Legendre Polynomials
... one containing only even powers. But while these are linearly independent, they are not the two linearly independent solutions solutions expected from a 2nd order ode. In fact, we have demonstrated that a second solution must diverge at the singular points. Suppose we choose to allow divergence by n ...
... one containing only even powers. But while these are linearly independent, they are not the two linearly independent solutions solutions expected from a 2nd order ode. In fact, we have demonstrated that a second solution must diverge at the singular points. Suppose we choose to allow divergence by n ...
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