DiskTrie: An Efficient Data Structure Using Flash Memory for Mobile
... ways. First, every internal node now has the same degree, which is two. Second, no space is needed to remember the character corresponding to an outgoing edge. The obvious problem of using binary encoding is that each string will become longer and as a result search will take longer time. The soluti ...
... ways. First, every internal node now has the same degree, which is two. Second, no space is needed to remember the character corresponding to an outgoing edge. The obvious problem of using binary encoding is that each string will become longer and as a result search will take longer time. The soluti ...
Linked Lists - Computer Science@IUPUI
... Linear collection of self-referential class objects, called nodes Connected by pointer links Accessed via a pointer to the first node of the list Link pointer in the last node is set to null to mark the list’s end ...
... Linear collection of self-referential class objects, called nodes Connected by pointer links Accessed via a pointer to the first node of the list Link pointer in the last node is set to null to mark the list’s end ...
The R+-Tree: A Dynamic Index for Multi
... that has been studied in the past is the case of points. The main idea is to divide the whole space into disjoint sub-regions, usually in such a way that each sub-region contains no more than C points. C is usually 1 if the data is stored in core, or it is the capacity of a disk page, that is the nu ...
... that has been studied in the past is the case of points. The main idea is to divide the whole space into disjoint sub-regions, usually in such a way that each sub-region contains no more than C points. C is usually 1 if the data is stored in core, or it is the capacity of a disk page, that is the nu ...
List
... The linked list uses dynamic memory allocation, that is, it allocates memory for new list elements as needed. A linked list is made up of a series of objects, called the nodes of the list. List node is a distinct object (as opposed to simply a cell in an array). Every node contains the data item and ...
... The linked list uses dynamic memory allocation, that is, it allocates memory for new list elements as needed. A linked list is made up of a series of objects, called the nodes of the list. List node is a distinct object (as opposed to simply a cell in an array). Every node contains the data item and ...
CMSC 420: Data Structures
... points in the left subtree is equal to the number of points in the right subtree for each node. Generalize this argument to show that in dimension 3, an orthogonal plane (one that is orthogonal either to the x-, y-, or z-axis) intersects O(n2/3 ) leaf cells of any balanced kd-tree having n total poi ...
... points in the left subtree is equal to the number of points in the right subtree for each node. Generalize this argument to show that in dimension 3, an orthogonal plane (one that is orthogonal either to the x-, y-, or z-axis) intersects O(n2/3 ) leaf cells of any balanced kd-tree having n total poi ...
TECH REPORT
... take O(log log n) time and Store operations take O(log log n) amortized expected time. The algorithm uses linear space. Because any data structure can be implemented with an array, we can use the techniques described in this paper to make any data structure fully persistent at a cost of an extra fac ...
... take O(log log n) time and Store operations take O(log log n) amortized expected time. The algorithm uses linear space. Because any data structure can be implemented with an array, we can use the techniques described in this paper to make any data structure fully persistent at a cost of an extra fac ...
Compressed Data Structures for Range Searching
... in T (v) are contained in the range of v, so for every vertex u ∈ T (v), ru ⊆ rv . Leafs may store either points or ranges, and each point or range may be stored in several leafs. The data structure supports range queries that produce their result after evaluating the tree through a (partial) traver ...
... in T (v) are contained in the range of v, so for every vertex u ∈ T (v), ru ⊆ rv . Leafs may store either points or ranges, and each point or range may be stored in several leafs. The data structure supports range queries that produce their result after evaluating the tree through a (partial) traver ...
Deletion without Rebalancing in Non
... cases, while 22 cases have to be considered for the non-blocking chromatic tree. We prove the linearizability and progress property of a non-blocking ravl tree, and bound its height. The theoretical results of our research are summarized in the following theorem: I Theorem 1. The non-blocking ravl t ...
... cases, while 22 cases have to be considered for the non-blocking chromatic tree. We prove the linearizability and progress property of a non-blocking ravl tree, and bound its height. The theoretical results of our research are summarized in the following theorem: I Theorem 1. The non-blocking ravl t ...
