Reaction Analysis and PAT Tools
... iC IR™ software was designed to take infrared data and convert it into useful and meaningful information about chemical reactions, in real time. The result of an extensive research project on how scientists analyze reactions, iC IR allows chemists and engineers to quickly gain an understanding of th ...
... iC IR™ software was designed to take infrared data and convert it into useful and meaningful information about chemical reactions, in real time. The result of an extensive research project on how scientists analyze reactions, iC IR allows chemists and engineers to quickly gain an understanding of th ...
The first practical method for asymmetric epoxidation
... The procedure described above for epoxidation of geraniol calls for 1 equiv of both titanium isopropoxide and diethyl tartrate. This is by no means necessary in all cases. With reactive allylic alcohols (la, 2a, 3a, and 4a in Table I), a catalytic amount (e.g., 0.1 equiv) of both Ti(O-i-Pr)4 and die ...
... The procedure described above for epoxidation of geraniol calls for 1 equiv of both titanium isopropoxide and diethyl tartrate. This is by no means necessary in all cases. With reactive allylic alcohols (la, 2a, 3a, and 4a in Table I), a catalytic amount (e.g., 0.1 equiv) of both Ti(O-i-Pr)4 and die ...
Sample Final Questions Key/FS12
... e. John Dalton (Gas Laws) showed that the partial pressure of each gas contributes to the total pressure. f. Johannes Diderik van der Waals (Gas Laws) revised the ideal gas law equation so that it can be used for real gases. g. Henri Becquerel (Nuclear) while studying fluorescence determined that so ...
... e. John Dalton (Gas Laws) showed that the partial pressure of each gas contributes to the total pressure. f. Johannes Diderik van der Waals (Gas Laws) revised the ideal gas law equation so that it can be used for real gases. g. Henri Becquerel (Nuclear) while studying fluorescence determined that so ...
Physical Science Chapter 7 Chemical Reactions Section 7.1
... _______________________________________________________ When geologists test the calcium carbonate content in a rock, they use a double-replacement reaction. _______________________________________________________ The product carbonic acid,H2CO3, then decomposes into carbon dioxide gas and water. __ ...
... _______________________________________________________ When geologists test the calcium carbonate content in a rock, they use a double-replacement reaction. _______________________________________________________ The product carbonic acid,H2CO3, then decomposes into carbon dioxide gas and water. __ ...
Oxygen Removal in Natural Gas Systems
... There are a number of commercially available catalytic oxidation processes, some of which are described below: ...
... There are a number of commercially available catalytic oxidation processes, some of which are described below: ...
Chem 171 Review Exam 2
... a. Calculate the mass of Fe2O3 that is produced from the reaction of 75.0 L of O2 at 2.33 atm and 150˚C with an excess of iron pyrite. b. The sulfur dioxide that is generated in (a) is dissolved in water to form 5.00 L of aqueous solution. What is the molar concentration of the resulting sulfurous a ...
... a. Calculate the mass of Fe2O3 that is produced from the reaction of 75.0 L of O2 at 2.33 atm and 150˚C with an excess of iron pyrite. b. The sulfur dioxide that is generated in (a) is dissolved in water to form 5.00 L of aqueous solution. What is the molar concentration of the resulting sulfurous a ...
Rapid Microwave Synthesis, Characterization and Reactivity
... of the phase requires the solid state reaction of Li3N and LiH at high temperature under strictly anaerobic conditions while preventing side reactions with container materials. In this work we demonstrate how microwave synthesis of Li4NH using both commercial multi-mode and single-mode microwave (MW ...
... of the phase requires the solid state reaction of Li3N and LiH at high temperature under strictly anaerobic conditions while preventing side reactions with container materials. In this work we demonstrate how microwave synthesis of Li4NH using both commercial multi-mode and single-mode microwave (MW ...
Fall 2008 Blank Final Exam
... I have learned to appreciate life; I have stopped to smell the roses, I have seen beauty where I had not seen beauty before, and I am grateful for those around me. ...
... I have learned to appreciate life; I have stopped to smell the roses, I have seen beauty where I had not seen beauty before, and I am grateful for those around me. ...
Key
... boiling. For CH3 Cl and CH3 SH, London forces are comparable. You could guess that because CH3 Cl has a larger dipole moment, it will boil higher than CH3 SH. As it happens, weak hydrogen bonding makes CH3 SH boil higher. Either ordering of CH3 Cl and CH3 SH will be marked as correct, if reasonably ...
... boiling. For CH3 Cl and CH3 SH, London forces are comparable. You could guess that because CH3 Cl has a larger dipole moment, it will boil higher than CH3 SH. As it happens, weak hydrogen bonding makes CH3 SH boil higher. Either ordering of CH3 Cl and CH3 SH will be marked as correct, if reasonably ...
