11 BALANCING CHEMICAL EQUATIONS 1. 2 K + 1
... 1) Pick one reaction which made a Precipitate from each column and write the ionic reaction. 2) Use the solubility rule to determine which product formed the precipitate & which was soluble. 3) Cross out the products which were soluble because they’re spectators as reactants & products. ...
... 1) Pick one reaction which made a Precipitate from each column and write the ionic reaction. 2) Use the solubility rule to determine which product formed the precipitate & which was soluble. 3) Cross out the products which were soluble because they’re spectators as reactants & products. ...
Balancing RedOx reactions handout
... 1. Determine the oxidation numbers for all atoms in the reaction. 2. Determine which atom is being oxidized and which is being reduced. 3. Write a half reaction for the reduction process (addition of electrons…electrons added to the left side). 4. Write a half reaction for the oxidation process (los ...
... 1. Determine the oxidation numbers for all atoms in the reaction. 2. Determine which atom is being oxidized and which is being reduced. 3. Write a half reaction for the reduction process (addition of electrons…electrons added to the left side). 4. Write a half reaction for the oxidation process (los ...
pdfCfE Higher - Unit 3 - Pupil Booklet 2 MB
... Power stations that burn fossil fuels must remove the sulfur dioxide from the gases before release to the atmosphere. The SO2 is converted to H2SO4 , which is sold. Waste used to be dumped in quarries, rivers, the sea or stored in containers from which it could leak into streams. These methods are n ...
... Power stations that burn fossil fuels must remove the sulfur dioxide from the gases before release to the atmosphere. The SO2 is converted to H2SO4 , which is sold. Waste used to be dumped in quarries, rivers, the sea or stored in containers from which it could leak into streams. These methods are n ...
Chemistry 1st Semester Practice Exam
... C. be separated into other substances by chemical means ...
... C. be separated into other substances by chemical means ...
Factors that affect the rate of reactions
... liquid, liquid and a gas etc. It does not affect reactants that are in the same phase. To summarize the 3 ways to change the rate of a reaction. If you can make the reactants: MOVE FASTER, HIT each other MORE OFTEN with MORE ENERGY The reaction rate will INCREASE ...
... liquid, liquid and a gas etc. It does not affect reactants that are in the same phase. To summarize the 3 ways to change the rate of a reaction. If you can make the reactants: MOVE FASTER, HIT each other MORE OFTEN with MORE ENERGY The reaction rate will INCREASE ...
spring semester review
... (a) Shifts right (b) shifts left (c) no change (d) can’t tell from the information given 6. Add more Ni? 7. Add more CO (g) 8. Add Neon (g) 9. Remove Ni(CO)4 (g) 10. Cut volume by ½ 11. Increase Temperature 12. Add a catalyst 13. For which one of the following reactions is Kc equal to Kp? (a) H2(g) ...
... (a) Shifts right (b) shifts left (c) no change (d) can’t tell from the information given 6. Add more Ni? 7. Add more CO (g) 8. Add Neon (g) 9. Remove Ni(CO)4 (g) 10. Cut volume by ½ 11. Increase Temperature 12. Add a catalyst 13. For which one of the following reactions is Kc equal to Kp? (a) H2(g) ...
From (2)
... This eq. Can be used for different solid-solid reactions. Ex. silicate system. X = (K’t)1/2 can be used if the surfaces are flat ...
... This eq. Can be used for different solid-solid reactions. Ex. silicate system. X = (K’t)1/2 can be used if the surfaces are flat ...
Chemistry 211 - George Mason University
... Often necessary to convert from one type of unit to another. • The method of dimensional analysis is used: – Multiply original number by conversion factors which change from one unit to another. – Conversion factor is the relationship between two units. ...
... Often necessary to convert from one type of unit to another. • The method of dimensional analysis is used: – Multiply original number by conversion factors which change from one unit to another. – Conversion factor is the relationship between two units. ...
AS specification - word format File
... changes but also to detect drugs such as alcohol. The unit deals with issues regarding the environment, such as climate change, the effect of greenhouse gases, carbon footprints and other aspects of green chemistry. It ensures that students understand the underlying chemistry and can investigate way ...
... changes but also to detect drugs such as alcohol. The unit deals with issues regarding the environment, such as climate change, the effect of greenhouse gases, carbon footprints and other aspects of green chemistry. It ensures that students understand the underlying chemistry and can investigate way ...
CHEMISTRY 1710 - Practice Exam #2 (KATZ)
... B) 2 K+(aq) + SO42-(aq) → K2SO4(s) C) H+(aq) + OH-(aq) + 2 K+(aq) + SO42-(aq) → H2O(l) + K2SO4(s) D) H22+(aq) + OH-(aq) → H2(OH)2(l) _____ 18. The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH solution. What is the concentration of the H2SO4 solution ...
