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... • During a test crash, an air bag inflates to stop a dummy’s forward motion. The dummy’s mass is 75.0 kg. If the net force on the dummy is 825. N toward the rear of the car, what is the dummy’s acceleration? ...
... • During a test crash, an air bag inflates to stop a dummy’s forward motion. The dummy’s mass is 75.0 kg. If the net force on the dummy is 825. N toward the rear of the car, what is the dummy’s acceleration? ...
Answers for chapters5,6 and 7
... (d) Plugging = 23° into the above result for F, with s = 0.42 and W = 180 N, yields F 70 N . 44. The magnitude of the acceleration of the car as it rounds the curve is given by v2/R, where v is the speed of the car and R is the radius of the curve. Since the road is horizontal, only the frictio ...
... (d) Plugging = 23° into the above result for F, with s = 0.42 and W = 180 N, yields F 70 N . 44. The magnitude of the acceleration of the car as it rounds the curve is given by v2/R, where v is the speed of the car and R is the radius of the curve. Since the road is horizontal, only the frictio ...
First--Inertia (see above for this law in detail)
... When the net force is zero, there are balanced forces and there is no change in motion. To achieve a net force of zero means that an applied force balances the force of friction so that the combined force acting on the object is zero. (Ex. Tug-of-War, when there is a deadlock and no one is able to m ...
... When the net force is zero, there are balanced forces and there is no change in motion. To achieve a net force of zero means that an applied force balances the force of friction so that the combined force acting on the object is zero. (Ex. Tug-of-War, when there is a deadlock and no one is able to m ...
Projectile Motion
... • When we combine the x- and y-components, we get the characteristic parabola-shape – Vx remains constant (a = 0) – Vy changes because of gravity (a = -9.8 m/s2) ...
... • When we combine the x- and y-components, we get the characteristic parabola-shape – Vx remains constant (a = 0) – Vy changes because of gravity (a = -9.8 m/s2) ...
Unit 2 AP Forces Practice Problems
... *Together a bike and its rider have a mass of 275 Kg. The bike is slowed down with an acceleration of –4.5 m/s/s. What is the net force on the bike? Describe the direction of the force and the meaning of the negative sign. (1.24 E3 N; Fnet is opposite dxn of motion) 2. A car with a mass of 1225 Kg, ...
... *Together a bike and its rider have a mass of 275 Kg. The bike is slowed down with an acceleration of –4.5 m/s/s. What is the net force on the bike? Describe the direction of the force and the meaning of the negative sign. (1.24 E3 N; Fnet is opposite dxn of motion) 2. A car with a mass of 1225 Kg, ...
Unit_4_AP_Review_Problems_Momentum,_Work,_Power,_Energy
... direction, which of the following scenarios will enable you to catch it barehanded so the pain (force) to your hand is the smallest: Should you move your hands toward the ball thereby decreasing the time of the ball’s momentum change, hold them still, or move them in the same direction as the ball i ...
... direction, which of the following scenarios will enable you to catch it barehanded so the pain (force) to your hand is the smallest: Should you move your hands toward the ball thereby decreasing the time of the ball’s momentum change, hold them still, or move them in the same direction as the ball i ...
Chapter 4 Force
... We often split these pairs up into the action force and the reaction force, which are always have the same magnitude but opposite directions. Action/reaction pairs can cancel each other out which results in equilibrium. Action/reaction pairs can also accelerate objects (see action/reaction han ...
... We often split these pairs up into the action force and the reaction force, which are always have the same magnitude but opposite directions. Action/reaction pairs can cancel each other out which results in equilibrium. Action/reaction pairs can also accelerate objects (see action/reaction han ...
Accelerating or· Braking on Turns
... Everyone has experienced centripetal force in one way or another. Centripetal force allows you, or forces you, in certain circumstances, to go around corners. Without centripetal force, or a force towards the center of a circle, you would instead travel in a straight line. The centripetal force for ...
... Everyone has experienced centripetal force in one way or another. Centripetal force allows you, or forces you, in certain circumstances, to go around corners. Without centripetal force, or a force towards the center of a circle, you would instead travel in a straight line. The centripetal force for ...
Lecture09-09
... to the block, and is pulled with a force of 45.0 N at an angle above the horizontal, as shown in the figure. After the block is pulled through a distance of 1.50 m, its speed is 2.60 m/s, and 50.0 J of work has been done on it. (a) What is the angle (b) What is the mass of the block? ...
... to the block, and is pulled with a force of 45.0 N at an angle above the horizontal, as shown in the figure. After the block is pulled through a distance of 1.50 m, its speed is 2.60 m/s, and 50.0 J of work has been done on it. (a) What is the angle (b) What is the mass of the block? ...
Force Vectors 1
... • The angle for minimum tension in rope 2 is determined by applying the Triangle Rule and observing the effect of variations in . • The minimum tension in rope 2 occurs when T1 and T2 are perpendicular. T2 5000 lbf sin 30 ...
... • The angle for minimum tension in rope 2 is determined by applying the Triangle Rule and observing the effect of variations in . • The minimum tension in rope 2 occurs when T1 and T2 are perpendicular. T2 5000 lbf sin 30 ...