Chemistry (English) Grade 11 and 12
... hold the molecules of the species together; that is, the easier it is to break the bonds, the lower the boiling point will be. The more carbon atoms an alkane molecule has the more places are available for induced dipole – induced dipole “bonds” to form, so that more energy is needed to break the “b ...
... hold the molecules of the species together; that is, the easier it is to break the bonds, the lower the boiling point will be. The more carbon atoms an alkane molecule has the more places are available for induced dipole – induced dipole “bonds” to form, so that more energy is needed to break the “b ...
Equilibrium (Sheet 1)
... increasing the concentration of the products and the equilibrium will shift to the left. On the other hand, if the concentration of steam or the concentration of carbon monoxide or both are decreased, then the equilibrium will shift to the left. Decreasing the concentration of either the hydrogen or ...
... increasing the concentration of the products and the equilibrium will shift to the left. On the other hand, if the concentration of steam or the concentration of carbon monoxide or both are decreased, then the equilibrium will shift to the left. Decreasing the concentration of either the hydrogen or ...
Day 13 Main Group Pt 1
... A. Introduction. Hydrogen is one of the most unique elements of the periodic table. Most people live their entire lives without ever encountering molecular hydrogen — yet we are constantly in contact with and dependent on compounds of hydrogen. The most familiar compound of hydrogen is water. Hydrog ...
... A. Introduction. Hydrogen is one of the most unique elements of the periodic table. Most people live their entire lives without ever encountering molecular hydrogen — yet we are constantly in contact with and dependent on compounds of hydrogen. The most familiar compound of hydrogen is water. Hydrog ...
Thermodynamics Practice Problems Presentation
... 1 mol each of H–H and F–F bonds are broken The bonds formed are 2 mol of H–F bonds ∆H= (nH-HDH-H + nF-FDF-F) – nH-FDH-F (1 mol x 432KJ) + (1 mol x 154 KJ) - (2 mol x 565 KJ mol mol mol ∆H = -544 KJ The enthalpy change for the reaction of 1 mol hydrogen gas and 1 mol fluorine gas to ptoduce 2 mol. Hy ...
... 1 mol each of H–H and F–F bonds are broken The bonds formed are 2 mol of H–F bonds ∆H= (nH-HDH-H + nF-FDF-F) – nH-FDH-F (1 mol x 432KJ) + (1 mol x 154 KJ) - (2 mol x 565 KJ mol mol mol ∆H = -544 KJ The enthalpy change for the reaction of 1 mol hydrogen gas and 1 mol fluorine gas to ptoduce 2 mol. Hy ...
6.02 × 1023 molecules = 1 mole
... At the most fundamental level, the chemist needs a unit that describes a very large quantity. ...
... At the most fundamental level, the chemist needs a unit that describes a very large quantity. ...
ACP Chemistry Semester 1 Final Exam - Doc-U-Ment
... D) AgC2H3O2 + Cu(NO3)2 E) None of the above solution pairs will produce a precipitate. 12) Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Na2CO3 and HCl are mixed. A) 2 H+(aq) + CO32-(aq) → H2CO3(s) B) 2 Na+(aq) + CO32-(aq) + 2 H+(aq) + 2 Cl-(aq) → H2CO3( ...
... D) AgC2H3O2 + Cu(NO3)2 E) None of the above solution pairs will produce a precipitate. 12) Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Na2CO3 and HCl are mixed. A) 2 H+(aq) + CO32-(aq) → H2CO3(s) B) 2 Na+(aq) + CO32-(aq) + 2 H+(aq) + 2 Cl-(aq) → H2CO3( ...
Chemistry (B) Final Exam Study Guide 3
... ____ 46. Symbols used in equations, together with the explanations of the symbols, are shown below. Which set is correct? a. (g), grams c. (aq), dissolved in water b. (l), liters d. s, solid product ____ 47. A catalyst is ____. a. the product of a combustion reaction b. not used up in a reaction c ...
... ____ 46. Symbols used in equations, together with the explanations of the symbols, are shown below. Which set is correct? a. (g), grams c. (aq), dissolved in water b. (l), liters d. s, solid product ____ 47. A catalyst is ____. a. the product of a combustion reaction b. not used up in a reaction c ...
IGCSE Revision Guide (Double Award) | PDF
... Use dot and cross diagrams to show how ions are formed from atoms, limited to compounds involving Li+, Na+, K+, Mg2+, Al3+, F-‐, Cl-‐, O2-‐, S2-‐ and N3-‐. Say that the similarity of chemica ...
