Table of Contents Pages Unit 1- Matter and Change 1
... ___________________ that traps the solid particles while the liquid passes through in a process called filtering. Some simple methods also exist for separating homogeneous mixtures. A solid dissolved in a liquid solution can be separated by letting it dry out in the process of ___________________. M ...
... ___________________ that traps the solid particles while the liquid passes through in a process called filtering. Some simple methods also exist for separating homogeneous mixtures. A solid dissolved in a liquid solution can be separated by letting it dry out in the process of ___________________. M ...
Chemistry_Stoichiome..
... 80. 100 mL of 10 % NaOH (w/V) is added to 100 mL of 10 % HCl (w/V). The resultant solution becomes: a) alkaline b) strongly alkaline c) acidic d) neutral 81. Calculate the molality of 1 L solution of 80 % H2SO4 (w/V), given that the density of the solution is 1.80 g mL−1 . a) 9.18 b) 8.6 c) 1.02 d) ...
... 80. 100 mL of 10 % NaOH (w/V) is added to 100 mL of 10 % HCl (w/V). The resultant solution becomes: a) alkaline b) strongly alkaline c) acidic d) neutral 81. Calculate the molality of 1 L solution of 80 % H2SO4 (w/V), given that the density of the solution is 1.80 g mL−1 . a) 9.18 b) 8.6 c) 1.02 d) ...
Chapter 2 The Components of Matter
... 1. Some compounds have been known and used for so long that their trivial (or common names) have become accepted by the IUPAC as official: ...
... 1. Some compounds have been known and used for so long that their trivial (or common names) have become accepted by the IUPAC as official: ...
Principles of Chemistry 1 and 2 Notes
... a. Draw Lewis structure of the compound. a. Count # of bonding pairs (central atom / terminal atoms). a. Count # of lone pairs (nonbonding); (around the central atoms ONLY) a. Look at the tables 10.1 and 10.2 (pages 369 and 375, respectively) in the textbook and figure out the electron bonding pair ...
... a. Draw Lewis structure of the compound. a. Count # of bonding pairs (central atom / terminal atoms). a. Count # of lone pairs (nonbonding); (around the central atoms ONLY) a. Look at the tables 10.1 and 10.2 (pages 369 and 375, respectively) in the textbook and figure out the electron bonding pair ...
Assigning Oxidation Numbers
... 3. Hydrogen’s oxidation number is +1, except for when bonded to metals as the hydride ion forming binary compounds. In LiH, NaH, and CaH2 , the oxidation number is -1. 4. Fluorine has an oxidation number of -1 in all of its compounds. 5. Halogens (Cl, Br, I) have negative oxidation numbers when they ...
... 3. Hydrogen’s oxidation number is +1, except for when bonded to metals as the hydride ion forming binary compounds. In LiH, NaH, and CaH2 , the oxidation number is -1. 4. Fluorine has an oxidation number of -1 in all of its compounds. 5. Halogens (Cl, Br, I) have negative oxidation numbers when they ...
Student Review Packet
... At endpoint: acid moles = base moles or [H+] = [OH-] Strong acid – strong base ...
... At endpoint: acid moles = base moles or [H+] = [OH-] Strong acid – strong base ...
advanced placement chemistry workbook and note set
... Atoms that contain equal numbers of electrons and protons are electrically neutral. However, atoms can easily lose or gain electrons and form ions, which are electrically-charged chemical species. The identity of the element does not change – only the electrical charge of the species changes. Recall ...
... Atoms that contain equal numbers of electrons and protons are electrically neutral. However, atoms can easily lose or gain electrons and form ions, which are electrically-charged chemical species. The identity of the element does not change – only the electrical charge of the species changes. Recall ...
5 SURFACE CHEMISTRY CATEGORY
... freezing point by 7.5°C? The freezing point depression constant, Kf , for water is 1.86 K kg mol–1. Assume van’t Hoff factor for NaCl is 1.87. 8. 18 g of glucose, C6H12O6 (Molar Mass = 180 g mol–1) is dissolved in 1 kg of water in a sauce pan. At what temperature will this solution boil? 9.Determine ...
... freezing point by 7.5°C? The freezing point depression constant, Kf , for water is 1.86 K kg mol–1. Assume van’t Hoff factor for NaCl is 1.87. 8. 18 g of glucose, C6H12O6 (Molar Mass = 180 g mol–1) is dissolved in 1 kg of water in a sauce pan. At what temperature will this solution boil? 9.Determine ...
