
solutions for the practice test
... (6) (a) Multiply the following polynomials. (You may use any shortcuts you remember.) (x3 − 3x + 1)(2x2 − 7) Remember that our shortcut for multiplying polynomials is to multiply every combination of a term from the first polynomial and a term from the second polynomial, then add it all up. We get ( ...
... (6) (a) Multiply the following polynomials. (You may use any shortcuts you remember.) (x3 − 3x + 1)(2x2 − 7) Remember that our shortcut for multiplying polynomials is to multiply every combination of a term from the first polynomial and a term from the second polynomial, then add it all up. We get ( ...
Galois` Theorem on Finite Fields
... a 0 for addition, a 1 for multiplication, you can divide consistently, etc. When the number of elements of the field is n, a non-negative integer, it is called finite. If n is a prime then addition and multiplication modulo p defines a field, denoted GF(p). Thus in GF(3), 2 × 2 = 2 + 2 = 1 since 4 ( ...
... a 0 for addition, a 1 for multiplication, you can divide consistently, etc. When the number of elements of the field is n, a non-negative integer, it is called finite. If n is a prime then addition and multiplication modulo p defines a field, denoted GF(p). Thus in GF(3), 2 × 2 = 2 + 2 = 1 since 4 ( ...
Solution
... quadratic equations using factoring quadratic equations graphically using the x-intercept method and the intersection method Solve quadratic equations by combining graphical and factoring methods Solve quadratic equations using the square root method Solve quadratic equations by completing the ...
... quadratic equations using factoring quadratic equations graphically using the x-intercept method and the intersection method Solve quadratic equations by combining graphical and factoring methods Solve quadratic equations using the square root method Solve quadratic equations by completing the ...
s08a.pdf
... Consider a situation involving a single independent variable x and an associated dependent variable y. Let m pairs of values (points) (xi , yi ), i = 1, 2, ..., m be given. Consider the approximation problem consisting of finding the equation of a straight line which best represents the collection o ...
... Consider a situation involving a single independent variable x and an associated dependent variable y. Let m pairs of values (points) (xi , yi ), i = 1, 2, ..., m be given. Consider the approximation problem consisting of finding the equation of a straight line which best represents the collection o ...
Common Algebra Mistakes
... If the negative is not in parentheses but instead hanging out front of the base, then just bring it down as part of your final answer and proceed to evaluate the exponential expression. The base is negative only if the negative is inside the parentheses and the exponent is outside the parenthese ...
... If the negative is not in parentheses but instead hanging out front of the base, then just bring it down as part of your final answer and proceed to evaluate the exponential expression. The base is negative only if the negative is inside the parentheses and the exponent is outside the parenthese ...
If , find all values of x such that f(x) = 256
... If f ( x) 4 , find all values of x such that f(x) = 256. Solution: Since f(x)=256, we can plug in 256 for f(x) in the first equation to get. ...
... If f ( x) 4 , find all values of x such that f(x) = 256. Solution: Since f(x)=256, we can plug in 256 for f(x) in the first equation to get. ...
James Lynch MAT 501 Class Notes: 10/29/09 Some Exam Problems
... (ii) d=-2 is a greatest common divisor of 4 and 6 in the integers because d clearly divides both 4 and 6, and if we have some c that also divides 4 and 6 then c can only be equal to one of -2,-1,1,2, by virtue that it must divide both 4 and 6. All of these possible values of c divide -2. Therefore, ...
... (ii) d=-2 is a greatest common divisor of 4 and 6 in the integers because d clearly divides both 4 and 6, and if we have some c that also divides 4 and 6 then c can only be equal to one of -2,-1,1,2, by virtue that it must divide both 4 and 6. All of these possible values of c divide -2. Therefore, ...
PDF
... Because a Pratt certificate requires the factorization of n − 1, it is generally only used for small numbers, with “small” being roughly defined as being less than about a billion. We’ll use a much smaller number for our example, one for which it would actually be faster to just perform trial divisi ...
... Because a Pratt certificate requires the factorization of n − 1, it is generally only used for small numbers, with “small” being roughly defined as being less than about a billion. We’ll use a much smaller number for our example, one for which it would actually be faster to just perform trial divisi ...
Chapter_1[1] Chris M
... Domain- is the set of values for which the function is defined. You can think of the domain of a function as the set of input values. ...
... Domain- is the set of values for which the function is defined. You can think of the domain of a function as the set of input values. ...
Factorization
In mathematics, factorization (also factorisation in some forms of British English) or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original. For example, the number 15 factors into primes as 3 × 5, and the polynomial x2 − 4 factors as (x − 2)(x + 2). In all cases, a product of simpler objects is obtained.The aim of factoring is usually to reduce something to “basic building blocks”, such as numbers to prime numbers, or polynomials to irreducible polynomials. Factoring integers is covered by the fundamental theorem of arithmetic and factoring polynomials by the fundamental theorem of algebra. Viète's formulas relate the coefficients of a polynomial to its roots.The opposite of polynomial factorization is expansion, the multiplying together of polynomial factors to an “expanded” polynomial, written as just a sum of terms.Integer factorization for large integers appears to be a difficult problem. There is no known method to carry it out quickly. Its complexity is the basis of the assumed security of some public key cryptography algorithms, such as RSA.A matrix can also be factorized into a product of matrices of special types, for an application in which that form is convenient. One major example of this uses an orthogonal or unitary matrix, and a triangular matrix. There are different types: QR decomposition, LQ, QL, RQ, RZ.Another example is the factorization of a function as the composition of other functions having certain properties; for example, every function can be viewed as the composition of a surjective function with an injective function. This situation is generalized by factorization systems.