(Core 1) Revision Sheet
... So the remainder is +16. Therefore x3 + 2x2 + 3x − 6 = (x − 2)(x2 + 4x + 11) + 16. • x − a is a factor ⇔ f (a) = 0. • Remainder theorem: When f (x) is divided by x − a the remainder is f (a). For example if told that when f (x) = x3 + 2x2 − 3x − 7 is divided by x − 2 the remainder is 3, we know f (2 ...
... So the remainder is +16. Therefore x3 + 2x2 + 3x − 6 = (x − 2)(x2 + 4x + 11) + 16. • x − a is a factor ⇔ f (a) = 0. • Remainder theorem: When f (x) is divided by x − a the remainder is f (a). For example if told that when f (x) = x3 + 2x2 − 3x − 7 is divided by x − 2 the remainder is 3, we know f (2 ...
Chapter 4
... Our last consideration is | x | < #, when that number is greater than zero. Again let's consider the positive numbers and the negative numbers that will make it a true statement. Positive numbers between zero and the number at hand will make a true statement. Negative numbers between zero and the op ...
... Our last consideration is | x | < #, when that number is greater than zero. Again let's consider the positive numbers and the negative numbers that will make it a true statement. Positive numbers between zero and the number at hand will make a true statement. Negative numbers between zero and the op ...