... B) 2 K+(aq) + SO42-(aq) → K2SO4(s) C) H+(aq) + OH-(aq) + 2 K+(aq) + SO42-(aq) → H2O(l) + K2SO4(s) D) H22+(aq) + OH-(aq) → H2(OH)2(l) _____ 18. The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH solution. What is the concentration of the H2SO4 solution ...
chp0-Intro
... [O3] = 1.0 x 1012 molecules cm-3 x 1000 cm3/1 L x 1 mol/6.022 x 1023 molecules = 1.7 x 10-9 mol L-1 pV = nRT, p(O3) = (n/V) RT = 1.7 x 10-9 mol L-1 x 0.0821 L atm/mol K x 217 K = 3.0 x 10-8 atm p(O3) ppmv = (3.0 x 10-8 atm / 0.12 atm ) x 106 ppmv = 0.25 ppmv ...
... [O3] = 1.0 x 1012 molecules cm-3 x 1000 cm3/1 L x 1 mol/6.022 x 1023 molecules = 1.7 x 10-9 mol L-1 pV = nRT, p(O3) = (n/V) RT = 1.7 x 10-9 mol L-1 x 0.0821 L atm/mol K x 217 K = 3.0 x 10-8 atm p(O3) ppmv = (3.0 x 10-8 atm / 0.12 atm ) x 106 ppmv = 0.25 ppmv ...
Theoretical Study of Atomic Layer Deposition Reaction Mechanism
... that this is a barrierless adsorption process. From P4, the reaction proceeds to eliminate CH4 via the transition state, TS3, with an imaginary frequency of i1318 cm-1. The P5 + CH4 products and the transition state are below the reactants by 36.0 and 2.0 kcal/mol, respectively. As shown in Figure 4 ...
... that this is a barrierless adsorption process. From P4, the reaction proceeds to eliminate CH4 via the transition state, TS3, with an imaginary frequency of i1318 cm-1. The P5 + CH4 products and the transition state are below the reactants by 36.0 and 2.0 kcal/mol, respectively. As shown in Figure 4 ...
Electrons
... it is bonded to metals in binary compounds. In these cases, its oxidation number is____. 5. Group 1 metals are____, Group 2 metals are____and fluorine is always____. 6. The sum of the oxidation numbers of all the atoms in a molecule or ion is equal to the charge on the molecule or ion. 7. Oxidation ...
... it is bonded to metals in binary compounds. In these cases, its oxidation number is____. 5. Group 1 metals are____, Group 2 metals are____and fluorine is always____. 6. The sum of the oxidation numbers of all the atoms in a molecule or ion is equal to the charge on the molecule or ion. 7. Oxidation ...
Document
... b. Liquid: definite volume without a definite shape; particles are close together but can move past one another – particles in a liquid move more rapidly than those in a solid. ...
... b. Liquid: definite volume without a definite shape; particles are close together but can move past one another – particles in a liquid move more rapidly than those in a solid. ...
Thermodynamics (Part 2)
... coins? What are the possible combinations to achieve the macrostates? Which macrostate is most probable? Disorder is more probable than order because there are so many more ways of achieving it. ...
... coins? What are the possible combinations to achieve the macrostates? Which macrostate is most probable? Disorder is more probable than order because there are so many more ways of achieving it. ...
Final Review 2006
... a. formation of a precipitate c. evolution of heat and light b. production of a gas d. change in total mass of substances ____ 31. A solid produced by a chemical reaction in solution that separates from the solution is called a. a precipitate. c. a molecule. b. a reactant. d. the mass of the product ...
... a. formation of a precipitate c. evolution of heat and light b. production of a gas d. change in total mass of substances ____ 31. A solid produced by a chemical reaction in solution that separates from the solution is called a. a precipitate. c. a molecule. b. a reactant. d. the mass of the product ...
Chapter 3: Atoms: The Building Blocks of Matter
... Give general equations for synthesis, decomposition, combustion, single replacement, and double replacement reactions. Classify a reaction according to type. Predict the products of a reaction given the reactants. Explain the significance of the activity series. Use an activity series to p ...
... Give general equations for synthesis, decomposition, combustion, single replacement, and double replacement reactions. Classify a reaction according to type. Predict the products of a reaction given the reactants. Explain the significance of the activity series. Use an activity series to p ...
Catalytic, Enantioselective Alkylation of r
... (MeCN)n (3c)16 performed the best, giving high yield (91%) and selectivity at 0 °C (98% ee, entry 3). Demonstrating the utility of our process, similarly good ee was obtained eVen when this reaction was conducted at 0 °C in the presence of only 2 mol % catalyst (96% ee, entry 4). At this temperature ...
... (MeCN)n (3c)16 performed the best, giving high yield (91%) and selectivity at 0 °C (98% ee, entry 3). Demonstrating the utility of our process, similarly good ee was obtained eVen when this reaction was conducted at 0 °C in the presence of only 2 mol % catalyst (96% ee, entry 4). At this temperature ...