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Final Exam_Summer 2013
Final Exam_Summer 2013

... with a variation of ±1 V. The diode is a 6.8 V Zener at an operationg current of 5 mA, with rZ =20 Ω, and IZK(Min) =0.2 mA. The line resistance used is 500 Ω. Calculate the following, with supporting circuit analysis. A circuit model for the diode is shown in Fig.2. (a) Draw the equivalent circuit f ...
Miniature, Precision Negative Reference
Miniature, Precision Negative Reference

Lab 4 - Ohm`s Law - Physics Introductory Labs at Stony Brook
Lab 4 - Ohm`s Law - Physics Introductory Labs at Stony Brook

... resistance of the voltmeter is “large”. Notice that all four devices above are “two-terminal” devices: one input terminal and one output terminal. The whole circuit above can be called a “series-parallel” circuit because it has three elements in series and one in parallel. The board which contains t ...
TORTURE BY ELECTRICITY
TORTURE BY ELECTRICITY

... 6. Draw a circuit that has two cells in series, four lamps in parallel, enough switches that each lamp can be turned on or off individually, a voltmeter and an ammeter that all the current goes through. Also, add a fuse in the appropriate spot for maximum safety. ...
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16spMid1C

Physics 536 - Assignment #1
Physics 536 - Assignment #1

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Transistor - Downend School

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Electric Circuits

... One last note… There are two types of current. DC (direct current) means it flows in one direction such as the current from a battery. AC (alternating current) means that it alternates the direction of flow. In the case of home electric circuits, they alternate at 60 Hz. As fun as it sounds AC is a ...
Ohm`s Law Practice Worksheet Key
Ohm`s Law Practice Worksheet Key

... Ohm’s Law Practice! Name _____KEY____________________________________ Using Ohm’s Law, calculate the missing value (E, I, or R) for each of the following circuits: 1. R = 100 Ω, I = 10 a, E = ____1000 volt_______________ 2. I = 4 a, E = 120 v, R = ____30 ohms________________ 3. E = 75 v, R = 25 Ω, I ...
1 - Marine Institute
1 - Marine Institute

생체계측 #5
생체계측 #5

... that any combination of voltage sources, current sources and resistors with two terminals is electrically equivalent to a single voltage source V(or current source) and a single series resistor R ...
Analog-to-Digital Converter and Multivibrators
Analog-to-Digital Converter and Multivibrators

6.2.6 Transistors
6.2.6 Transistors

... Transistors Parts of the Transistor The First Transistor Transistors as Amplifiers Transistors as Switches Night Light Circuit ...
6.2.6 Transistors
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Transistors - Eisenhower

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US6T4

... EMITTER TO BASE VOLTAGE : VEB(V) COLLECTOR TO BASE VOLTAGE : VCB(V) ...
Voltage Dividers
Voltage Dividers

... A series circuit acts as a voltage divider. You will learn what this term means and why voltage dividers are an important application of series circuits. After completing this section, you should be able to: Use a series circuit as a voltage divider Apply the voltage-divider formula Use the potentio ...
Current, Voltage and resistance
Current, Voltage and resistance

DN126 - The LT1166: Power Output Stage Automatic Bias System Control IC
DN126 - The LT1166: Power Output Stage Automatic Bias System Control IC

... Class AB output stage by incorporating two control loops, the current-control loop and the voltage-control loop. The current-control loop (Figure 2) operates independently of the voltage loop while keeping the product of V1 and V2 constant. The voltage loop maintains the output voltage at the input ...
BJT Differential Amplifier Laboratory
BJT Differential Amplifier Laboratory

... results with theoretical and simulated results is required for the relative validity of the models. This lab also investigates the variation of differential and common mode gains using a Monte Carlo analysis. ...
Voltage and Current Conventions
Voltage and Current Conventions

... charged body at point A with respect to its energy at point B. • If it requires Energy of amount U to move a body having charge Q from point B to point A, then we say that there is a “potential difference” between points A and B of U/Q = VAB volts. • The energy expended in moving Q from B to A can b ...
HVLED805 – one-chip solution for LED driving
HVLED805 – one-chip solution for LED driving

Transistor Amplifier – Design
Transistor Amplifier – Design

... resistor R4 is 1K, then if 2.3 volt passes through it, emitter current will be 2.3V/ 1 = 2.3 mA.Collector current also remains same. If the value of the load resistor R3 is 2K, two times higher than that of R4, then the voltage drop across it will be 2 x 2.3V = 4.6 volts.There fore the collector vol ...
Tutorial 2 - Portal UniMAP
Tutorial 2 - Portal UniMAP

... Calculate the output voltage, Vout if the input voltage given is 300 2 sin 2100tmV . What will happen when R6 opens? Draw the input and output waveforms. Determine new output voltage, Vout if the value of R6 changes to 100kΩ. Name the type of multistage amplifier shown in Figure 1. Controlled sourc ...
Electronics Glossary
Electronics Glossary

... Electric motors work through the interaction between electricity and magnetism. The motor’s rotor is an electromagnet – a tightly rolled coil of copper through which a current is passed. Surrounding the rotor are two magnets, one with the north pole facing the rotor and the other with the south pole ...
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Current mirror

A current mirror is a circuit designed to copy a current through one active device by controlling the current in another active device of a circuit, keeping the output current constant regardless of loading. The current being 'copied' can be, and sometimes is, a varying signal current. Conceptually, an ideal current mirror is simply an ideal inverting current amplifier that reverses the current direction as well or it is a current-controlled current source (CCCS). The current mirror is used to provide bias currents and active loads to circuits. It can also be used to model a more realistic current source (since ideal current sources don't exist).The circuit topology covered here is one that appears in many monolithic ICs. It is a Widlar mirror without an emitter degeneration resistor in the follower (output) transistor. This topology can only be done in an IC as the matching has to be extremely close and cannot be achieved with discretes.Another topology is the Wilson mirror. The Wilson mirror solves the Early effect voltage problem in his design.
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