Table of Contents
... ___________________ that traps the solid particles while the liquid passes through in a process called filtering. Some simple methods also exist for separating homogeneous mixtures. A solid dissolved in a liquid solution can be separated by letting it dry out in the process of ___________________. M ...
... ___________________ that traps the solid particles while the liquid passes through in a process called filtering. Some simple methods also exist for separating homogeneous mixtures. A solid dissolved in a liquid solution can be separated by letting it dry out in the process of ___________________. M ...
Mole-Volume Conversion Assignment
... Ex. For a reaction between vinegar & baking soda (acetic acid and sodium bicarbonate): Note: A 5.0% solution of vinegar means there are 5.0 g of acetic acid for every 100mL of solution. So if we use 50mL of vinegar that means we are using 2.5g of acetic acid. What volume of carbon dioxide will be pr ...
... Ex. For a reaction between vinegar & baking soda (acetic acid and sodium bicarbonate): Note: A 5.0% solution of vinegar means there are 5.0 g of acetic acid for every 100mL of solution. So if we use 50mL of vinegar that means we are using 2.5g of acetic acid. What volume of carbon dioxide will be pr ...
Chapter 4: Types of Chemical Reactions and Solution Stoichiometry
... Example: If a solution containing potassium chloride is added to a solution containing ammonium nitrate, will a precipitate form? KCl(aq) + NH4NO3(aq) → K+(aq) + Cl-(aq) + NH4+(aq) + NO3-(aq) Possible reaction products are KCl and NH4NO3, NH4Cl and KNO3. All are soluble, so there is no precipitate. ...
... Example: If a solution containing potassium chloride is added to a solution containing ammonium nitrate, will a precipitate form? KCl(aq) + NH4NO3(aq) → K+(aq) + Cl-(aq) + NH4+(aq) + NO3-(aq) Possible reaction products are KCl and NH4NO3, NH4Cl and KNO3. All are soluble, so there is no precipitate. ...
1. Atomic Structure and Periodic Table THE MASS SPECTROMETER
... A. As one goes down a group, the outer electrons are found in shells further from the nucleus and are more shielded so the attraction of the nucleus becomes smaller Q. Why is there a general increase in first ionisation energy across a period? A. As one goes across a period , the number of protons i ...
... A. As one goes down a group, the outer electrons are found in shells further from the nucleus and are more shielded so the attraction of the nucleus becomes smaller Q. Why is there a general increase in first ionisation energy across a period? A. As one goes across a period , the number of protons i ...
Topical KCSE Mock-Chemistry Answers(15 Schools)
... together. These require a lot of energy to break, hence it has high melting point. Carbon (IV) Oxide has simple molecular structure with weakVan Der Waals forces holding the molecules together which require little energy to break, hence sublimes at low temperature and is a gas at room temperature an ...
... together. These require a lot of energy to break, hence it has high melting point. Carbon (IV) Oxide has simple molecular structure with weakVan Der Waals forces holding the molecules together which require little energy to break, hence sublimes at low temperature and is a gas at room temperature an ...
Part II - American Chemical Society
... c. The calculated Ksp will be too large because the student is relying on seeing the formation of a precipitate at the moment that Q exceeds Ksp. The student will miss the exact moment that happens, so the calculated value of Ksp will be too large. Other possible issues: Protolysis will decrease the ...
... c. The calculated Ksp will be too large because the student is relying on seeing the formation of a precipitate at the moment that Q exceeds Ksp. The student will miss the exact moment that happens, so the calculated value of Ksp will be too large. Other possible issues: Protolysis will decrease the ...
12_chemistry_impq_CH13_amines_02
... This resonance accounts for the stability of the diazonium ion. Hence, diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines: Gabriel phthalimide synthesis results in the formation of 1° ami ...
... This resonance accounts for the stability of the diazonium ion. Hence, diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines: Gabriel phthalimide synthesis results in the formation of 1° ami ...
Aromatic Chemistry - heckgrammar.co.uk
... distribution of energies amongst particles at different temperatures give rise to the MaxwellBoltzmann distribution curves based on the Arrhenius expression ...
... distribution of energies amongst particles at different temperatures give rise to the MaxwellBoltzmann distribution curves based on the Arrhenius expression ...
Carefully detach the last page. It is the Data Sheet.
