kJ of heat? 3. A 25-g piece of gold (specific heat = 0.129 J/g K) an ...
CHEM230P1_06_2014_Y_P1
... Pt(s) | Sn2+ (aq, 0.50 M), Sn4+ (aq, 0.50 M) || I–(aq, 0.15 M) | AgI(s) | Ag(s) ...
... Pt(s) | Sn2+ (aq, 0.50 M), Sn4+ (aq, 0.50 M) || I–(aq, 0.15 M) | AgI(s) | Ag(s) ...
5 Energetics/thermochemistry
... above absolute zero. In the case of an ideal gas, the absolute temperature (in kelvin) is directly proportional to the average kinetic energy of translational motion (from one place to another). In liquids and solids there is still a similar relationship. So the warmth you feel when you touch a hot ...
... above absolute zero. In the case of an ideal gas, the absolute temperature (in kelvin) is directly proportional to the average kinetic energy of translational motion (from one place to another). In liquids and solids there is still a similar relationship. So the warmth you feel when you touch a hot ...
Electrolysis of water
Electrolysis of water is the decomposition of water (H2O) into oxygen (O2) and hydrogen gas (H2) due to an electric current being passed through the water.This technique can be used to make hydrogen fuel (hydrogen gas) and breathable oxygen; though currently most industrial methods make hydrogen fuel from natural gas instead.