... Use dot and cross diagrams to show how ions are formed from atoms, limited to compounds involving Li+, Na+, K+, Mg2+, Al3+, F-‐, Cl-‐, O2-‐, S2-‐ and N3-‐. Say that the similarity of chemica ...
practice problems of chap4_5 - Chemistry
... Hint: p.p. 124-126. Examples 4.1 & 4.2. Check with the solubility table for the produ cts, which must be solids (s), liquids (l) or gases (g). 4. Which of the following is a Brǿnsted acid? (a) HCO3(b) CH3COO(c) S2(d) SO4(e) NO3Hint: p. 128. Example 4.3. Definition. Brǿnsted acids must contain availa ...
... Hint: p.p. 124-126. Examples 4.1 & 4.2. Check with the solubility table for the produ cts, which must be solids (s), liquids (l) or gases (g). 4. Which of the following is a Brǿnsted acid? (a) HCO3(b) CH3COO(c) S2(d) SO4(e) NO3Hint: p. 128. Example 4.3. Definition. Brǿnsted acids must contain availa ...
Unit 8 Packet
... 3. When 0.50 mole of aluminum reacts with 0.72 mole of iodine to form aluminum iodide, how many moles of the excess reactant will remain? ____________ How many moles of aluminum iodide will be formed? _____________ Bal. Equation: Before: __________________________________________ Change:___________ ...
... 3. When 0.50 mole of aluminum reacts with 0.72 mole of iodine to form aluminum iodide, how many moles of the excess reactant will remain? ____________ How many moles of aluminum iodide will be formed? _____________ Bal. Equation: Before: __________________________________________ Change:___________ ...
Gas Volumes and the Ideal Gas Law
... Recall an important point of Dalton’s atomic theory: atoms are indivisible. Dalton also thought that the particles of gaseous elements exist in the form of isolated single atoms. He believed that one atom of one element always combines with one atom of another element to form a single particle of th ...
... Recall an important point of Dalton’s atomic theory: atoms are indivisible. Dalton also thought that the particles of gaseous elements exist in the form of isolated single atoms. He believed that one atom of one element always combines with one atom of another element to form a single particle of th ...
Topic 14 - Fertilisers
... Ammonia reacts with acids to make ammonium salts which can be used as fertilisers. NH3 + HNO3 ...
... Ammonia reacts with acids to make ammonium salts which can be used as fertilisers. NH3 + HNO3 ...
chemical reaction
... energy. • 2. Make the following TRUE: The rate of a reaction can be increased by adding an inhibitor. • 3. Which of the following will not increase the rate of a reaction? ...
... energy. • 2. Make the following TRUE: The rate of a reaction can be increased by adding an inhibitor. • 3. Which of the following will not increase the rate of a reaction? ...
2.4 Chemical equilibria
... The higher the pressure the more the reaction moves in the direction with less gas molecules. • Increasing the pressure will give more N2O4 • Decreasing pressure gives more NO2 at equilibrium.. ...
... The higher the pressure the more the reaction moves in the direction with less gas molecules. • Increasing the pressure will give more N2O4 • Decreasing pressure gives more NO2 at equilibrium.. ...
Chemistry 20 Lesson 36 – The Whole Enchilada
... Suppose you are given four, unlabelled beakers, each containing a colorless aqueous solution of one solute. The possible solutions are NaCl(aq), HCl(aq), Ba(OH)2 (aq), and CH3Cl(aq). Write a series of diagnostic tests to distinguish each solution from the others. ...
... Suppose you are given four, unlabelled beakers, each containing a colorless aqueous solution of one solute. The possible solutions are NaCl(aq), HCl(aq), Ba(OH)2 (aq), and CH3Cl(aq). Write a series of diagnostic tests to distinguish each solution from the others. ...
Catalytic reforming
Catalytic reforming is a chemical process used to convert petroleum refinery naphthas distilled from crude oil (typically having low octane ratings) into high-octane liquid products called reformates, which are premium blending stocks for high-octane gasoline. The process converts low-octane linear hydrocarbons (paraffins) into branched alkanes (isoparaffins) and cyclic naphthenes, which are then partially dehydrogenated to produce high-octane aromatic hydrocarbons. The dehydrogenation also produces significant amounts of byproduct hydrogen gas, which is fed into other refinery processes such as hydrocracking. A side reaction is hydrogenolysis, which produces light hydrocarbons of lower value, such as methane, ethane, propane and butanes.In addition to a gasoline blending stock, reformate is the main source of aromatic bulk chemicals such as benzene, toluene, xylene and ethylbenzene which have diverse uses, most importantly as raw materials for conversion into plastics. However, the benzene content of reformate makes it carcinogenic, which has led to governmental regulations effectively requiring further processing to reduce its benzene content.This process is quite different from and not to be confused with the catalytic steam reforming process used industrially to produce products such as hydrogen, ammonia, and methanol from natural gas, naphtha or other petroleum-derived feedstocks. Nor is this process to be confused with various other catalytic reforming processes that use methanol or biomass-derived feedstocks to produce hydrogen for fuel cells or other uses.