... Ag+(aq) + e− U Ag(s) O2(g) + 2H2O(l) + 4e– U 4 OH–(aq) Cu2+(aq) + 2e− U Cu(s) 2H+(aq) + 2e− U H2(g) Sn2+(aq) + 2e− U Sn(s) Ni2+(aq) + 2e− U Ni(s) Fe2+(aq) + 2e− U Fe(s) Cr3+(aq) + 3e− U Cr(s) Zn2+(aq) + 2e− U Zn(s) 2H2O (l) + 2e− U H2(g) + 2OH−(aq) Al3+(aq) + 3e− U Al(s) ...
... Ag+(aq) + e− U Ag(s) O2(g) + 2H2O(l) + 4e– U 4 OH–(aq) Cu2+(aq) + 2e− U Cu(s) 2H+(aq) + 2e− U H2(g) Sn2+(aq) + 2e− U Sn(s) Ni2+(aq) + 2e− U Ni(s) Fe2+(aq) + 2e− U Fe(s) Cr3+(aq) + 3e− U Cr(s) Zn2+(aq) + 2e− U Zn(s) 2H2O (l) + 2e− U H2(g) + 2OH−(aq) Al3+(aq) + 3e− U Al(s) ...
5 organic chemistry: functional groups
... enough energy to dissociate a Cl2 molecule to a pair of Cl atoms. The reaction occurs at high temperatures because Cl2 molecules can dissociate to form Cl atoms by absorbing thermal energy. • The reaction continues after the light has been turned off because light is needed only to generate the Cl ...
... enough energy to dissociate a Cl2 molecule to a pair of Cl atoms. The reaction occurs at high temperatures because Cl2 molecules can dissociate to form Cl atoms by absorbing thermal energy. • The reaction continues after the light has been turned off because light is needed only to generate the Cl ...
Acids and Bases
... important than its electronegativity in determining how well it bears its negative charge. For example, as we proceed down a column in the periodic table, as the elements get larger, their stability increases, so the strength of their conjugate acid also increases. Thus, HI is the strongest acid of ...
... important than its electronegativity in determining how well it bears its negative charge. For example, as we proceed down a column in the periodic table, as the elements get larger, their stability increases, so the strength of their conjugate acid also increases. Thus, HI is the strongest acid of ...
Type - Enrico Fermi High
... What is the force that accounts for HF being a liquid, while H 2 and F2 are gases? ...
... What is the force that accounts for HF being a liquid, while H 2 and F2 are gases? ...
KHARKOV STATE MEDICAL UNIVERSITY
... living systems in relatively small quantities), are Ca, Cl, Mg, K, Na. Microelements are essential elements necessary only in very small quantities to maintain the chemical reactions on which life depends. These are: Cu, Fe, Mo, Zn, Co, F, I, B, Mn, Se, As, Si, Cr, Ni, Sn, V. The main organogen is c ...
... living systems in relatively small quantities), are Ca, Cl, Mg, K, Na. Microelements are essential elements necessary only in very small quantities to maintain the chemical reactions on which life depends. These are: Cu, Fe, Mo, Zn, Co, F, I, B, Mn, Se, As, Si, Cr, Ni, Sn, V. The main organogen is c ...
AP Chemistry Notes and Worksheets 2014
... o Compounds are formed when atoms of different elements combine in a constant composition. o Atoms are not changed in a chemical reaction, only rearranged. Dalton determined the first table of atomic weights. Many were wrong because of incorrect formulas. o Ex. OH for water with O having a mass of ...
... o Compounds are formed when atoms of different elements combine in a constant composition. o Atoms are not changed in a chemical reaction, only rearranged. Dalton determined the first table of atomic weights. Many were wrong because of incorrect formulas. o Ex. OH for water with O having a mass of ...
Hydroxide
Hydroxide is a diatomic anion with chemical formula OH−. It consists of an oxygen and hydrogen atom held together by a covalent bond, and carries a negative electric charge. It is an important but usually minor constituent of water. It functions as a base, a ligand, a nucleophile and a catalyst. The hydroxide ion forms salts, some of which dissociate in aqueous solution, liberating solvated hydroxide ions. Sodium hydroxide is a multi-million-ton per annum commodity chemical. A hydroxide attached to a strongly electropositive center may itself ionize, liberating a hydrogen cation (H+), making the parent compound an acid.The corresponding electrically neutral compound •HO is the hydroxyl radical. The corresponding covalently-bound group -OH of atoms is the hydroxyl group.Hydroxide ion and hydroxyl group are nucleophiles and can act as a catalyst in organic chemistry.Many inorganic substances which bear the word ""hydroxide"" in their names are not ionic compounds of the hydroxide ion, but covalent compounds which contain hydroxyl groups.