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Isometries of figures in Euclidean spaces
Isometries of figures in Euclidean spaces

3.2 (III-14) Factor Groups
3.2 (III-14) Factor Groups

Document
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... 3. Add elements of one row to corresponding elements of another row We are going to work with our augmented matrix to get it in a form that will tell us the solutions to the system of equations. The three things above are the only things we can do to the matrix but we can do them together (i.e. we c ...
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... In Section 2 we define the square root function of a matrix. The feature which complicates the existence theory for matrix square roots is that in general not all the square roots of a matrix A are functions of A. In Section 3 we classify the square roots of a nonsingular matrix A in a manner which ...
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... A, we construct an arrangement by simplifying, that is, removing all zero columns, constructing a multiset of hyperplanes corresponding to the kernels of the linear forms defined by the columns, giving a multiarrangement, and disregarding the multiplicities to obtain an arrangement. If A is essentia ...
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... x ∈ X , the set of all images g(x), as g varies through G, is called the orbit of x. Distinct orbits form equivalent classes and they partition the set X . The action is transitive if for every pair of elements x, y ∈ X , there is a group element g ∈ G such that g(x) = y. In other words, the action ...
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... Let V be a finite-dimensional vector space. Let T : V → V be linear. 1. If rank(T ) = rank(T 2 ), prove that R(T ) ∩ N (T ) = {0}. Deduce that V = R(T ) ⊕ N (T ). 2. Prove that V = R(T k ) + N (T k ) for some positive integer k. Proof: For 1), we need this first: Lemma: ker T = ker T 2 . Proof: Choo ...
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... If {u1 , . . . , um } and {v1 , . . . , vn } both satisfy these conditions then m = n. Definition 2.6 A finite set {v1 , . . . , vn } ⊆ V of a vector space is called a basis if it satisfies one, and hence all, of the conditions in Theorem 2.1. The unique number of elements in a basis is called the d ...
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... (i.e., with a remainder of small norm) can be performed in a fast and stable way via evaluation/interpolation techniques (see [3]), which exploit the properties of the discrete Fourier transform. Alternatively, Theorem 2.3 can be employed to determine the coefficients of a gcd; the cofactors, if req ...
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... I-st case. λ 6= 0. The ordered set {e01 , e02 , e03 } is a basis because vectors are linear independent (see the exercise 3), This basis is not orthogonal, because the length vector is not equal to 1 ((e03 , e03 ) = |e03 |2 = 2+λ2 ). This matrix is not orthogonal, because the new basis is not orthon ...
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LECTURE NOTES 1. Basic definitions Let K be a field. Definition 1.1
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Jordan normal form



In linear algebra, a Jordan normal form (often called Jordan canonical form)of a linear operator on a finite-dimensional vector space is an upper triangular matrix of a particular form called a Jordan matrix, representing the operator with respect to some basis. Such matrix has each non-zero off-diagonal entry equal to 1, immediately above the main diagonal (on the superdiagonal), and with identical diagonal entries to the left and below them. If the vector space is over a field K, then a basis with respect to which the matrix has the required form exists if and only if all eigenvalues of the matrix lie in K, or equivalently if the characteristic polynomial of the operator splits into linear factors over K. This condition is always satisfied if K is the field of complex numbers. The diagonal entries of the normal form are the eigenvalues of the operator, with the number of times each one occurs being given by its algebraic multiplicity.If the operator is originally given by a square matrix M, then its Jordan normal form is also called the Jordan normal form of M. Any square matrix has a Jordan normal form if the field of coefficients is extended to one containing all the eigenvalues of the matrix. In spite of its name, the normal form for a given M is not entirely unique, as it is a block diagonal matrix formed of Jordan blocks, the order of which is not fixed; it is conventional to group blocks for the same eigenvalue together, but no ordering is imposed among the eigenvalues, nor among the blocks for a given eigenvalue, although the latter could for instance be ordered by weakly decreasing size.The Jordan–Chevalley decomposition is particularly simple with respect to a basis for which the operator takes its Jordan normal form. The diagonal form for diagonalizable matrices, for instance normal matrices, is a special case of the Jordan normal form.The Jordan normal form is named after Camille Jordan.
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