![Chemistry](http://s1.studyres.com/store/data/002946952_1-1643b0d49fe22ab4fa834d90c8f883e3-300x300.png)
Chemistry
... The use of a pocket calculator is permissible in the examination for ALL Chemistry modules. Note that students who have NOT passed Physical Science at Matriculation level must pass CHE111 and 112 BEFORE they register for any other modules in Chemistry. Students who register for modules in Chemistry ...
... The use of a pocket calculator is permissible in the examination for ALL Chemistry modules. Note that students who have NOT passed Physical Science at Matriculation level must pass CHE111 and 112 BEFORE they register for any other modules in Chemistry. Students who register for modules in Chemistry ...
chemical equilibrium
... 4 moles of NH3 in a 2-L vessel is allowed to come equilibrium at a total pressure of 3.6 atm. The number of mole of N2(g) in the equilibrium mixture is measured to be 1 mol. What is the Kp for the following reaction below? 2NH3(g) N2(g) + 3H2(g) Variation of Kc Expression The value of Kc changes b ...
... 4 moles of NH3 in a 2-L vessel is allowed to come equilibrium at a total pressure of 3.6 atm. The number of mole of N2(g) in the equilibrium mixture is measured to be 1 mol. What is the Kp for the following reaction below? 2NH3(g) N2(g) + 3H2(g) Variation of Kc Expression The value of Kc changes b ...
Example of Lab Notebook
... base to deprotonate the water soluble intermediate and to liberate the product. Following crystallization in an ice-water bath, the product underwent vacuum filtration to isolate. The product was dried and the purity of the product was assessed by running a melting point and by comparing the experim ...
... base to deprotonate the water soluble intermediate and to liberate the product. Following crystallization in an ice-water bath, the product underwent vacuum filtration to isolate. The product was dried and the purity of the product was assessed by running a melting point and by comparing the experim ...
Name:__Grading key
... Determine the impact of the indicator error choice on the volume of NaOH used by your teammate to reach the end point. Indicate (circle) the volume of NaOH used by your teammate at the end point. more than 2 points or zero ...
... Determine the impact of the indicator error choice on the volume of NaOH used by your teammate to reach the end point. Indicate (circle) the volume of NaOH used by your teammate at the end point. more than 2 points or zero ...
Hein and Arena - faculty at Chemeketa
... equilibrium, the system will respond in such a way as to relieve that stress and restore equilibrium under a new set of conditions. ...
... equilibrium, the system will respond in such a way as to relieve that stress and restore equilibrium under a new set of conditions. ...
CHEM110P1_06_2015_Y_P1
... A student used a titration to determine whether an unknown sample was malonic acid (CH2(COOH)2, molar mass = 104.1 g mol–1). The student weighed 1.08 g of the unknown acid and transferred it to a 250.0 mL volumetric flask and prepared a standard solution. The burette was filled with 0.09970 M NaOH s ...
... A student used a titration to determine whether an unknown sample was malonic acid (CH2(COOH)2, molar mass = 104.1 g mol–1). The student weighed 1.08 g of the unknown acid and transferred it to a 250.0 mL volumetric flask and prepared a standard solution. The burette was filled with 0.09970 M NaOH s ...
Topic 1 Review - Capital High School
... C. Each magnesium atom loses two electrons and each chlorine atom gains one electron. D. Each magnesium atom gains one electron and each chlorine atom loses two electrons. 6. Which is the best description of ionic bonding? A. The electrostatic attraction between positively charged nuclei and an elec ...
... C. Each magnesium atom loses two electrons and each chlorine atom gains one electron. D. Each magnesium atom gains one electron and each chlorine atom loses two electrons. 6. Which is the best description of ionic bonding? A. The electrostatic attraction between positively charged nuclei and an elec ...
Student 2 response
... and allowed to react until there until no more bubbles were evolved. Some HCl did not react and remained in the reaction mixture. CaCO3 + 2 HCl CaCl2 + CO2 + H2O Step 2: The HCl which did not react was titrated with a standardised solution of NaOH of concentration 0.200 mol L1. NaOH + HCl NaCl ...
... and allowed to react until there until no more bubbles were evolved. Some HCl did not react and remained in the reaction mixture. CaCO3 + 2 HCl CaCl2 + CO2 + H2O Step 2: The HCl which did not react was titrated with a standardised solution of NaOH of concentration 0.200 mol L1. NaOH + HCl NaCl ...
IB Chemistry Review. Unit I. Topics 2
... C. Each magnesium atom loses two electrons and each chlorine atom gains one electron. D. Each magnesium atom gains one electron and each chlorine atom loses two electrons. 6. Which is the best description of ionic bonding? A. The electrostatic attraction between positively charged nuclei and an elec ...
... C. Each magnesium atom loses two electrons and each chlorine atom gains one electron. D. Each magnesium atom gains one electron and each chlorine atom loses two electrons. 6. Which is the best description of ionic bonding? A. The electrostatic attraction between positively charged nuclei and an elec ...
Chemistry
... promote an awareness that: 5.1 the study and practice of science are co-operative and cumulative activities, and are subject to social, economic, technological, ethical and cultural influences and limitations 5.2 the applications of science may be both beneficial and detrimental to the individual, t ...
... promote an awareness that: 5.1 the study and practice of science are co-operative and cumulative activities, and are subject to social, economic, technological, ethical and cultural influences and limitations 5.2 the applications of science may be both beneficial and detrimental to the individual, t ...
