Lesson 1: Newton`s First Law of Motion
... Newton's First Law of Motion Newton's First Law Newton's first law of motion – sometimes referred to as the "law of inertia." An object at rest tends to stay at rest and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force ...
... Newton's First Law of Motion Newton's First Law Newton's first law of motion – sometimes referred to as the "law of inertia." An object at rest tends to stay at rest and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force ...
Magnetic Force Acting on a Current
... • if the field is directed in the x direction, as shown in Figure, there is no component of force in the x direction. As a result, ax =0, and the x component of velocity remains constant. • However, the magnetic force q v x B causes the components v and v to change in time, and the resulting motion ...
... • if the field is directed in the x direction, as shown in Figure, there is no component of force in the x direction. As a result, ax =0, and the x component of velocity remains constant. • However, the magnetic force q v x B causes the components v and v to change in time, and the resulting motion ...
Problem 5.1 An electron with a speed of 8 × 10 6 m/s is projected
... positive x-direction into a medium containing a uniform magnetic flux density B = (x̂4 − ẑ3) T. Given that e = 1.6 × 10−19 C and the mass of an electron is me = 9.1 × 10−31 kg, determine the initial acceleration vector of the electron (at the moment it is projected into the medium). Solution: The a ...
... positive x-direction into a medium containing a uniform magnetic flux density B = (x̂4 − ẑ3) T. Given that e = 1.6 × 10−19 C and the mass of an electron is me = 9.1 × 10−31 kg, determine the initial acceleration vector of the electron (at the moment it is projected into the medium). Solution: The a ...
NEWTON`S LAWS OF MOT ION, FRICTION
... Gravitational force is normally considered to be analogous to electrostatic Coulomb’s force. In case of Gravitational force, G is universal constant. In case of Coulomb’s force, the constant K is not universal. K depends on the medium. When you hit the table, you feel pain; this is due to the normal ...
... Gravitational force is normally considered to be analogous to electrostatic Coulomb’s force. In case of Gravitational force, G is universal constant. In case of Coulomb’s force, the constant K is not universal. K depends on the medium. When you hit the table, you feel pain; this is due to the normal ...
Practice Problems – Weight, Normal Force, and Tension Physics
... For all problems assume air resistance is negligible. You are encouraged to use g = 10 m/s/s for this activity. 1. (Level 2) A box with a mass of 10 kg is resting on the ground. a. Draw a free body diagram of the box. b. What is the net force on the object. c. Calculate the force due to gravity of t ...
... For all problems assume air resistance is negligible. You are encouraged to use g = 10 m/s/s for this activity. 1. (Level 2) A box with a mass of 10 kg is resting on the ground. a. Draw a free body diagram of the box. b. What is the net force on the object. c. Calculate the force due to gravity of t ...
Momentum
... • Define unknown terms Take notes for your SQ4R on a separate sheet and staple to your momentum and collision worksheet ...
... • Define unknown terms Take notes for your SQ4R on a separate sheet and staple to your momentum and collision worksheet ...
ExamView - C_Rotation_MC_2008 practice.tst
... B) his angular velocity remains the same. E) his rotational inertia decreases. C) his angular momentum remains the same. 15. A top spinning on the floor precesses because the torque due to gravity, about the point of contact of the top with the floor, is: A) parallel to the angular momentum vector. ...
... B) his angular velocity remains the same. E) his rotational inertia decreases. C) his angular momentum remains the same. 15. A top spinning on the floor precesses because the torque due to gravity, about the point of contact of the top with the floor, is: A) parallel to the angular momentum vector. ...
B - AQA
... The steel cylinder Q is a strong permanent magnet. P and Q are released separately from the top of a long, vertical copper tube so that they pass down the centre of the tube, as shown in Figure 5. Figure 5 metal cylinder P or Q ...
... The steel cylinder Q is a strong permanent magnet. P and Q are released separately from the top of a long, vertical copper tube so that they pass down the centre of the tube, as shown in Figure 5. Figure 5 metal cylinder P or Q ...
pre-lab preparation sheet for lab 11
... force exerted by a spring increases the more you stretch the spring. In this lab you will learn how to measure and calculate the work done by any force that acts on a moving object (even a force that changes with time). Often it is useful to know both the total amount of work that is done, and also ...
... force exerted by a spring increases the more you stretch the spring. In this lab you will learn how to measure and calculate the work done by any force that acts on a moving object (even a force that changes with time). Often it is useful to know both the total amount of work that is done, and also ...
Chapter 12 Equilibrium and Elasticity
... 1. The linear momentum P of the center of mass is constant. 2. The angular momentum L about the center of mass or any other point is a constant. Our concern in this chapter is with situations in which P 0 and L 0. That is, we are interested in objects that are not moving in any way (this include ...
... 1. The linear momentum P of the center of mass is constant. 2. The angular momentum L about the center of mass or any other point is a constant. Our concern in this chapter is with situations in which P 0 and L 0. That is, we are interested in objects that are not moving in any way (this include ...
Presentation
... to take the path that gently winds around the mountain, even though it is 8 times longer than the steep path. They both eventually reach the top of the mountain, but Alice reaches the top in 1/3 the time that Bill takes using the steep route. How does the work that Alice did in climbing the mountain ...
... to take the path that gently winds around the mountain, even though it is 8 times longer than the steep path. They both eventually reach the top of the mountain, but Alice reaches the top in 1/3 the time that Bill takes using the steep route. How does the work that Alice did in climbing the mountain ...
sy30_may10_s12
... Proportional to the mass ( m1m2 ) Inversely proportional to the distance (1/r) Circular orbits: Dynamical quantities (v,E,K,U,F) involve radius K(r) = - ½ U(r) Employ conservation of angular momentum in elliptical orbits No need to derive Kepler’s Laws (know the reasons for them) Energy transf ...
... Proportional to the mass ( m1m2 ) Inversely proportional to the distance (1/r) Circular orbits: Dynamical quantities (v,E,K,U,F) involve radius K(r) = - ½ U(r) Employ conservation of angular momentum in elliptical orbits No need to derive Kepler’s Laws (know the reasons for them) Energy transf ...
