Ch 12 Collections
... • Arrays are static; once you define the number of elements it can hold, the size doesn’t change • A dynamic data structure grows and shrinks at execution time as required by its contents • A dynamic data structure is implemented using links Coming up: Object References ...
... • Arrays are static; once you define the number of elements it can hold, the size doesn’t change • A dynamic data structure grows and shrinks at execution time as required by its contents • A dynamic data structure is implemented using links Coming up: Object References ...
CUSTOMER_CODE SMUDE DIVISION_CODE SMUDE
... Relaxation: The relaxation process updates the costs of all the vertices, v, connected to a vertex u, if we could improve the best estimate of the shortest path to v by including (u,v) in the path to v. The relaxation procedure proceeds as follows: Initialize_single_source(Graph G, Node s) (1 mark) ...
... Relaxation: The relaxation process updates the costs of all the vertices, v, connected to a vertex u, if we could improve the best estimate of the shortest path to v by including (u,v) in the path to v. The relaxation procedure proceeds as follows: Initialize_single_source(Graph G, Node s) (1 mark) ...
pptx
... Check to see if MA (hashes to 0) is in the set. What should we do if we override equals()? ...
... Check to see if MA (hashes to 0) is in the set. What should we do if we override equals()? ...
Laboratory 6: Binary trees I. THEORETICAL ASPECTS
... For example, it is considered: a. p1 - is a pointer to a node from the tree to which the inserting is to be linked (p1 indicates initially to the root of the tree) b. p2 – is a pointer to the current node (the node that will be inserted) c. if p2->val < p1->val, then it tries to insert the current n ...
... For example, it is considered: a. p1 - is a pointer to a node from the tree to which the inserting is to be linked (p1 indicates initially to the root of the tree) b. p2 – is a pointer to the current node (the node that will be inserted) c. if p2->val < p1->val, then it tries to insert the current n ...
1 3,9, ,32,11,50,7
... how do we refer to the mark of any one particular student in the array or do calculations with it? We need to identify each of the ‘cells’ in the array – usually with numbers These ‘cells’ are correctly called INDEXES or INDECES So the value (mark) for the 3rd student is students[3] If that ...
... how do we refer to the mark of any one particular student in the array or do calculations with it? We need to identify each of the ‘cells’ in the array – usually with numbers These ‘cells’ are correctly called INDEXES or INDECES So the value (mark) for the 3rd student is students[3] If that ...
Backtracking
... Each non-leaf node in a tree is a parent of one or more other nodes (its children) Each node in the tree, other than the root, has exactly one parent parent Usually, however, we draw our trees downward, with the root at the top ...
... Each non-leaf node in a tree is a parent of one or more other nodes (its children) Each node in the tree, other than the root, has exactly one parent parent Usually, however, we draw our trees downward, with the root at the top ...
Exam
... keys: 7, 6, 5, 4, 3, 2, 1. Give three different possibilities for B. (b) We consider binary trees implemented in a linked structure, where T.root gives the root of the tree T . In a node v, we have v.parent pointing to the parent, v.lef t pointing to the left child, and v.right pointing to the right ...
... keys: 7, 6, 5, 4, 3, 2, 1. Give three different possibilities for B. (b) We consider binary trees implemented in a linked structure, where T.root gives the root of the tree T . In a node v, we have v.parent pointing to the parent, v.lef t pointing to the left child, and v.right pointing to the right ...
RRB-Trees: Efficient Immutable Vectors - Infoscience
... copy the item in the 3rd node and the three items in the 4th node into a new node that now meets the invariant. However, in general several or even all the nodes may need to be copied before they meet the invariant. In the worst case m2 nodes must be copied at each balancing. It is always possible t ...
... copy the item in the 3rd node and the three items in the 4th node into a new node that now meets the invariant. However, in general several or even all the nodes may need to be copied before they meet the invariant. In the worst case m2 nodes must be copied at each balancing. It is always possible t ...