Enzyme Activity
... – Lower temperature T° • molecules move slower • fewer collisions between enzyme & substrate ...
... – Lower temperature T° • molecules move slower • fewer collisions between enzyme & substrate ...
IOSR Journal of Applied Chemistry (IOSR-JAC)
... excellent activity when aromatic substitutions are present at 2- and/or 6-positions. Mannich reaction is one of the multi-component reactions for the carbon-carbon and carbon heteroatom sequential bond formation. Mannich type condensation involving aromatic aldehydes, ammonium acetate and ketones ha ...
... excellent activity when aromatic substitutions are present at 2- and/or 6-positions. Mannich reaction is one of the multi-component reactions for the carbon-carbon and carbon heteroatom sequential bond formation. Mannich type condensation involving aromatic aldehydes, ammonium acetate and ketones ha ...
do not
... How do enzymes work? 1) Enzymes act upon a substance called a substrate 2) The enzyme has an indent in it called the active site where the substrate can fit into, kind of like a lock and a key ...
... How do enzymes work? 1) Enzymes act upon a substance called a substrate 2) The enzyme has an indent in it called the active site where the substrate can fit into, kind of like a lock and a key ...
do not - wwphs
... How do enzymes work? 1) Enzymes act upon a substance called a substrate 2) The enzyme has an indent in it called the active site where the substrate can fit into, kind of like a lock and a key ...
... How do enzymes work? 1) Enzymes act upon a substance called a substrate 2) The enzyme has an indent in it called the active site where the substrate can fit into, kind of like a lock and a key ...
Stoichometry Notes (Unit 2)
... represents a chemical reaction in which two diatomic hydrogen (gas) molecules react with one diatomic oxygen (gas) molecule react to yield two water (liquid) molecules. Hydrogen and oxygen are the reactants (a.k.a. reagents) and water is the product. The “à” symbol separates the reactant(s) from the ...
... represents a chemical reaction in which two diatomic hydrogen (gas) molecules react with one diatomic oxygen (gas) molecule react to yield two water (liquid) molecules. Hydrogen and oxygen are the reactants (a.k.a. reagents) and water is the product. The “à” symbol separates the reactant(s) from the ...
Combined
... 6. Chlorine has a relative atomic mass of 35.5 and has two isotopes with relative isotopic masses of 35 and 37. Which of the following statements about chlorine are CORRECT? (1) The isotopes have same atomic number. (2) It contains the two isotopes, chlorine-35 and chlorine-37, in a ratio of 1:3. (3 ...
... 6. Chlorine has a relative atomic mass of 35.5 and has two isotopes with relative isotopic masses of 35 and 37. Which of the following statements about chlorine are CORRECT? (1) The isotopes have same atomic number. (2) It contains the two isotopes, chlorine-35 and chlorine-37, in a ratio of 1:3. (3 ...
Past AP FRQ`s Linked to Text Chapters
... ionized. Omit formulas for any ions or molecules that are unchanged by the reaction. In all cases a reaction occurs. You need not balance. Example: A strip of magnesium is added to a solution of silver nitrate. (a) Solutions of zinc sulfate and sodium phosphate are mixed. (b) Solutions of silver ni ...
... ionized. Omit formulas for any ions or molecules that are unchanged by the reaction. In all cases a reaction occurs. You need not balance. Example: A strip of magnesium is added to a solution of silver nitrate. (a) Solutions of zinc sulfate and sodium phosphate are mixed. (b) Solutions of silver ni ...
Chemistry Test Ch 11 Stoichiometry
... If 18.5 grams of Fe2(SO4)3 are actually made what is the percent yield? 5. Use the following equation answer these questions: C12H22O11 + 12O2 ---> 12CO2 + 11H2O A. If 3.45 g CO2 is produced how many water molecules are also produced? B. If there are 10.0 g of C12H22O11 and 10.0 g of oxygen reacting ...
... If 18.5 grams of Fe2(SO4)3 are actually made what is the percent yield? 5. Use the following equation answer these questions: C12H22O11 + 12O2 ---> 12CO2 + 11H2O A. If 3.45 g CO2 is produced how many water molecules are also produced? B. If there are 10.0 g of C12H22O11 and 10.0 g of oxygen reacting ...
Part II
... Free radicals – have unpaired electron(s). Atmospheric lifetimes seconds, minutes. e.g., •O-H radical, missing one bond (H), wants to steal one from somewhere. Similar story for •CH3 radical, missing one bond. Or the HO2 radical, H-O-O• These free radicals are usually generated by sunlight (photoche ...
... Free radicals – have unpaired electron(s). Atmospheric lifetimes seconds, minutes. e.g., •O-H radical, missing one bond (H), wants to steal one from somewhere. Similar story for •CH3 radical, missing one bond. Or the HO2 radical, H-O-O• These free radicals are usually generated by sunlight (photoche ...
Heat
... The formation reaction for a substance is defined as the reaction that produces one mole of a single product out of elements in their standard state. Because of the way we have defined the formation reaction, we may have to use fractional stoichiometric coefficients for some or all of the reactants. ...
... The formation reaction for a substance is defined as the reaction that produces one mole of a single product out of elements in their standard state. Because of the way we have defined the formation reaction, we may have to use fractional stoichiometric coefficients for some or all of the reactants. ...