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AD628 High Common-Mode Voltage Programmable Gain
AD628 High Common-Mode Voltage Programmable Gain

... ±5 V, ±10 V, and 4–20 mA input signals to a single-ended output within the input range of single-supply ADCs. The AD628 has an input common-mode and differential mode operating range of ±120 V. The high common-mode input impedance makes the device well suited for high voltage measurements across a s ...
current electricity
current electricity

Power Supply, Primary Switch Mode, Narrow Design MINI-PS
Power Supply, Primary Switch Mode, Narrow Design MINI-PS

DM74LS123 Dual Retriggerable One
DM74LS123 Dual Retriggerable One

... as close to the one-shot device pins as possible to minimize stray capacitance, to reduce noise pick-up, and to reduce I-R and Ldi/dt voltage developed along their connecting paths. If the lead length from CX to pins (6) and (7) or pins (14) and (15) is greater than 3 cm, for example, the output pul ...
EXPERIMENT #2: DC Circuits and Tools
EXPERIMENT #2: DC Circuits and Tools

Chapter 20 (Electricity) Practice Test
Chapter 20 (Electricity) Practice Test

... 5. For a constant voltage, increasing the resistance will cause the current to decrease. _________________________ ...
DS14C232 Low Power +5V Powered TIA/EIA
DS14C232 Low Power +5V Powered TIA/EIA

File u208b | allcomponents.ru
File u208b | allcomponents.ru

Chapter 17
Chapter 17

... random motion (due to collisions with the atoms) • When an electric field is set up in the conductor, it creates an electric force on the electrons and hence a current • The zigzag line represents the motion of charge carrier in a conductor ...
AN2118
AN2118

... (IL >0 mA), the VBAT voltage is automatically adjusted depending on the loop resistance and on the programmed current limitation value (ILIM). It should be noted that the device is optimized to operate on short loop applications (RLOOP ≤500 Ω) in order to obtain the correct ring-trip detection. In t ...
Problem 4.5 For the op-amp circuit shown in Fig. P4.5: (a) Use the
Problem 4.5 For the op-amp circuit shown in Fig. P4.5: (a) Use the

... Problem 4.5 For the op-amp circuit shown in Fig. P4.5: (a) Use the model given in Fig. 4-4 to develop an expression for the current gain Gi = iL /is . (b) Simplify the expression by applying the ideal op-amp model by (taking A → ∞, Ri → ∞, and Ro → 0). ...
Chapter 25 Electric Currents and Resistance
Chapter 25 Electric Currents and Resistance

CMT14N50
CMT14N50

... IDSS and VDS(on) Specified at Elevated Temperature ...
ISL6744A - Intersil
ISL6744A - Intersil

The Common Source JFET Amplifier - IDC
The Common Source JFET Amplifier - IDC

... As with the common emitter bipolar circuit, the DC load line for the common source JFET amplifier produces a straight line equation whose gradient is given as: -1/(Rd + Rs) and that it crosses the vertical Id axis at point A equal to Vdd/(Rd + Rs). The other end of the load line crosses the horizon ...
Computer Simulation HW-A 2013
Computer Simulation HW-A 2013

... The maximum positive output value is: -----------The minimum output value is: ----------------C- ...
circuits
circuits

... In time t, a charge Q is pushed through the resistor by the battery. The amount of work done by the battery is : W  VQ Power : ...
current - Images
current - Images

ADP3331 数据手册DataSheet 下载
ADP3331 数据手册DataSheet 下载

... to the uncertainty of the load capacitance and resistance. Moreover, the ESR value required to keep conventional LDOs stable changes, depending on load and temperature. These ESR limitations make designing with LDOs more difficult because of their unclear specifications and extreme variations over t ...
MAX15059 Evaluation Kit Evaluates: General Description Features
MAX15059 Evaluation Kit Evaluates: General Description Features

... www.vishay.com ...
ULN2803 - Texas Instruments
ULN2803 - Texas Instruments

... Each channel of ULN2803A consists of Darlington connected NPN transistors. This connection creates the effect of a single transistor with a very-high current gain. The very high β allows for high output current drive with a very-low input current, essentially equating to operation with low GPIO volt ...
Smart Quad Channel Low-Side Switch
Smart Quad Channel Low-Side Switch

LTC1151 - Dual ±15V Zero-Drift Operational Amplifier
LTC1151 - Dual ±15V Zero-Drift Operational Amplifier

... solder, and even copper wire are all candidates for thermal EMF generation. Junctions of copper wire from different manufacturers can generate thermal EMFs of 200nV/°C; four times the maximum drift specification of the LTC1151. Minimizing thermal EMF-induced errors is possible if judicious attention ...
MCQs from here
MCQs from here

74F413 64 x 4 First-In First-Out Buffer Memory with Parallel I/O
74F413 64 x 4 First-In First-Out Buffer Memory with Parallel I/O

... Data Output— Data is read from the O0–O3 outputs. When data is shifted to the output stage, Output Ready (OR) goes HIGH, indicating the presence of valid data. When the OR is HIGH, data may be shifted out by bringing the Shift Out (SO) HIGH. A HIGH signal at SO causes the OR to go LOW. Valid data is ...
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Current mirror

A current mirror is a circuit designed to copy a current through one active device by controlling the current in another active device of a circuit, keeping the output current constant regardless of loading. The current being 'copied' can be, and sometimes is, a varying signal current. Conceptually, an ideal current mirror is simply an ideal inverting current amplifier that reverses the current direction as well or it is a current-controlled current source (CCCS). The current mirror is used to provide bias currents and active loads to circuits. It can also be used to model a more realistic current source (since ideal current sources don't exist).The circuit topology covered here is one that appears in many monolithic ICs. It is a Widlar mirror without an emitter degeneration resistor in the follower (output) transistor. This topology can only be done in an IC as the matching has to be extremely close and cannot be achieved with discretes.Another topology is the Wilson mirror. The Wilson mirror solves the Early effect voltage problem in his design.
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