12 Abstract Data Types
... At the ADT level, we use the queue and its four operations at the implementation level. We need to choose a data structure to implement it. A queue ADT can be implemented using either an array or a linked list. Figure 12.13 on page 329 shows an example of a queue ADT with five items. The figure also ...
... At the ADT level, we use the queue and its four operations at the implementation level. We need to choose a data structure to implement it. A queue ADT can be implemented using either an array or a linked list. Figure 12.13 on page 329 shows an example of a queue ADT with five items. The figure also ...
On Hardness of Several String Indexing Problems
... query processing, where p1 = |P1 | and p2 = |P2 | and k is the output size1 . Later Cohen and Porat [7] presented a space efficient structure of O(n log n)√ space, but with a higher query time of O(p1 + p2 + nk log n log2 n). The space and the query √ time of was improved by Hon et al. [11] to O(n) ...
... query processing, where p1 = |P1 | and p2 = |P2 | and k is the output size1 . Later Cohen and Porat [7] presented a space efficient structure of O(n log n)√ space, but with a higher query time of O(p1 + p2 + nk log n log2 n). The space and the query √ time of was improved by Hon et al. [11] to O(n) ...
PPT - UNSW
... Begin by testing for a set of base cases (there should be at least one). Every possible chain of recursive calls must eventually reach a base case, and the handling of each base case should not use recursion. ...
... Begin by testing for a set of base cases (there should be at least one). Every possible chain of recursive calls must eventually reach a base case, and the handling of each base case should not use recursion. ...
BST_Hash
... – Value of key field given to hash function – Location in a hash table is calculated ...
... – Value of key field given to hash function – Location in a hash table is calculated ...
question-paper-Data-Structures-with-C-06cs35-10cs35
... (6marks) b. Write an algorithm for converting an infix expression to postfix. Trace the algorithm indicating the contents of stack for the expression ((A-(B+C))*(D$(E+F) (10 marks) c. Convert infix to postfix and prefix ((a-(b+c))*d$(e+f) (4 marks) ...
... (6marks) b. Write an algorithm for converting an infix expression to postfix. Trace the algorithm indicating the contents of stack for the expression ((A-(B+C))*(D$(E+F) (10 marks) c. Convert infix to postfix and prefix ((a-(b+c))*d$(e+f) (4 marks) ...
Lecture 5 (linked lists and vectors)
... We compare the incremental strategy and the doubling strategy by analyzing the total time T(n) needed to perform a series of n push operations We assume that we start with an empty stack represented by an array of size 1 We call amortized time of a push operation the average time taken by a push ove ...
... We compare the incremental strategy and the doubling strategy by analyzing the total time T(n) needed to perform a series of n push operations We assume that we start with an empty stack represented by an array of size 1 We call amortized time of a push operation the average time taken by a push ove ...
5 Binary Trees
... controlling which members of the collection will be visited. For example, some tree “traversals” might in fact visit only some tree nodes, while avoiding processing of others. Exercise 5.20 must solve exactly this problem in the context of a binary search tree. It must visit only those children of a ...
... controlling which members of the collection will be visited. For example, some tree “traversals” might in fact visit only some tree nodes, while avoiding processing of others. Exercise 5.20 must solve exactly this problem in the context of a binary search tree. It must visit only those children of a ...
Chapter 7 Data Structures for Strings
... a constant time operation, then running time is O(|s|). If we consider this deletion to take O(N) time, then the running time is O(|s| + N). An important di erence between Patricia trees and tries is that Patricia trees contain no nodes with only one child. Every node is either a leaf or has at leas ...
... a constant time operation, then running time is O(|s|). If we consider this deletion to take O(N) time, then the running time is O(|s| + N). An important di erence between Patricia trees and tries is that Patricia trees contain no nodes with only one child. Every node is either a leaf or has at leas ...