Ahmed Tarek Reda sec(1)
... be easily implemented. The thermistor offers a low resistance at high temperature and high resistance at low temperature. This phenomenon is employed here for sensing the fire. The IC1 (NE555) is configured as a free running oscillator at audio frequency. The transistors T1 and T2 drive IC1. The out ...
... be easily implemented. The thermistor offers a low resistance at high temperature and high resistance at low temperature. This phenomenon is employed here for sensing the fire. The IC1 (NE555) is configured as a free running oscillator at audio frequency. The transistors T1 and T2 drive IC1. The out ...
OHMS LAW
... Ohm’s Law explains the relationship between voltage (V ), current (I) and resistance (R) Used by electricians, automotive technicians, stereo installers ...
... Ohm’s Law explains the relationship between voltage (V ), current (I) and resistance (R) Used by electricians, automotive technicians, stereo installers ...
circuits and current review
... 1. What two things are needed for charge to flow between two points? 2. What is actually flowing in a current carrying wire? 3. What is an ampere? 4. The resistance of a wire depends on what three factors? 5. Which has more resistance, a thick wire or a thin wire? 6. What is the unit of resistance? ...
... 1. What two things are needed for charge to flow between two points? 2. What is actually flowing in a current carrying wire? 3. What is an ampere? 4. The resistance of a wire depends on what three factors? 5. Which has more resistance, a thick wire or a thin wire? 6. What is the unit of resistance? ...
Reverse polarity and overvoltage protection
... combination with a fuse. But you can do it better. First, the diode in series can be replaced by Pchannel MOSFET (Q1). Drain connected to input and source to output. Gate is connected to ground. The transistor appears to be reversed and it is. But on purpose. Suppose the voltage is reversed. Then, g ...
... combination with a fuse. But you can do it better. First, the diode in series can be replaced by Pchannel MOSFET (Q1). Drain connected to input and source to output. Gate is connected to ground. The transistor appears to be reversed and it is. But on purpose. Suppose the voltage is reversed. Then, g ...
Voltage Regulator
... • IC 723 has unregulated dc supply at input between 11.5 V to 40 V. It can withstand maximum load current of 150 mA. Internal power dissipation is about 800 mW. It has low temperature and high ripple rejection. The output voltage can be adjusted between 2 V to 37 V. The pin configuration of IC 723 i ...
... • IC 723 has unregulated dc supply at input between 11.5 V to 40 V. It can withstand maximum load current of 150 mA. Internal power dissipation is about 800 mW. It has low temperature and high ripple rejection. The output voltage can be adjusted between 2 V to 37 V. The pin configuration of IC 723 i ...
Circuit component
... R2. (This resistor is usually around 240 ohms, but 220 ohms will work fine without any problems). Because of this the voltage at the output can never decrease below 1.2 volts, but as the potentiometer (P1) increases in resistance the voltage across it, due to current from the regulator plus current ...
... R2. (This resistor is usually around 240 ohms, but 220 ohms will work fine without any problems). Because of this the voltage at the output can never decrease below 1.2 volts, but as the potentiometer (P1) increases in resistance the voltage across it, due to current from the regulator plus current ...
Ohms Law - Abel Electronics
... Electronics Calculations Using Ohm’s Law Ohm's law states that the current through a conductor between two points is directly proportional to the potential difference or voltage across the two points, and inversely proportional to the resistance between them. The mathematical equation that describes ...
... Electronics Calculations Using Ohm’s Law Ohm's law states that the current through a conductor between two points is directly proportional to the potential difference or voltage across the two points, and inversely proportional to the resistance between them. The mathematical equation that describes ...
electronic devices ii
... carriers cross over to the collector resulting in a large increase in Ic. This is principle of operation of transistor as an amplifier. The behavior of npn transistor can be explained in the same way with the battery bias reversed and the majority carriers ie electrons contributing to conduction. NO ...
... carriers cross over to the collector resulting in a large increase in Ic. This is principle of operation of transistor as an amplifier. The behavior of npn transistor can be explained in the same way with the battery bias reversed and the majority carriers ie electrons contributing to conduction. NO ...
