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Monday, November 15, 2010
Monday, November 15, 2010

... 1.  A ball of mass M at rest is dropped from the height h above the ground onto a spring on the ground, whose spring constant is k. Neglecting air resistance and assuming that the spring is in its equilibrium, express, in terms of the quantities given in this problem and the gravitational accelerati ...
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... understanding of how objects move when projected through the air. See how promising a career as a motocross rider, stunt person, or bow-hunter might be for you. Click here to view this applet. Circular Motion - Balls on Strings The Circular Motion applet is designed for users to examine the basic id ...
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... the MAR industrial manipulator is presented. The mathematical analysis of vibrations is based on the perturbation method. The presented considerations include an analytical description of inertial vibrations as well as results of the numerical analysis for the RPP– type manipulator. Keywords: Robot ...
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... words, it is in equilibrium. Two horizontal forces act on the plane. One is the thrust of the propeller that pulls it forward. The other is the force of air resistance (air friction) that acts in the opposite direction. Which force is greater? Answer: Neither, for both forces have the same strength. ...
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... the electric force on the test charge is the same as that of the field vector. Confusion is avoided. Physics for Scientists and Engineers II , Summer Semester 2009 ...
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... If you pull on a spring, the spring stretches. If you pull on a wagon, the wagon moves. When a football is caught, its motion is stopped. These pushes and pulls are examples of contact forces, which are so named because they result from physical contact between two objects. Contact forces are usuall ...
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... You like to drive home fast, slam on your brakes at the start of the driveway, and screech to a stop “laying rubber” all the way. It’s particularly fun when your mother is in the car with you. You practice this trick driving at 20 mph and with some groceries in your car with the same mass as your mo ...
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... center-of-mass has zero acceleration. For stationary objects, in the absence of external forces: One or more parts of the system can move, but other parts must move in response to keep the center-of-mass in the same place. Internal forces cannot change the position of the center-of-mass. ...
Finding Safer Roofing Shoes - Delaware Valley Regional High School
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... 1. Prepare two sets of blank data tables like the ones shown in the Data Tables section. The first two tables will be for the static friction and kinetic friction, respectively, of the first shoe. The second two tables will be for the static friction and kinetic friction of the second shoe. 2. If th ...
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... (1) if every particle that passes a particular point moves along exactly the same smooth path followed by previous particles passing the point, this path is called streamline. If this happens, this flow is said to be streamline or laminar. (2) the flow of a fluid becomes irregular, or turbulent, abo ...
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... Problem No. 10 : A machine foundation supported by a soil layer can be approximated as a mass-spring-dashpot system. The weight of foundation with machine is 800kN. The stiffness constant k is 200x10^3 kN/m and damping constant c is 2340kN-sec/m a) Determine critical damping coefficient, damping rat ...
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... and the base of the swing has a mass of 153 g. Assume that the swing and bird are originally at rest and that the bird takes off horizontally at 2.00 m/s. If the base can swing freely (without friction) around the pivot, how high will the base of the swing rise above its original level? How many obj ...
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... High mass objects can have low momentum when they have low velocities; low mass objects can have high momentum when they have high velocities. The more momentum an object has, the harder it is to stop. Newton's second law of motion expressed in terms of momentum states that the rate of change in mom ...
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... From Newton's 3rd, for every force there is an equal and opposite reaction. Thus all the internal forces sum to zero: In an analogous way, all the internal torques also sum to zero: ...Thus L =  ext t Then if all of the external torques sum to zero, we have L = 0 t which implies that L = a ...
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Centripetal force

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