EE 4BD4 Lecture 28
... • (1) Use a DC-DC converter to give high voltage source to drive circuit Fig 3.8 slide 21 • (2) Replace load in Fig 3.8 by the input coil of a pulse transformer • If output current to electrodes is to be e.g. 40 ma, the input current must be 480 ma if transformer ratio is 1:12 • May then replace tra ...
... • (1) Use a DC-DC converter to give high voltage source to drive circuit Fig 3.8 slide 21 • (2) Replace load in Fig 3.8 by the input coil of a pulse transformer • If output current to electrodes is to be e.g. 40 ma, the input current must be 480 ma if transformer ratio is 1:12 • May then replace tra ...
Video Transcript - Rose
... R1’s resistance is the voltage across it by the current through it. This gives R1 = 2 kΩ because V/mA = kΩ. R2’s value is 3 kΩ. For v3 and v4, we know the total voltage across the two is v4 + v3. From the given equation, we know that v4 = 2*v3 because their ratio is 2:1. Set our equation equal to 6 ...
... R1’s resistance is the voltage across it by the current through it. This gives R1 = 2 kΩ because V/mA = kΩ. R2’s value is 3 kΩ. For v3 and v4, we know the total voltage across the two is v4 + v3. From the given equation, we know that v4 = 2*v3 because their ratio is 2:1. Set our equation equal to 6 ...
44407DesignProject
... 4. Report (document) file including “Discussions and Conclusions" and highligthing the results obtained, presenting them clearly and consicely using figures, charts and tables and describing and making comments on the successes/failures and suggested/implemented improvements. ”. PROBE plots can be s ...
... 4. Report (document) file including “Discussions and Conclusions" and highligthing the results obtained, presenting them clearly and consicely using figures, charts and tables and describing and making comments on the successes/failures and suggested/implemented improvements. ”. PROBE plots can be s ...
File
... • I need to track a 12VDC battery voltage on an analog pin on a microcontroller. I am trying to see what the current level the battery is. The microcontroller has a maximum rated input of 5VDC. How can I go from 48VDC to 5VDC so I don’t blow up the microcontroller? – Voltage Divider: a simple way to ...
... • I need to track a 12VDC battery voltage on an analog pin on a microcontroller. I am trying to see what the current level the battery is. The microcontroller has a maximum rated input of 5VDC. How can I go from 48VDC to 5VDC so I don’t blow up the microcontroller? – Voltage Divider: a simple way to ...
4.3 Notes - Seymour ISD
... Resistance- measure of the ability of an electrical device to oppose flow of charge through a device Measured in OHMS (Ω) ...
... Resistance- measure of the ability of an electrical device to oppose flow of charge through a device Measured in OHMS (Ω) ...
971 Quiz 01
... (a) Find the transfer curve vo v.s. v i .(10 points) (b) Find the output signal, for the above input signal. (5 points) ...
... (a) Find the transfer curve vo v.s. v i .(10 points) (b) Find the output signal, for the above input signal. (5 points) ...
Linearity
... several sources in a circuit to the voltages across and the currents through components in the circuit. ...
... several sources in a circuit to the voltages across and the currents through components in the circuit. ...
Lab06 - Weber State University
... Fig. 1 NPN Common-Emitter amplifier circuit with coupling capacitors. Design the amplifier to achieve a small-signal gain of at least AV = -200 V/V and IC = 1 mA. Use V+=15 V, RSIG = 50 Ω, RL = 10 kΩ, RB1 =80 kΩ, and RB2 = 20 kΩ. Although there will be variations from transistor to transistor, you m ...
... Fig. 1 NPN Common-Emitter amplifier circuit with coupling capacitors. Design the amplifier to achieve a small-signal gain of at least AV = -200 V/V and IC = 1 mA. Use V+=15 V, RSIG = 50 Ω, RL = 10 kΩ, RB1 =80 kΩ, and RB2 = 20 kΩ. Although there will be variations from transistor to transistor, you m ...
